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# patterns

Topic closed. 38 replies. Last post 4 years ago by dr san.

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Economy class
Belgium
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February 27, 2012
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 Posted: January 8, 2013, 6:30 pm - IP Logged
 13/05/2008 1 2 3 4 5 6 9 11 13 23 27 29 31 32 42 45 52 58 64 65 4/12/2010 1 2 3 4 5 6 7 10 24 27 29 30 39 47 53 55 60 65 66 67

6/6 = 200 EUR

 Date N1 N2 N3 N4 N5 N6 N7 N8 N9 N10 N11 N12 N13 N14 N15 N16 N17 N18 N19 N20 20/07/2009 8 10 15 16 17 18 19 20 21 22 23 38 42 44 52 54 55 56 64 69 21/03/2012 2 3 14 17 18 19 20 21 22 23 24 27 32 34 41 44 54 56 63 66

9/9 = 50 000 EUR

8/8 = 10 000 EUR

Gail Howard: "Don't play 1 to 6!"

Economy class
Belgium
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 Posted: January 8, 2013, 6:46 pm - IP Logged

I could find only one drawing with spread numbers in more than 1000 drawings!

 16/08/2008 4 9 12 14 20 22 25 28 31 34 36 40 43 46 49 52 54 56 65 69
florida
United States
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December 16, 2012
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 Posted: January 8, 2013, 6:57 pm - IP Logged

a couple months ago here in fl we had 98 people won on fantasy five playing 1 3 5 7 9 i wasnt one of them they only got like 2300 each lol

Somerset
United Kingdom
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December 17, 2004
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 Posted: January 8, 2013, 8:35 pm - IP Logged

Every combination has exactly the same chance as any other combination, even if it did appaer 10 weeks in a row, in the following draw the stats are reset.

Each combination does have a different chance of appearing in different positions on a ticket but the overall odds always remain unchanged,

In a 6/49 lotto there are 13,983,816 different 6 ball combinations, you pick one line per bet you have one in 13,983,816 of winning the jackpot.

Distributions come in to play when talking less than 6 hits in a 6/49 but the overall odds can never change no matter which combination you select

I will now demonstrate

-----------------------------------------------------

In a 6/49 draw

1,712,304 combinations of the possible 13,983,816 combinations have ball 1 as the lowest ball

178,365 combinations of the possible 13,983,816 combinations have ball 2 as the 2nd ball

15,180 combinations of the possible 13,983,816 combinations have ball 3 as the 3rd ball

990 combinations of the possible 13,983,816 combinations have ball 4 as the 4th ball

44 combinations of the possible 13,983,816 combinations have ball 5 as the 5th ball

1 combination of the possible 13,983,816 combinations have ball 6 as the 6th ball (01 02 03 04 05 06)

1,712,304 + 178,365 + 15,180 + 990 + 44 +1 = 1,906,884

So 1,906,884 possible combinations in the 6/49 have at least one number that intersects one of the combination 01,02,03,04,05,06

-----------------------------------------------------------

Now to prove that there is a difference for whatever line chosen I will pick last week's lotto draw results which were 07 09 20 21 30 37 and repeat the above

-----------------------------------------------------

In a 6/49 draw

850,668 combinations of the possible 13,983,816 combinations have ball 7 as the lowest ball

731,120 combinations of the possible 13,983,816 combinations have ball 9 as the 2nd ball

624,834 combinations of the possible 13,983,816 combinations have ball 20 as the 3rd ball

430,920 combinations of the possible 13,983,816 combinations have ball 21 as the 4th ball

451,269 combinations of the possible 13,983,816 combinations have ball 30 as the 5th ball

376,992 combination of the possible 13,983,816 combinations have ball 37 as the 6th ball

850,668 + 731,120 + 624,834 + 430,920 + 451,269 + 376,992 = 3,465,803

So 3,465,803 possible combinations in the 6/49 have at least one number that intersects one of the combination 07,09,20,21,30,37

