|Posted: July 4, 2010, 8:55 pm - IP Logged|
and happy 4th of july to all.
Question : Does anyone know how to calculate how many combinations a number by positions will generate ?
for exemple :
Number 1 as 1st position generate 341 055 combinations.
Number 15 as 1st position generate 101 270 combinations.
Number 26 as 3rd position generate 130 500 combinations.
See below part of the chart
Thank you .... Serge.
First you have to know the size of the combinations and the size of the number pool because the larger the combination and number pool, the more combinations that will be generated.
The potion of the chart you're showing looks like it's for combinations of 5 for a pool of 56 numbers.
If 1 is in the first position then there are 4/55 combinations left = 341055
If 2 is in the first position then there are 4/54 combinations left = 316251 and etc.
Since 2 is the lowest number that can be in the second position of any combination, you start with 2.
If 2 is in the second position then there are 3/54 combinations left = 24504 and etc.
You do the same thing for all the remaining positions and you will have made a chart.
If you were doing this for a combination of 6 for a number pool of 49 then:
If 1 is in the first position then there are 5/48 combinations left = 1712304 and etc.
If you don't have a program to calculate the number of combinations of a certain size for a number pool of a certain size, you can use the formula at the link in JADELottery post or just download one from the Internet.
* you don't need to buy more tickets, just buy a winning ticket *