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# Algorithms for number selection?

Topic closed. 51 replies. Last post 4 years ago by RJOh.

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MA
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March 30, 2010
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 Posted: April 26, 2012, 5:30 pm - IP Logged

Does anyone have or know of any simple algorithms to try on past drawings to determine the result of the next draw?  I have been working on our pick 5 here in Mass and always seem to miss the big win.  I have discovered that from the last 2 draws I can almost always find the next winning draw line.  This is done by just adding or subrtracting from the last 2 lines to make up the proables for the next draw.  Even knowing this I can't manage to even lock down 4/5 never mind 5/5.

I could post an example if that would help to assist anyone with some ideas as I'm just about exhausted.  It seems so simple yet I always miss out.

That is why I was hoping maybe there is an algorithm to help pin this down or another simple way, I just can't seem to see it!

M

MA
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 Posted: April 26, 2012, 5:50 pm - IP Logged

Ok, here is an example:

Draw 4/23/2012        3-7-9-20-23

Draw 4/22/2012         19-21-25-30-31

Draw 4/21/2012        6-7-10-33-35

Now pretending we did not know the outcome of April 23rd here is what I usually do to find the probable numbers.

Taking 10 minus 7 = 3

Taking 31 minus 25 = 6 + 1 = 7

taking 30 minus 21 = 9

Taking 33 minus (6+7) = 20

Taking 33 minus 10 = 23

Now the tricky part, it isn't always this easy as a lot of times these additions and subtractions are different and are from different digits within the 2 lines but almost always just by doing basic math can yield a good set of probable numbers.  Basically the theme is by adding a 1 or subtracting a 1 or sometimes 2 from the first basic equations will yield all 5 winning numbers.  I just can't seem to isolate which ones will be drawn as there are many combinations that can be gotten from 10 initial digits.

I do believe I'm just not seeing the light as i just don't know what to try next as wheels don't seem to help without the correct numbers selected.

I can go back say 25 draws and just by doing this basic math from 2 previous draws can almost always put together the 5 numbers.  I just can't seem to pin them down to yield some 4/5's or even a 5/5

Can anyone suggest something maybe more math intensive or even something simple that has been overlooked?

Thanks for any input!

Meskhov

mid-Ohio
United States
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March 24, 2001
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 Posted: April 27, 2012, 3:07 pm - IP Logged

I've been using a similar system to pick numbers for MM the last few weeks only I search all the drawings back to 06/24/l2 when the present matrix started and look at the numbers in the last drawing and what followed them every time they hit in past drawings in the same positions.

For example in the last drawing the lowest number was 3 and it has been the lowest number 54 of the 61 times it hit in the past 713 drawings.  Thirty seven of those time when the previous number was higher, the lowest number in the next drawing was a three or higher up to 23.  Since eleven of those numbers repeated three or more times, I'll be picking my lowest numbers from that group for tonight's MM drawing.  I'll picking the other four numbers in a similar fashion.

Back testing the last 14 drawings showed I had a chance of matching four or better in four of those drawings using a pool of less than 25 numbers. The only problem is I don't know how many combinations can be generated using these parameters and I will only be generating 20 for tonight's drawing and hoping if all five winners are in the mix that they are on the same line.

* you don't need to buy more tickets, just buy a winning ticket *
* your best chance for winning a lottery jackpot is to buy a ticket *

United States
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March 14, 2012
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 Posted: April 27, 2012, 3:24 pm - IP Logged

according to KISS, a simple algorithm would be as follows...

If your last draw results were    (N1)  (N2)  (N3)  (N4)  (N5)... then the next draw could be

(N1)  (N1+1)  (N3+1) (N4+3)  (N5-3)

of course you would have to try out all the differnt possible algorithms and back test to see which occurs the most.

well not all, but i would start with the core fibs...+0, +/-1, +/-2, +/-3 almost every draw has an adjacent number so you just have to guess when you think 2 or more will occur...

mid-Ohio
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 Posted: April 27, 2012, 3:42 pm - IP Logged

according to KISS, a simple algorithm would be as follows...

If your last draw results were    (N1)  (N2)  (N3)  (N4)  (N5)... then the next draw could be

(N1)  (N1+1)  (N3+1) (N4+3)  (N5-3)

of course you would have to try out all the differnt possible algorithms and back test to see which occurs the most.

well not all, but i would start with the core fibs...+0, +/-1, +/-2, +/-3 almost every draw has an adjacent number so you just have to guess when you think 2 or more will occur...