-----------------------------------------------------------

By changing the numbers from 1,2,3,4,5,6 to 7,9,20,21,30,37 we have increased the odds of intersecting a single number by 1,558,919 to 1

We can go further and do the same for two ball combinations, however this gets a little more complex in the approach as instead of 6 ball positions we now have 15 possible pair positions to deal with, (6 numbers break into 15 pairs

1 2|1 3|1 4|1 5|1 6|2 3|2 4|2 5|2 6|3 4|3 5|3 6|4 5|4 6|5 6

In a 6/49 draw

01: 178,365 combinations of the possible 13,983,816 combinations have ball pair 1 2 at position 1 2

02: 15180 combinations of the possible 13,983,816 combinations have ball pair 1 3 at position 1 3

03: 990 combinations of the possible 13,983,816 combinations have ball pair 1 4 at position 1 4

04: 44 combinations of the possible 13,983,816 combinations have ball pair 1 5 at position 1 5

05: 1 combinations of the possible 13,983,816 combinations have ball pair 1 6 at position 1 6

06: 15,180 combinations of the possible 13,983,816 combinations have ball pair 2 3 at position 2 3

07: 990 combinations of the possible 13,983,816 combinations have ball pair 2 4 at position 2 4

08: 44 combinations of the possible 13,983,816 combinations have ball pair 2 5 at position 2 5

09: 1 combination of the possible 13,983,816 combinations have ball pair 2 6 at position 2 6

10: 990 combinations of the possible 13,983,816 combinations have ball pair 3 4 at position 3 4

11: 44 combinations of the possible 13,983,816 combinations have ball pair 3 5 at position 3 5

12: 1 combinations of the possible 13,983,816 combinations have ball pair 3 6 at position 3 6

13: 44 combinations of the possible 13,983,816 combinations have ball pair 4 5 at position 4 5

14: 1 combinations of the possible 13,983,816 combinations have ball pair 4 6 at position 4 6

15: 1 combinations of the possible 13,983,816 combinations have ball pair 5 6 at position 5 6

178,365+15180 +990 +44 +1+15,180 +990 +44+1 +990 +44 +1+44 +1 +1 = 211,876

So 211,876 combinations in the 6/49 have two numbers that intersects one of the possible 15 pairs found in the combination 01,02,03,04,05,06

-----------------------------------------------------------

Again repeat for last week's numbers

In a 6/49 draw

01: 178,365 combinations of the possible 13,983,816 combinations have ball pair 7 9 at position 1 2

02: 15,180 combinations of the possible 13,983,816 combinations have ball pair 7 20 at position 1 3

03: 990 combinations of the possible 13,983,816 combinations have ball pair 7 21 at position 1 4

04: 44 combinations of the possible 13,983,816 combinations have ball pair 7 30 at position 1 5

05: 1 combinations of the possible 13,983,816 combinations have ball pair 7 37 at position 1 6

06: 29,232 combinations of the possible 13,983,816 combinations have ball pair 9 20 at position 2 3

07: 33,264 combinations of the possible 13,983,816 combinations have ball pair 9 21 at position 2 4

08: 28,880 combinations of the possible 13,983,816 combinations have ball pair 9 30 at position 2 5

09: 23,400 combinations of the possible 13,983,816 combinations have ball pair 9 37 at position 2 6

10: 64,638 combinations of the possible 13,983,816 combinations have ball pair 20 21 at position 3 4

11: 29,241 combinations of the possible 13,983,816 combinations have ball pair 20 30 at position 3 5

12: 20,520 combinations of the possible 13,983,816 combinations have ball pair 20 37 at position 3 6

13: 21,660 combinations of the possible 13,983,816 combinations have ball pair 21 30 at position 4 5

14: 17,100 combinations of the possible 13,983,816 combinations have ball pair 21 37 at position 4 6

15: 4,845 combinations of the possible 13,983,816 combinations have ball pair 30 37 at position 5 6

