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how to calculate the odds of this

Topic closed. 1 reply. Last post 6 years ago by RL-RANDOMLOGIC.

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New Member
new york
United States
Member #110090
April 25, 2011
5 Posts
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Posted: May 12, 2011, 4:47 pm - IP Logged

hi all , I am backtesting some systems and  I would like to know if someone can give me the mathematical formula to figure out the odds of the following --- Lets say just for example Im playing 29.6 % of all #s and yet none of my #s come out for 17 consecutive drawings. Would the odds be 29.6% divided by 2,divided  by 2 ,divided by 2 ,etc... 17 x ? 

                       thanks in advance , J

    RL-RANDOMLOGIC's avatar - usafce

    United States
    Member #59354
    March 13, 2008
    3971 Posts
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    Posted: May 12, 2011, 5:19 pm - IP Logged

    mylot

    It depends on what odds your looking for.  NY take-5 is a 5-39 game so 29.6% of the numbers equal 11.5.

    This would mean you are playing a different game because you can't have 11.5 numbers so for this I will

    use 11.  There are 462 sets of 5 in 11 numbers and 575757 sets of 5 in 39 so 575757/462=1246.2  so your

    odds would be 1 in 1246 if you play all 462 combos.   If you are using conditional odds where you think all

    5 numbers will come from the pool of 11 then the odds would be 1 in 462 for a 5 of 5.  The conditional odds

    for lower prizes are listed below

    4 of 5 = 1 in 15.4 

    3 of 5 = 1 in 3.08

    2 of 5 = 1 in 2.13

    1 of 5 = 1 in 6.16

    0 of 5 = 1 in 77

    These odds are based on the condition that all 5 numbers will come from the pool of 11.  The odds don't change

    for the game no matter how long a number is out.