That's a fairly easy one to test.  I would be surprised if it hasn't already been tested for most games.  A similar one for pick3 and pick4 games have been written about many times.  Since most of those threads didn't get much attention, I assume it wasn't very successful.

* you don't need to buy more tickets, just buy a winning ticket *
* your best chance for winning a lottery jackpot is to buy a ticket *

MA
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 Posted: April 27, 2012, 4:38 pm - IP Logged

RJOH:

Thanks for the reply.  I do believe there is a simple solution to this but I can't seem to nail it down to a reasonable set of numbers to wheel.  As from my example almost every draw is similar to this but I just can't seem to narrow it down enough to even capture a 4/5 from the grouping.  I was hoping for some simple equations but I guess that won't happen.  I was hoping that I just am not seeing something simple in order to derive a better simple equation to narrow a group of winning numbers down.

If you have any further ideas I would be very interested in hearing them!

Thanks

M

mid-Ohio
United States
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March 24, 2001
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 Posted: April 27, 2012, 4:57 pm - IP Logged

RJOH:

Thanks for the reply.  I do believe there is a simple solution to this but I can't seem to nail it down to a reasonable set of numbers to wheel.  As from my example almost every draw is similar to this but I just can't seem to narrow it down enough to even capture a 4/5 from the grouping.  I was hoping for some simple equations but I guess that won't happen.  I was hoping that I just am not seeing something simple in order to derive a better simple equation to narrow a group of winning numbers down.

If you have any further ideas I would be very interested in hearing them!

Thanks

M

It all depends on what you call simple.  When Massachusetts had a run down of their state game when the jackpot hadn't been won after reaching more than \$4M and would be shared among the second prizes winners, the couple from Michigan thought buying \$150K to \$300K worth of tickets to win a few second prizes a simple solution to winning part of the jackpot.   But if I ever came up with an algorithm, it wouldn't  be simple if it required me to spend more than \$25-\$50 to win, even win big.

* you don't need to buy more tickets, just buy a winning ticket *
* your best chance for winning a lottery jackpot is to buy a ticket *

MA
United States
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March 30, 2010
245 Posts
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 Posted: April 27, 2012, 6:42 pm - IP Logged

RJOH:

Yes, I see what you mean.

I'm going to try a few things in the upcoming games and see if it helps with the number selections.

Will let you know if anything develops.

We'll keep trying.

Thanks Again for all your assistance.

M

cleveland ohio
United States
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October 9, 2008
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 Posted: April 28, 2012, 1:59 am - IP Logged

I've been using a similar system to pick numbers for MM the last few weeks only I search all the drawings back to 06/24/l2 when the present matrix started and look at the numbers in the last drawing and what followed them every time they hit in past drawings in the same positions.

For example in the last drawing the lowest number was 3 and it has been the lowest number 54 of the 61 times it hit in the past 713 drawings.  Thirty seven of those time when the previous number was higher, the lowest number in the next drawing was a three or higher up to 23.  Since eleven of those numbers repeated three or more times, I'll be picking my lowest numbers from that group for tonight's MM drawing.  I'll picking the other four numbers in a similar fashion.

Back testing the last 14 drawings showed I had a chance of matching four or better in four of those drawings using a pool of less than 25 numbers. The only problem is I don't know how many combinations can be generated using these parameters and I will only be generating 20 for tonight's drawing and hoping if all five winners are in the mix that they are on the same line.

Thats why I love this place so much. If combined with what Im working on for Splinter trying to find the actual decades of numbers to be drawn the pool would be much easier to manage and perhaps much more focused.

We all hit things at different angles and just miss but some day we will collectively pool all of it into a winner.  keep the up the great work that is an excellent approach.

mid-Ohio
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March 24, 2001
19786 Posts
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 Posted: April 28, 2012, 2:45 pm - IP Logged

We all hit things at different angles and just miss but some day we will collectively pool all of it into a winner.

I'm surprised it hasn't already happened but I guess when it comes to winning a lottery jackpot, luck trumps good ideas every time and there isn't an algorithm for that.

* you don't need to buy more tickets, just buy a winning ticket *
* your best chance for winning a lottery jackpot is to buy a ticket *

Appleton, Wi
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October 24, 2011
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 Posted: April 30, 2012, 7:39 pm - IP Logged

Made from last 30MM drawings. 1,6,.... have 4hits last 30 games. 4,5,10 have 3hits last 30 games. Maybe 4 and 13 will get hits on 5-1-2012 to straighten out the curve??