178,365 +15,180 +990 +44 +1 +29,232 +33,264 +28,880 +23,400+64,638 +29,241 +20,520 +21,660 +17,100 +4,845 =467,360

So 467,360 possible combinations in the 6/49 have two numbers that intersects one of possible 15 pairs found in the combination 7,9,20,21,30,37

By changing the numbers from 1,2,3,4,5,6 to 7,9,20,21,30,37 we have increased the odds of intersecting a pair by 255,484 to 1

So to cap this up, the lines you choose do appear to change the odds however

And a big However

Each pair appears the same number of times in the total combinations

Just different amounts in different ticket positions.

The fact is that in the 6/49 draw

Each 2 ball combo appears a total of 178,365 times

Each 3 ball combo appears a total of 15,180 times (1 in 56.6559)

Each 4 ball combo appears a total of 990 times (1 in 1,032.4)

Each 5 ball combo appears a total of 44 times (1 in 55,491.3)

Each 6 ball combo appears once 1: (1 in 13,983,816)

So the conclusion here is shuffling numbers about increases odds on some combinations but then in the same instance decreases the combinations in other ticket positions.

Always leaveing the overall odds unchanged.

Here is a small snippet taken from LSA that shows each 2 ball combo positions in a 6/49 draw, note they all add up to 178,365

1=1 2 = 178,365 0 0 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365
2=1 3 = 163,185 15,180 0 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365
3=1 4 = 148,995 28,380 990 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365
4=1 5 = 135,751 39,732 2,838 44 0 0 0 0 0 0 0 0 0 0 0 = 178,365
5=1 6 = 123,410 49,364 5,418 172 1 0 0 0 0 0 0 0 0 0 0 = 178,365
6=1 7 = 111,930 57,400 8,610 420 5 0 0 0 0 0 0 0 0 0 0 = 178,365
7=1 8 = 101,270 63,960 12,300 820 15 0 0 0 0 0 0 0 0 0 0 = 178,365
8=1 9 = 91,390 69,160 16,380 1,400 35 0 0 0 0 0 0 0 0 0 0 = 178,365
9=1 10 = 82,251 73,112 20,748 2,184 70 0 0 0 0 0 0 0 0 0 0 = 178,365
10=1 11 = 73,815 75,924 25,308 3,192 126 0 0 0 0 0 0 0 0 0 0 = 178,365
11=1 12 = 66,045 77,700 29,970 4,440 210 0 0 0 0 0 0 0 0 0 0 = 178,365
12=1 13 = 58,905 78,540 34,650 5,940 330 0 0 0 0 0 0 0 0 0 0 = 178,365
13=1 14 = 52,360 78,540 39,270 7,700 495 0 0 0 0 0 0 0 0 0 0 = 178,365
14=1 15 = 46,376 77,792 43,758 9,724 715 0 0 0 0 0 0 0 0 0 0 = 178,365
15=1 16 = 40,920 76,384 48,048 12,012 1,001 0 0 0 0 0 0 0 0 0 0 = 178,365
16=1 17 = 35,960 74,400 52,080 14,560 1,365 0 0 0 0 0 0 0 0 0 0 = 178,365

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: January 9, 2013, 5:23 am - IP Logged

Hello, good job telling, wonder how likely a lottery 49/6
Repeat the same draw (six figures) in 5 or more draws followed?
Revelator an example = the number 01, to match the 02 has only a number
Now to match any other has 47 numbers fighting or competing
With the number 02, then recapiturando, 01, one to 02 numbers for the remaining 47 chance
Then a chance competing against 47, we have to focus on the 80% and not 20%, the frequency of these low standards, is very small

bgonÃ§alves
Brasil
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 Posted: January 9, 2013, 7:57 am - IP Logged

