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# Cash 3 and Fantasy 5 Comparison

Topic closed. 6 replies. Last post 4 years ago by onlymoney.

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Thread Starter

United States
Member #134627
November 2, 2012
1122 Posts
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 Posted: November 30, 2012, 9:07 am - IP Logged

Cash 3 fools naive players by showing only what seems to be 9 numbers, but are actually 10. If only those 10 numbers were involved, there would be 720 combinations to guess among, very little. However, each number , apparently, can come up twice in one combination, and even 3 times! That makes 30 numbers, which create a lot more, 24360 possible combinations.

Still, if we compare 24.360 combinations in Cash 3 to Fantasy 5, where 36 numbers create a whooping 376.992 combinations, due to larger amount of numbers per combination, and numbers in general, then Cash 3 does not seem that bad, even with small pay offs. In Fantasy 5 you have to work 16 times harder, which means buying 16 tickets per each 1 ticket in Cash 3, to get same pay off, \$500, and even that does not come often.

Kentucky
United States
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February 14, 2006
7455 Posts
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 Posted: November 30, 2012, 3:02 pm - IP Logged

Cash 3 fools naive players by showing only what seems to be 9 numbers, but are actually 10. If only those 10 numbers were involved, there would be 720 combinations to guess among, very little. However, each number , apparently, can come up twice in one combination, and even 3 times! That makes 30 numbers, which create a lot more, 24360 possible combinations.

Still, if we compare 24.360 combinations in Cash 3 to Fantasy 5, where 36 numbers create a whooping 376.992 combinations, due to larger amount of numbers per combination, and numbers in general, then Cash 3 does not seem that bad, even with small pay offs. In Fantasy 5 you have to work 16 times harder, which means buying 16 tickets per each 1 ticket in Cash 3, to get same pay off, \$500, and even that does not come often.

"That makes 30 numbers, which create a lot more, 24360 possible combinations."

Those 30 digits are equally distributed in groups of 10 with each group having the same 10 digits. 10 times 10 times 10 equals 1000.

I understand what you're saying but in either game you'll probably collect less than 50% of your total wagers.

Thread Starter

United States
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November 2, 2012
1122 Posts
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 Posted: November 30, 2012, 3:51 pm - IP Logged

1000? You are a dreamer. :)

United States
Member #128790
June 2, 2012
5431 Posts
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 Posted: November 30, 2012, 4:06 pm - IP Logged

1000? You are a dreamer. :)

000-999= 1,000 combos total. I have no idea what kind of math you are using, but it doesn't work.

First column-10

Second column-10

Third column-10

10X10=100, 100X10=1000

Kentucky
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February 14, 2006
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 Posted: November 30, 2012, 9:27 pm - IP Logged

1000? You are a dreamer. :)

If 30 ping pong balls with three balls each having one digit between 0 and 9 were put into a container and just three were drawn, there are 24,360 permutations. But that doesn't change the fact there are "only" 1000 possible outcomes.

Thread Starter

United States
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November 2, 2012
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 Posted: December 1, 2012, 6:10 am - IP Logged

Since there is 24360 permutations, and 2 of the balls actually have number of a first one, the only way is to divide 24360 by 3, which gives us 8120 combinations. Still it is not 1000.

If we have 10 balls, then 10X9X8= 720 combinations, where order of the numbers matters. I multiply 3 upper numbers because game calls for three numbers chosen in a combination.If I use your method, then I should 720 X 720 X 720=373 millions approximately.

This game has options where order of numbers does not matter, so for that option 720 : 6=120. By your method 120 X 120 X 120=1.728.000 ( almost 2 millions).

United States
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June 2, 2012
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 Posted: December 1, 2012, 4:50 pm - IP Logged

Since there is 24360 permutations, and 2 of the balls actually have number of a first one, the only way is to divide 24360 by 3, which gives us 8120 combinations. Still it is not 1000.

If we have 10 balls, then 10X9X8= 720 combinations, where order of the numbers matters. I multiply 3 upper numbers because game calls for three numbers chosen in a combination.If I use your method, then I should 720 X 720 X 720=373 millions approximately.

This game has options where order of numbers does not matter, so for that option 720 : 6=120. By your method 120 X 120 X 120=1.728.000 ( almost 2 millions).

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