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weel of 50/3/3

Topic closed. 10 replies. Last post 5 years ago by dr san.

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bgonçalves
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Posted: September 3, 2011, 8:47 pm - IP Logged

Hello, can someone help me on this wheel is 50 3 if 3 or 50/3/3 with 100% accuracy   I want to download this figure 19,600, already have this value, you must have 100% guarantee

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    Dump Water Florida
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    Posted: September 4, 2011, 4:56 am - IP Logged

    Hello, can someone help me on this wheel is 50 3 if 3 or 50/3/3 with 100% accuracy   I want to download this figure 19,600, already have this value, you must have 100% guarantee


    From 19,600 I can see you are asking for 50/3/3/3 or (50,3,3,3)=19600 not (50,3,3,6) it helps to provide as much information as you can.

    Send me an email (addy on the bottom of most of my L-L pages), put dr san 50333 in the subject line and I will send you the wheel.  If you have Advanced Lotto Tool you can make it yourself by creating a 50/3 lottery game and full wheeling all the numbers.  First combo 1-2-3 last 48-49-50.

    BobP

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      bgonçalves
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      Posted: September 4, 2011, 10:37 am - IP Logged

      Hello, bobp this conbinçao I have, I wanted to see if we could reduce this   = 03/03/50 = 19,600 of these wheels I have, the question whether it is possible to reduce more, Or reduction is only possovel large wheels with 100%, making arrangements for the lines in a matrix of the lottery, a lottery example 50 / 5 (Euromillions) we have 5 lines with ten numbers each = 10 / 5, what I'm trying to see a reduction better, because the wheels seem to be flaws in the structure of room construction, you may be separated with digits (digits forward and the final digit of each number) the BJECTIVES is to see the best possible reduction with guaranteed 100%

        Raven62's avatar - binary
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        Posted: September 4, 2011, 3:59 pm - IP Logged

        Hello, can someone help me on this wheel is 50 3 if 3 or 50/3/3 with 100% accuracy   I want to download this figure 19,600, already have this value, you must have 100% guarantee

        Lottery Wheels are based upon the premise that you can select a subset of the numbers that would be drawn and then the wheel will give you a list of all the combinations from that subset of numbers.

        A mind once stretched by a new idea never returns to its original dimensions!

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          bgonçalves
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          Posted: September 4, 2011, 6:04 pm - IP Logged

          Lottery Wheels are based upon the premise that you can select a subset of the numbers that would be drawn and then the wheel will give you a list of all the combinations from that subset of numbers.

          Ravem, I agree, but what I seek is just one example of lottery = 60 / 6   Divide into 4 groups of 15 numbers each is 100% guaranteed that at least one of these four groups will always have two numbers with guaranteed 100% in the cuddle, then this factor to accumulate more in this sector to generate pairs is to go after combining with other groups, the reduction is to try this, having the benefit of more lvl agr in an industry, and try to create a rotating wheel, of course you know that 10% will give two numbers (in mimino), but do not know what to do in the group will have 4 groups 15, this type of wheel that is looking for!

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            Dump Water Florida
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            Posted: September 5, 2011, 12:18 am - IP Logged

            Hello, bobp this conbinçao I have, I wanted to see if we could reduce this   = 03/03/50 = 19,600 of these wheels I have, the question whether it is possible to reduce more, Or reduction is only possovel large wheels with 100%, making arrangements for the lines in a matrix of the lottery, a lottery example 50 / 5 (Euromillions) we have 5 lines with ten numbers each = 10 / 5, what I'm trying to see a reduction better, because the wheels seem to be flaws in the structure of room construction, you may be separated with digits (digits forward and the final digit of each number) the BJECTIVES is to see the best possible reduction with guaranteed 100%


            Ah no.  No reduction would be possible.  If tomorrow some state started a 3/50 game the jackpot odds would be 1 in 19,600 because there would be 19,600 combinations making up the game and like wise the full wheel (50,3,3,3)=19,600 combinations that would be required to 100% guarantee a jackpot. 