0  1  2  3  4  5  6  7

1                        1

2                             2

3                             3

4                   4

5                   5

6                         6

7        7

8        8

9                                      9

10                 10

11          11

12     12

13 13

14                  14

15                  15

16                        16

17                        17

18                  18

19                        19

20                  20

21            21

22       22

23                  23

24                         24

25            25

26            26

27                   27

28                         28

29                         29

30                         30

31                   31

32            32

33                   33

34    34

35           35

36                                    36

37           37

38                          38

39           39

40    40

41    41

42                   42

43            43

44    44

45            45

46            46

47                    47

48                           48

49            49

50     50

51                    51

52            52

53                    53

54     54

55 55

56 56

Good Luck,

BlueDuck

mid-Ohio
United States
Member #9
March 24, 2001
19786 Posts
Online
 Posted: April 30, 2012, 10:07 pm - IP Logged

Made from last 30MM drawings. 1,6,.... have 4hits last 30 games. 4,5,10 have 3hits last 30 games. Maybe 4 and 13 will get hits on 5-1-2012 to straighten out the curve??

0  1  2  3  4  5  6  7

1                        1

2                             2

3                             3

4                   4

5                   5

6                         6

7        7

8        8

9                                      9

10                 10

11          11

12     12

13 13

14                  14

15                  15

16                        16

17                        17

18                  18

19                        19

20                  20

21            21

22       22

23                  23

24                         24

25            25

26            26

27                   27

28                         28

29                         29

30                         30

31                   31

32            32

33                   33

34    34

35           35

36                                    36

37           37

38                          38

39           39

40    40

41    41

42                   42

43            43

44    44

45            45

46            46

47                    47

48                           48

49            49

50     50

51                    51

52            52

53                    53

54     54

55 55

56 56

Good Luck,

BlueDuck

It's going to be interesting to see the algorithm you develop using that data.

Good luck.

* you don't need to buy more tickets, just buy a winning ticket *
* your best chance for winning a lottery jackpot is to buy a ticket *

Economy class
Belgium
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February 27, 2012
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 Posted: May 4, 2012, 7:56 am - IP Logged

I think that all you find is that generally there is no such thing as full repeats or totally different, especially if you divide your numbers into groups.

Example of changes to nearest:

 0 -1 +7 0 -4 0 0 +-1 -1 -4 -5 0 0 -3 +-1 -6 +1 +1 +15 +6 -1 -3 +3 0 -4 -6 -8 +-10 -1 -3 +-5 +3 +1 +-1 +1 -16 +-3 +2 0 -2 -5 +3 0 -1 -2 -3 -3 -5

0 = repeat, ... . For repeats there is an easy average probability, but as you can see an average isn't a rule.

There is a greater chance that there are more different numbers than same numbers drawn.
When you are lucky, you can find a trend-group hitting over a longer period.
The above is simplified and you can simplify it even more with ABS().

You might come up with ideas like playing adjacent numbers and repetitions, in the second and third row you would have got 4/6 by playing 18 numbers. This does not happen a lot.

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 Posted: May 5, 2012, 11:36 pm - IP Logged

meskhoy

I worked on something simialr to this but finally gave it up.  Taking the numbers from a couple draws

and using hindsight to build the next set is easy once the draw is over with but doing it before the

draw is a bit harder.  It's amazing just how many numbers can be gotten from this sort of analysis.

Once the draw has come and gone it's much easier to come up with the correct 5 but that dose not

help us win.  Ever notice how often one or more numbers come from the date.  count the day as 1 to 7

use the day of the month plus the month and the four digit year.

Saturday = 7 the last day of the week

the day today  is the 5th

the month is also the 5th

and the year is 20 and 12

Here we have 7-5-5-20-12

so from these nmbers we could make up several

Using the digits

5-7-12-15-17-20-21-25-27

using subtraction

2-3-4-5-7 etc...

19-37-46-28-etc...

once you work out every solution you have many numbers to choose from.  The day of the month

does seem to match one of the numbers drawn so who knows.  The best way to calculate all the

possible  outcomes is to count digits.  If you have all 10 digits then you have the makings for any

number in your lottery which would make having 5of5 a breeze.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

United States
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March 14, 2012
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 Posted: May 6, 2012, 3:14 am - IP Logged

That's a fairly easy one to test.  I would be surprised if it hasn't already been tested for most games.  A similar one for pick3 and pick4 games have been written about many times.  Since most of those threads didn't get much attention, I assume it wasn't very successful.

Ok mister unknowledgable....i would like to see you do the analysis...and dont forget the f--king fibbies...or i will have to fast furious fully function fabricate fully a function fiddly diddly fideism...>>>>>>U...f---E-R

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