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# Math Odds Question

Topic closed. 10 replies. Last post 6 years ago by MADDOG10.

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Sunny California
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 Posted: December 15, 2010, 4:38 pm - IP Logged

Wheeling 16 numbers in a Pick 5 game gives me 4,368 combinations. Now if I split those 4,368 combos into 10 line sets that would give me about 437 sets of 10 lines.

Say that one of the combos was a sure fire jackpot win. If 437 people were playing their 10 lines of numbers one of them would have hit the big one.

My question is...what would their odds have been?

1/437 because of the way it was split up?

Or 1/4,368 because of the odds in the first place?

mid-Ohio
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 Posted: December 15, 2010, 5:03 pm - IP Logged

Their odds of winning would only be 10:4368 if your 16 numbers included all five winning numbers other wise if it's a 5/39 game their odds of winning would be 10:575757.

* you don't need to buy more tickets, just buy a winning ticket *

Sunny California
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 Posted: December 15, 2010, 5:08 pm - IP Logged

Thanks RJOH. Yes,you're right,it would be a 5/39 game. So how come it is 10/4368  instead of 1/4368 ?  Only 1 line of numbers will win. Wouldn't it be 10/437? LoL. I'm confusing myself. I appreciate your answer.

Kentucky
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 Posted: December 16, 2010, 10:28 am - IP Logged

Wheeling 16 numbers in a Pick 5 game gives me 4,368 combinations. Now if I split those 4,368 combos into 10 line sets that would give me about 437 sets of 10 lines.

Say that one of the combos was a sure fire jackpot win. If 437 people were playing their 10 lines of numbers one of them would have hit the big one.

My question is...what would their odds have been?

1/437 because of the way it was split up?

Or 1/4,368 because of the odds in the first place?

Even though we don't know which of the 4,368 chances will win, we know 1 out of 437 people are holding the winning chance so the odds of anyone of the 437 players winning are 436 to 1.

Sunny California
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 Posted: December 16, 2010, 10:38 am - IP Logged

Thank you,Stack. I was thinking more along the lines of this myself. But how is it 1/436? LoL. I'll get this right yet!

mid-Ohio
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 Posted: December 16, 2010, 5:44 pm - IP Logged

Thanks RJOH. Yes,you're right,it would be a 5/39 game. So how come it is 10/4368  instead of 1/4368 ?  Only 1 line of numbers will win. Wouldn't it be 10/437? LoL. I'm confusing myself. I appreciate your answer.

If you're playing 10 lines and there are 4368 possible outcomes then you're covering 10 of the 4368 which would be about the same as 1/437.

* you don't need to buy more tickets, just buy a winning ticket *

Kentucky
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 Posted: December 17, 2010, 1:08 pm - IP Logged

Thank you,Stack. I was thinking more along the lines of this myself. But how is it 1/436? LoL. I'll get this right yet!

It gets confusing by putting it in terms of chances to win by saying there is 1 chance to win out of 437 chances.

Odds are calculated as chances to lose compared to chances to win. The actual odds against winning on a 5/39 are 575,574 to 1 because one of those combos has to win. Since 436 chances in your example will lose but one will win, the odds are 436 to 1.

Australia
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 Posted: December 18, 2010, 3:40 am - IP Logged

its a basic fraction reduction . 10/20 is same as 1/2. 10/4000 is same as 1/400 .

2014 = -1016; 2015= -1409; 2016 JAN = -106; FEB= -81; MAR= -131; APR= - 87: MAY= -91; JUN= -39; JUL=-134; AUG= -124; SEP = -123; OCT= -84  NOV=- 73 TOT= -3498

keno historic = -2291 ; 2015= -603; 2016= JAN=-32, FEB= +12 , MAR= -86, APR = -77. MAY= -48, JUN= -29, JUL=-71; AUG = -52; SEPT= -43; OCT = +56 NOV = -33 TOT= -3297

Kentucky
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 Posted: December 18, 2010, 5:06 pm - IP Logged

In listing odds there is difference between expressing them as "to" or "for". Odds of 10 to 1 means you win \$10 and keep your \$1. Most lotteries express odds of 500 to 1, but keep the \$1 so we actually win \$499. The odds should be 500 "for" 1.

Race tracks express odds in "to" and payoff by giving back the initial bet; that's why when the odds on a horse is 4 "to" 1, the payoff is \$10 on a \$2 bet.

Sunny California
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 Posted: December 28, 2010, 8:47 pm - IP Logged

It gets confusing by putting it in terms of chances to win by saying there is 1 chance to win out of 437 chances.

Odds are calculated as chances to lose compared to chances to win. The actual odds against winning on a 5/39 are 575,574 to 1 because one of those combos has to win. Since 436 chances in your example will lose but one will win, the odds are 436 to 1.

Great explanation,thanks much! I believe you un-confused me now  What were the odds of that? lol

Beautiful Florida
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 Posted: December 28, 2010, 8:56 pm - IP Logged

Great explanation,thanks much! I believe you un-confused me now  What were the odds of that? lol

That odds of that would be:      43.68 to 1

"  When Injustice Becomes Law, Resistance Becomes Duty "

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