            If we look at wheel (50,5,3,3) there are 10 ways in each line of 5 numbers to make a 3 number combinations, many of these will be duplicates through out the wheel, even so it takes fewer lines of 5 numbers than 3 numbers to  guarantee a 3 number win. 

            If you break the game down to 5 lines of 10 numbers, there is no room for reduction within those groups, it is straight forward. 

            BobP

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              bgonçalves
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              Posted: September 5, 2011, 9:51 am - IP Logged

              Hello, bobp, a good factor is just such a lottery = 49 / 6, almost two repeats of the final three digits (0 to 9 endings) of the previous result, then one way to see the lottery pairs and trios 49 / 6 repeat of the final digits, you can see this study? Pushing a twos and threes, the rest would be completed with different teminaçoes the latest results, the guarantee would be given in this condition!

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                Posted: September 5, 2011, 10:17 am - IP Logged

                Hello, bobp, a good factor is just such a lottery = 49 / 6, almost two repeats of the final three digits (0 to 9 endings) of the previous result, then one way to see the lottery pairs and trios 49 / 6 repeat of the final digits, you can see this study? Pushing a twos and threes, the rest would be completed with different teminaçoes the latest results, the guarantee would be given in this condition!

                In this Instance: Use a 3-Number Key Wheel...

                A mind once stretched by a new idea never returns to its original dimensions!

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                  bgonçalves
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                  Posted: September 6, 2011, 11:02 am - IP Logged

                  Hello, bobp, a lottery of 49 / 6 split into 3 groups   1st group = 16 numbers Group 2 = 16 numbers Group 3 = 17 numbers However as we are dealing with only three groups, Consider these variations:
                  System 600: 600 - 060 to 006 System 510: 510-501 - 051-015 - 150-105 System 420: 420-402 - 042-024 - 140-104 System 411: 411 - 141 to 114 System 330: 330 - 303 to 033 System 321: 321 - 312 to 231 - 213 - 123 to 132 222 system: 222 Are all possibilities Emde occurrences in the three groups can be created based on the wheel tends number 231 = best example would be the base group of two or three groups, you can see a rotating system with these various groups?

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                    Posted: September 7, 2011, 3:42 am - IP Logged

                    Hello, bobp, a lottery of 49 / 6 split into 3 groups   1st group = 16 numbers Group 2 = 16 numbers Group 3 = 17 numbers However as we are dealing with only three groups, Consider these variations:
                    System 600: 600 - 060 to 006 System 510: 510-501 - 051-015 - 150-105 System 420: 420-402 - 042-024 - 140-104 System 411: 411 - 141 to 114 System 330: 330 - 303 to 033 System 321: 321 - 312 to 231 - 213 - 123 to 132 222 system: 222 Are all possibilities Emde occurrences in the three groups can be created based on the wheel tends number 231 = best example would be the base group of two or three groups, you can see a rotating system with these various groups?


                    These are the number of numbers allowed from each group in making up the combinations.  231 would mean the first group would contribute two numbers to each combination in turn and so on.

                    While you can use several of these sets, you might also simply allow the option, no more than 2 no less then 2 from the first group, no more than 3 and no less then 2 from the second group and no more then 2 and no less then 1 from the third group.

                    Of course the more of this you do, the more combinations that pass this filter.

                    Any rotation of the system would depend on your seeing said rotation in the draws.  I just park on 222 and wait for it to come to me.  Of course I filter down to ten combinations or less so I don't care so much when I lose.  I wouldn't want to lose 19,600 once even playing with someone else's money.

                    BobP

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                      bgonçalves
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                      Posted: September 7, 2011, 8:13 am - IP Logged

                      Hello, bobp within these sets possible to happen, as it could create filters?   For positions not repeated, what would be the reference group (base), and these statistics do   Groups! to then make wheels! example in the wheel 2,2,2 eslheria two numbers in each group!