Hello, developer, can help me on this idea, to build a vtrac for 49/6
Entao1 vtrac = 01.25 º
2 = 02.26 vtrac
Until the 24th vtrac = 24.48,
So it was with pairs vtrac 24, but the problem are the positions
Example vtrac number 1 = 01,25, ie the number 01 is the 1st position, but his pair mate, the number 25, provalmente will be the 3rd or 4th position, must see this conflict when together a pair of vtrac to 49 / 6, can you help me? thank you

Somerset
United Kingdom
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December 17, 2004
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 Posted: January 9, 2013, 3:38 pm - IP Logged

Hello, developer, can help me on this idea, to build a vtrac for 49/6
Entao1 vtrac = 01.25 º
2 = 02.26 vtrac
Until the 24th vtrac = 24.48,
So it was with pairs vtrac 24, but the problem are the positions
Example vtrac number 1 = 01,25, ie the number 01 is the 1st position, but his pair mate, the number 25, provalmente will be the 3rd or 4th position, must see this conflict when together a pair of vtrac to 49 / 6, can you help me? thank you

List the pairs and I will give you the stats.

I can also give the same stats on 3, 4,5 or 6 combo for any size pool lotto.

Jamie

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

bgonÃ§alves
Brasil
Member #92564
June 9, 2010
2080 Posts
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 Posted: January 9, 2013, 8:13 pm - IP Logged

List the pairs and I will give you the stats.

I can also give the same stats on 3, 4,5 or 6 combo for any size pool lotto.

Jamie

ok

01 25

02 26

03 27

04 28

05 29

06 30

07 31

08 32

09 33

10 34

11 35

12 36

13 37

14 38

15 39

16 40

17 41

18 42

19 43

20 44

21 45

22 46

23 47

24 48,49

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: January 10, 2013, 1:48 pm - IP Logged
Hello, developer, I also need this research will form blocks of 49/6
With peers, a couple followed example 01.02 another pair with 26 5 31 delta
Are looks like 01.02 .26 .31, this is the default, the pair of delta can vary from 2, 18
The pair followed by the 6/49 are
01.02 02.03 04.05 06.07 08.09 10.11 12.13 14.15 16.17 18.19 20.21 22.23
24.25 26.27 28.29 30.31 32.33 34.35 36.37 38.39 40.41 42.43 44.45 46.47
48.49, good these are couples followed in sequence of 1 (one) the other pair
And as the definition of the delta to assemble the couple, there will be blocks from 49/6,
The other two missing numbers to complete the wager is random
bgonÃ§alves
Brasil
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 Posted: January 10, 2013, 2:07 pm - IP Logged

Hello developer, I forgot this standard example
In the draw 49/6 = 01,02,06,16 gave 21.39
Note that the pair 06.16 is also one sequence when seen in the vertical column
In an array 10 rows and five columns, such as 49 to take a number
Then we have the sequences online and in columns

Somerset
United Kingdom
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December 17, 2004
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 Posted: January 10, 2013, 5:24 pm - IP Logged

