Welcome Guest
You last visited December 11, 2016, 5:30 am
All times shown are
Eastern Time (GMT-5:00)

# pick3 even-odd numbers

Topic closed. 3 replies. Last post 5 years ago by dr san.

 Page 1 of 1
New Member
NewYork
United States
Member #68392
December 20, 2008
21 Posts
Offline
 Posted: November 19, 2011, 12:27 am - IP Logged

Hi guys,

I need some help in developing this method. out of 1000 numbers

125 - all odd( ex: 135 113 357 975 997 .....)

125 - all even (ex: 246 268 880 ....)

375 - two even and one odd (ex: 467 986 883 029 ....)

375 - two odd and one even (ex: 974 556 396 ....)

My concentration is on only 375 numbers which are of odd even (both) . More than 85% of the time either    two even one odd  or  two odd one even  comes.

I need help in picking only one 375 numbers  on exact day which comes depending on previous draw or day or date or anything..

Guest

Member #0
January 1, 2000
0 Posts
Offline
 Posted: November 19, 2011, 8:29 am - IP Logged

Check history and see how many draws the longest before they switch. If you see long draws between switches, then go back in history again and see how often it happens. If it happens on regular basis, wait a few draws then switch. but still very risky.

ex:

In 3 month history, 12 times a long wait happens before a switch. let's say 4 or 5 draws before switch. this means it happens on regular basis, which is about once a week. still too risky unless you plan to narrow down the 375 and play online.

bgonÃ§alves
Brasil
Member #92564
June 9, 2010
2126 Posts
Offline
 Posted: November 19, 2011, 2:22 pm - IP Logged
Hello, ahtnana, you can also see it =
Low = 1,2,3,4,5
High = 6,7,8,9,0
If the third digit of 1,2,3,4,5 pick3 are all low, we have 10 conbinçoes
Also 10 pairs combinations
Or pick three high 6,7,8,9,0
We have 10 conbinaçoes.
10 high pairs conbinaçoes
Ahtnana note that the groups have two low pairs = 2.4
And in the high group 3 pairs = 6,8,9
You can also pair formation with low single digits and another high example = 28
bgonÃ§alves
Brasil
Member #92564
June 9, 2010
2126 Posts
Offline
 Posted: November 19, 2011, 2:41 pm - IP Logged
Hello, this use has 25 pairs, and 90% of the results,
Course within the three positions, the third digit is random
These 25 pairs are formed with a group down and typed a digit in the high group ok
Here = 25 pairs =
1 6
1 7
1 8
1 9
1 0
2 6
2 7
2 8
2 9
2 0
3 6
3 7
3 8
3 9
3 0
4 6
4 7
4 8
4 9
4 0
5 6
5 7
5 8
5 9
5 0

 Page 1 of 1