bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 7, 2012, 4:10 pm - IP Logged

Quote: Originally posted by x1kosmic on June 7, 2012

I get it Dr. San

My last states results were 07- 16- 20- 21- 35

the formula, or set-up, should have been

0- 1- 2- 2 but don't do the last number

Dr. San ? if thats it I like

Hello, x1kosmic, ok perfect, Dr. sistem san, was divided into two parts ok in front of digits ranging from 3 0th and endings ranging from 0 to 9, the fifth number is wild (random, you can choose in the 5th position in the vertical view statistics to see the three frequencies, xkosmic, the number of wildcards can also be a 0023 x = x is the wildcard) It may be the 2nd 3rd and 4th and 5th of the 4th example {1,2,3 x3. So you can play the joker with 5 possobidades below the 5 positions, Another possibility is to play in the center with three pairs of edges Example results of your pair of spikes or the smallest number with the largest = 07 32 07xxx 32 where x is the matrix will, of course is now only three, three is easier to hit With patience will get the hang of. It varies variants system Dr. san

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 7, 2012, 5:01 pm - IP Logged

Hello, x1kosmic, pays attention, the system dr san, has many ways = Look at the example of the draw = 07 = 16 20 21 35 Let's make the limit 01 to 10 to 1 or smaller number of the pair and the limit of 21-39 for the 5th or the greatest number = total pairs this limit = 01 to 10 and 21 39 = are 90 pairs within the 90 pairs, can see for three frequencies, or look there is no repetition of the digits 07 35, ok! 07 35 the pair, the other three numbers ranging within the limits 07-35 will 08-34 07 XXX 35 where x is the three. are the groups 20 07 0_ 0_ 1_35, now only missing endings, which can be filtered like a pick3

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 7, 2012, 5:31 pm - IP Logged

Hello, 1kosmic, I did limit the pairs 01-08 and 30-35 gave 48 pairs. Following pairs ok, you can see the use of these 48 pairs? well after It is being put the pair,

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 8, 2012, 9:21 am - IP Logged

Helo x1kosmic has to do in four editions, because whenever a group has zero or a number And another two or more numbers in a group 100% will always carry

Economy class Belgium Member #123700 February 27, 2012 4035 Posts Offline

Posted: June 8, 2012, 1:07 pm - IP Logged

@ san

It helps to reverse the string to make yourself less comprehensive!

uoy knaht ?9/93 yrettol a ni ti ees nac usniw ,93,83,62 62 eb ll'tI neht ,9,8,7,6 = gnitaeper-non eb tsum slanimret eht esac siht ni oS rebmun eht taeper lliw oaçnaimret eht taeper ot tnorf 3,3,2,2 = tigid elpmas ton naC tigid lanif ro sgnidne detaeper era tnorf fo spuorg nehw rO nac ,63 62 61 60 semoceb ti neht ,6666 sepyT detaeper eb nac sgnidne = 3,2,1,0 = elpmas taeper oN si stigid fo spuorg tnorf eht nehw ti ees ot usniw deen I retlif ro tsacerof eht fi ,nmuloc eht ni tigid ro rebmun a taeper uoy nehW os ees ot ,usniuw htiw srebmem decneirepxe erom deen I ,olleH

Economy class Belgium Member #123700 February 27, 2012 4035 Posts Offline

Posted: June 8, 2012, 1:09 pm - IP Logged

Quote: Originally posted by dr san on June 7, 2012

Hello, x1kosmic, ok perfect, Dr. sistem san, was divided into two parts ok in front of digits ranging from 3 0th and endings ranging from 0 to 9, the fifth number is wild (random, you can choose in the 5th position in the vertical view statistics to see the three frequencies, xkosmic, the number of wildcards can also be a 0023 x = x is the wildcard) It may be the 2nd 3rd and 4th and 5th of the 4th example {1,2,3 x3. So you can play the joker with 5 possobidades below the 5 positions, Another possibility is to play in the center with three pairs of edges Example results of your pair of spikes or the smallest number with the largest = 07 32 07xxx 32 where x is the matrix will, of course is now only three, three is easier to hit With patience will get the hang of. It varies variants system Dr. san

Olá, x1kosmic, ok perfeito, Dr. sistem san, foi dividido em duas partes ok na frente de dígitos que varia de 3 0 e finais variando de 0 a 9, o quinto número é selvagem (aleatório, você pode escolher na 5 ª posição no as estatísticas de visão vertical para ver as três frequências, xkosmic, o número de curingas também pode ser um 0023 x = x é o curinga) pode ser o terceiro segundo e quarto e quinto do exemplo 4 {1,2,3 x3. Assim você pode jogar o joker com 5 possobidades abaixo dos 5 posições, outra possibilidade é jogar no centro, com três pares de resultados Exemplo bordas de seu par de picos ou o menor número com o maior = 07 32 07xxx 32, onde x é o matriz, é claro é agora apenas três, três é mais fácil de acertar com paciência vai pegar o jeito. Ela varia de variantes do sistema Dr. san