ok

01 25

02 26

03 27

04 28

05 29

06 30

07 31

08 32

09 33

10 34

11 35

12 36

13 37

14 38

15 39

16 40

17 41

18 42

19 43

20 44

21 45

22 46

23 47

24 48,49

 01 25 24=1   25-10626|46552|69828|42504|8855|0|0|0|0|0|0|0|0|0|0 02 26 72=2 26-8855|40733|64009|40733|8855|1771|5819|5819|1771|0|0|0|0|0|0 03 27 119=3   27-7315|35420|58443|38962|8855|3080|10626|11132|3542|231|506|253|0|0|0 04 28 165=4   28-5985|30590|53130|37191|8855|3990|14490|15939|5313|630|1449|759|21|23|0 05 29 210=5   29-4845|26220|48070|35420|8855|4560|17480|20240|7084|1140|2760|1518|80|92|1 06 30 254=6   30-3876|22287|43263|33649|8855|4845|19665|24035|8855|1710|4370|2530|190|230|5 07 31 297=7   31-3060|18768|38709|31878|8855|4896|21114|27324|10626|2295|6210|3795|360|460|15 08 32 339=8   32-2380|15640|34408|30107|8855|4760|21896|30107|12397|2856|8211|5313|595|805|35 09 33 380=9   33-1820|12880|30360|28336|8855|4480|22080|32384|14168|3360|10304|7084|896|1288|70 10 34 420=10   34-1365|10465|26565|26565|8855|4095|21735|34155|15939|3780|12420|9108|1260|1932|126 11 35 459=11   35-1001|8372|23023|24794|8855|3640|20930|35420|17710|4095|14490|11385|1680|2760|210 12 36 497=12   36-715|6578|19734|23023|8855|3146|19734|36179|19481|4290|16445|13915|2145|3795|330 13 37 534=13   37-495|5060|16698|21252|8855|2640|18216|36432|21252|4356|18216|16698|2640|5060|495 14 38 570=14   38-330|3795|13915|19481|8855|2145|16445|36179|23023|4290|19734|19734|3146|6578|715 15 39 605=15   39-210|2760|11385|17710|8855|1680|14490|35420|24794|4095|20930|23023|3640|8372|1001 16 40 639=16   40-126|1932|9108|15939|8855|1260|12420|34155|26565|3780|21735|26565|4095|10465|1365 17 41 672=17   41-70|1288|7084|14168|8855|896|10304|32384|28336|3360|22080|30360|4480|12880|1820 18 42 704=18   42-35|805|5313|12397|8855|595|8211|30107|30107|2856|21896|34408|4760|15640|2380 19 43 735=19   43-15|460|3795|10626|8855|360|6210|27324|31878|2295|21114|38709|4896|18768|3060 20 44 765=20   44-5|230|2530|8855|8855|190|4370|24035|33649|1710|19665|43263|4845|22287|3876 21 45 794=21   45-1|92|1518|7084|8855|80|2760|20240|35420|1140|17480|48070|4560|26220|4845 22 46 822=22   46-0|23|759|5313|8855|21|1449|15939|37191|630|14490|53130|3990|30590|5985 23 47 849=23   47-0|0|253|3542|8855|0|506|11132|38962|231|10626|58443|3080|35420|7315 24 48 875=24 48-0|0|0|1771|8855|0|0|5819|40733|0|5819|64009|1771|40733|8855 25 49 900=25 49-0|0|0|0|8855|0|0|0|42504|0|0|69828|0|46552|10626

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

Somerset
United Kingdom
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December 17, 2004
182 Posts
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 Posted: January 10, 2013, 5:46 pm - IP Logged

Just a note on the last post, the data is as follows

900=25 49-0|0|0|0|8855|0|0|0|42504|0|0|69828|0|46552|10626

Line | Pair |

XX0000 = 25 49 never appears in position one in the 6/49

X0X000 = 25 49 never appears in position two in the 6/49

X00X00 = 25 49 never appears in position three in the 6/49

X000X0 = 25 49 never appears in position four in the 6/49

X0000X = 25 49 appears in position five 8855 times in the 6/49

0XX000 and so on

0X0X00

0X00X0

0X000X

00XX00

00X0X0

00X00X

000XX0

000X0X

0000XX

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

bgonÃ§alves
Brasil
Member #92564
June 9, 2010
2080 Posts
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 Posted: January 10, 2013, 5:50 pm - IP Logged

Ok, developer, very good job, the idea is to see the example par vtrac
01.25 the best position and the best position for 01 to 25, and so with the other pairs

Somerset
United Kingdom
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 Posted: January 10, 2013, 6:43 pm - IP Logged

Dr San - I have been thinking about this VTRAC system, bearing in mind I have not read up on it so could be wrong but from what you have explained in this post I see a floor in the system.

Say you have the pair 1 2 and you have made your system based upon this.

