Gap Strategy - Texas Pick 3 combined drawings.

Form 6 - Hot Alpha Number followers.

This is the last form - I promise!

The data source for this Form is the Hot Alpha # stream on Form 2. This

stream consists of numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10.

These numbers appear in random order.

All players using this strategy should know how the HA# numbers are generated, as well as

The inventories on Form 3.

Form 6 provides a systematic means for processing the numbers in a way that

allows analysis and use in the number generation array.

Form 6A is for HA numbers 1A ,2A and 3A

Form 6B is for HA numbers 4B, 5B and 6B.

Form 6C is for HA numbers 7C, 8C, 9C and 10R.

Using the same row and column reference method I've used, here are the instructions

for Form 6A. The same procedures are used for Forms 6B and 7C.

Using a standard sheet of graph paper (8.5x11) use rows 1 and 2 to identify what the form contains,

i.e., Texas Pick 3C, 070109, Hot Alpha Numbers 1,2, and 3.

Beginning with Row 3 column 2 to 9, enter '’#’” eight times. These are the header columns where the

numbers 1, 2 and 3 will be logged in the order in which they occur on Form 2.

I have 42 entries in Column 2 and 28 in Column 3 (as of 0815 night drawing).

Since we are all on the same page, ie. we started on 070109, the number sequence, from Form 2, Round 1,

Begins with 1121213332212, etc

Beginning with Row 3, Column 10 enter nine column headings - '’11', skip a column, '12' skip a column, '13', skip a

column '21', skip a column, '22', skip a column, '23', skip a column, '31', skip a column '32',

skip a column, '33'

Here's how the data is logged:

First 3 numbers in Column 2 are '112', therefore, a '2' is put in the first open cell under

the header column 11.

The second, third and fourth numbers in Column 2 are '121', therefore a '1' is placed in the first

open cell in the column header 12.

The third, fourth and fifth numbers in Column 2 are 212; therefore a 2 is placed in the first

open cell under column header 21.

The fourth, fifth and sixth numbers in Column 2 are 121, therefore a 1 is placed in the

cell below the 1 already in the column.

The fifth, sixth and seventh numbers in Column 2 are 213, therefore a 3 placed in the cell below

the 2 already logged in the column.

This process continues until all of the numbers are logged.

Your log should be as indicated below:

Row 3 11 12 13 21 22 23 31 32 33

Row 4 2 1 3 2 1 3 3 2 3

Row 5 3 1 2 3 2 3 2 1 2

Row6 1 1 1 2 2 3 1 2

Row7 1 1 2 2 2 2 3

Row8 3 3 1 1 1 2 2

Row9 1 2 3 1 2 2

Row10 1 3 2 2 3 2

Row 11 1 2 2 3

Row12 2 3 1

Row 13 2 3

Row14 2

Row 15 3

Additional numbers are added as they occur.

As can be seen these are 'consecutive triples',. I don't know how else to say it.

But, we learn by doing.

I'll explain how this information is used in number generation later.

An additional feature is tracking of the ‘pairs’.

This is done by outlining 9 blocks having 4 cells each at the bottom of the page.

Using a pen establish 3 rows having 3 blocks.

Enter 1 for the first row, 2 for the second and 3 for the third.

Across the top, enter 1 for the first column, 2 for the third and 3 for the 4^{th}.

Refer to columns 2 and 3 and tabulate the pairs. Ie., 11, 12, 21, 12, 21, 13, etc

When you have completed the list, the 9 blocks should be as follows:

1 2 3

1 5 9 7

2 12 10 3

3 2 8 7

What this shows is that ‘11’ has come up 5 times, 12 has come up 9 times, 13 has come up 7 times.

The pair 21 has come up 12 times, 22 has come up 10 times, etc.

Use a light pencil when entering the totals because they will be erased and updated frequently.

Referring to column 3, you will note that the number stream ends with ‘232’

The question then becomes, ‘What is the next number?”

Referring to the data logged, the last number in the ‘32’ column is 3, which was a repeat.

Will it repeat a third time?

Referring to the pair chart, the 2 is frequently followed by a ‘1’, but ‘2’ also has a high total.

If the number sequence selector sub-array calls for 1 or more of the 3 HA numbers, you make a choice.

The critical part is that your choice will decide exactly which of the three lottery numbers under consideration will be put into play.

The same procedures outlined above is followed by HA numbers 4B, 5B, and 6B. The headers are 44, 45, 46, 54, 55, 56, 64, 65, 66

Again, the same procedures are followed for HA numbers 7C, 8C, 9C and 10R. The difference being that you need

12 blocks to log the pairs.

When you establish the data columns, you will notice that some of the ‘triples’ repeat.

On Form 6B, the triple 544 has come up 4 times (544-5, 544-6, 544-5, 544-6)

The triple ‘546’, the last triple in the column, has come up 4 times ( 546-4, 546-5, 546-4, 546-?)

Will the fourth digit be a 4, a 5 or a 6?

It’s really difficult to demonstrate all of the possibilities presented by Form 6.

I can only stress that your choices here are the ones that really count.

If you have any difficulty establishing your Form 6, let me know.

Thanks for your interest.