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 8, 2012, 1:37 pm - IP Logged

Hello sergem, but the difficulty will always be 0-9 up because I fear 10 000 combinations It's like a pick four dismembered, the system is done in two parts The first part is 100% guaranteed at least one of the 37 combinations hits forever!, But you can do with only three have 20 combinations, and unite the extreme pairing and three in the center, to predict the 0-9 can be make it into a pick3 There are several way to do this is important is the matrix perfect 100% in all drawings, Having secured halfway, still missing, only to be even and odd

I wish I can understand what you're talking about. Only then I might be able to remember you. Maybe you can try translate to German or French first and then translate that to English. Try that to see if it's any better.

xaab

dr san is using 4 decade digits for four of the numbers then allowing the fifth to be picked randomly.

The list is the combinations of decades. 3 3 3 3 = 4 numbers in the 30's + one randomly generated

set. You have to select one decade group from the list and if correct then you have at least one 4of5

and many 3of5's that could also be 4of5 if the random number also matches a number in the set. It

would only work if you can pick the correct one from the list. If you play them all then you are talking

a lot of sets. using 3 3 3 3 for four decades would give you all the sets 30-31-32-33 to 36-37-38-39

plus any random number that is not one of the 4.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 10, 2012, 9:06 am - IP Logged

Quote: Originally posted by RL-RANDOMLOGIC on June 10, 2012

xaab

dr san is using 4 decade digits for four of the numbers then allowing the fifth to be picked randomly.

The list is the combinations of decades. 3 3 3 3 = 4 numbers in the 30's + one randomly generated

set. You have to select one decade group from the list and if correct then you have at least one 4of5

and many 3of5's that could also be 4of5 if the random number also matches a number in the set. It

would only work if you can pick the correct one from the list. If you play them all then you are talking

a lot of sets. using 3 3 3 3 for four decades would give you all the sets 30-31-32-33 to 36-37-38-39

plus any random number that is not one of the 4.

RL

Hello, xaab the rl understood, perfect xaab the fifth number, can also be the 1st or 2nd in the 3rd or fourth position, the above examples are the fifth position of the random number, But it could be the other four posiçoe Xaav the list of 37 is 100% in all drawings, but you do not need to play all 37 You can make the analysis of the three frequencies, hot, medium, and cold, eg The training = 000 332 333, are very hard to leave. Can also choose So even or only odd = odd pairs = 0022 or 1133 or variation example has also Creating pair of ends, you can only play three 07 xxx 35, For the final digits, you can use the pick pic3 and 4 in the example of peers, Ie the system was divided into two blocks ok, the digits of the front is 100% garntido Of course the termiançoes go 0-9 is the worst, always remembering that doing 4 editions of the quadrants, one will always carry, is a game to play with several friends,

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 10, 2012, 10:50 am - IP Logged

Quote: Originally posted by topnail on June 10, 2012

it is not work for me

i agree is 100 % that all first digit of the set

but how many combianation will be fill in second digit thai is ?

too much to lose

sorry

Hello nail top, of course, the great difficulty is to hit the the ending, you can use the pick4 pick3 or when it is for couples, is a game to play with friends, make a bowling The final digit can be any pair example 0-9 2,4,6,8. 1,5,7,9 or odd, Then you can use the sitema rl randonlogic to filter the final digits, has several Statistics in the vertical, if it were easy we would have cracked the lottery, you need solft To simulate conditions, filter the results above, with pen to paper is not possible,

bgonÃ§alves Brasil Member #92564 June 9, 2010 2122 Posts Offline

Posted: June 10, 2012, 11:29 am - IP Logged

Quote: Originally posted by dr san on June 10, 2012

Hello nail top, of course, the great difficulty is to hit the the ending, you can use the pick4 pick3 or when it is for couples, is a game to play with friends, make a bowling The final digit can be any pair example 0-9 2,4,6,8. 1,5,7,9 or odd, Then you can use the sitema rl randonlogic to filter the final digits, has several Statistics in the vertical, if it were easy we would have cracked the lottery, you need solft To simulate conditions, filter the results above, with pen to paper is not possible,

Hello nail top, you must go in search of patterns, look at the example Result = 08 09 23 24 32 Next results = 15 23 29 32 38 Of the first four digits repeated 3.9'm talking about the final digit 0-9 So of the 10 000 possible solft, filtraria groups that have the 3.9 digit Of course it could be 8.4, which make mass repeats, endings exatemente With a pick4,

Los Angeles County, Ca. United States Member #128513 May 26, 2012 2261 Posts Offline

Posted: June 10, 2012, 12:13 pm - IP Logged

Good Morning RL,

I have been reading this stuff for 4 days, maybe I am not as mathematically advanced as some of you here on the LP, or maybe because many words will not translate from Portuguese to English, in any case I am really lost. Could you please help explain it to me? Maybe if I saw an example, from the start to a finished set of numbers I might grasp it a bit better.