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Fl Fantasy 5, for December 7, Groups of Numbers

Topic closed. 2 replies. Last post 4 years ago by Uluska.

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Uluska's avatar - strawberry

United States
Member #134627
November 2, 2012
1001 Posts
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Posted: December 7, 2012, 8:34 am - IP Logged

15 numbers (3003 possible combinations where order of numbers does not matter):

10, 14, 15, 17, 20,

32, 22, 26, 27, 28, 

36, 23, 25, 33, 35

 

12 numbers (792 possible combinations where order of numbers does ot matter):

28, 10, 32, 14, 17, 33, 22, 36, 25, 23, 27, 26

 

8 numbers (56 possible combiantions where order of numbers does not matter):

12, 34, 15, 35, 16, 13, 20, 29

 

8 numbers ( 56 possible combinations):

13, 28, 22, 25, 26, 18, 34, 27

    Uluska's avatar - strawberry

    United States
    Member #134627
    November 2, 2012
    1001 Posts
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    Posted: December 7, 2012, 8:52 am - IP Logged

    With the amount of possible combinations being rather large, we can still be optimistic, because for every 5 number combination there is more of 4 number combinations inside that can be matched, and even more those of three number combinations and, of course, lots of two number combinations that can be guessed for at least a Free Ticket. For example, 5 number combination has five 4-number combinations inside itself to potencially be guessed. So, while aiming at 5 numbers we simultaneously aiming at five 4 number wins, ten 3-number combinations, etc., of course, only one of them can potentially be a match.

    Say, I have 6 numbers, I wheel them and get six 5-number combinations. That also means that I have thirty 4- number combinations and sixty 3-number combinations in my tickets. Altogether 91 combinations that can bring me, say, in Fl Fantays 5, monetary reward that is higher than my spending.

      Uluska's avatar - strawberry

      United States
      Member #134627
      November 2, 2012
      1001 Posts
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      Posted: December 8, 2012, 7:29 am - IP Logged

      Ok, result is: 6-9-18-21-24

      Groups had none. There is more groups that can be derived from previous numbers, I just can'

      t type them all. Take 5 previous lines, and write down all the double digit numbers, cross over those that repeat. Amount of numbers will change with every game. Then make tickets out of those numbers. As you can see, 18, 21, and 24 were inside that group.

      And, of course , 27 numbers group, created excluding single numbers,  will always have double digit numbers.