|Posted: October 20, 2010, 7:30 pm - IP Logged|
I play Colorado's 6/42 Lotto. The there are 216 possible sums of the numbers ranging from 21 (1-2-3-4-5-6) to 237 (37-38-39-40-41-42). There is only 1 possible combination of the numbers to get a sum of 21 and the same with 237. Is there a formula out there to calculate how many possibilities of the 5.3M there are per sum for the rest of the sums between them? Something I could apply to all lottery games? Thanks.