The math is only correct until the first number is drawn, at that point it all falls over as effectively at that point in time you're playing a 5/48 draw not a 6/49

So with a 6/49 the pair 1 2 appears 178,365 times

Now let's say the first ball drawn is ball number 1 to keep this as simple as possible, what then happens to the system?.

This would then leave the remaining combinations from a game of 5/48

2=1 3-14190|990|0|0|0|0|0|0|0|0

3=1 4-13244|1892|44|0|0|0|0|0|0|0

4=1 5-12341|2709|129|1|0|0|0|0|0|0

5=1 6-11480|3444|252|4|0|0|0|0|0|0

6=1 7-10660|4100|410|10|0|0|0|0|0|0

7=1 8-9880|4680|600|20|0|0|0|0|0|0

8=1 9-9139|5187|819|35|0|0|0|0|0|0

9=1 10-8436|5624|1064|56|0|0|0|0|0|0

10=1 11-7770|5994|1332|84|0|0|0|0|0|0

11=1 12-7140|6300|1620|120|0|0|0|0|0|0

12=1 13-6545|6545|1925|165|0|0|0|0|0|0

13=1 14-5984|6732|2244|220|0|0|0|0|0|0

14=1 15-5456|6864|2574|286|0|0|0|0|0|0

15=1 16-4960|6944|2912|364|0|0|0|0|0|0

16=1 17-4495|6975|3255|455|0|0|0|0|0|0

17=1 18-4060|6960|3600|560|0|0|0|0|0|0

18=1 19-3654|6902|3944|680|0|0|0|0|0|0

19=1 20-3276|6804|4284|816|0|0|0|0|0|0

20=1 21-2925|6669|4617|969|0|0|0|0|0|0

21=1 22-2600|6500|4940|1140|0|0|0|0|0|0

22=1 23-2300|6300|5250|1330|0|0|0|0|0|0

23=1 24-2024|6072|5544|1540|0|0|0|0|0|0

24=1 25-1771|5819|5819|1771|0|0|0|0|0|0

25=1 26-1540|5544|6072|2024|0|0|0|0|0|0

26=1 27-1330|5250|6300|2300|0|0|0|0|0|0

27=1 28-1140|4940|6500|2600|0|0|0|0|0|0

28=1 29-969|4617|6669|2925|0|0|0|0|0|0

29=1 30-816|4284|6804|3276|0|0|0|0|0|0

30=1 31-680|3944|6902|3654|0|0|0|0|0|0

31=1 32-560|3600|6960|4060|0|0|0|0|0|0

32=1 33-455|3255|6975|4495|0|0|0|0|0|0

33=1 34-364|2912|6944|4960|0|0|0|0|0|0

34=1 35-286|2574|6864|5456|0|0|0|0|0|0

35=1 36-220|2244|6732|5984|0|0|0|0|0|0

36=1 37-165|1925|6545|6545|0|0|0|0|0|0

37=1 38-120|1620|6300|7140|0|0|0|0|0|0

38=1 39-84|1332|5994|7770|0|0|0|0|0|0

39=1 40-56|1064|5624|8436|0|0|0|0|0|0

40=1 41-35|819|5187|9139|0|0|0|0|0|0

41=1 42-20|600|4680|9880|0|0|0|0|0|0

42=1 43-10|410|4100|10660|0|0|0|0|0|0

43=1 44-4|252|3444|11480|0|0|0|0|0|0

44=1 45-1|129|2709|12341|0|0|0|0|0|0

45=1 46-0|44|1892|13244|0|0|0|0|0|0

46=1 47-0|0|990|14190|0|0|0|0|0|0

47=1 48-0|0|0|15180|0|0|0|0|0|0

The way I see it is that we would have to take into account that any combination that starts with the ball number one is now valid all other combinations in the 6/49 become invalid.

This then leaves you just 15,180 combinations that could possibly win, (one of the remaining 15,180 combos will be the winning combination)

So everything has now changed and in a very big way.

The way I see this is that you would have to make 4 VTRACs 6/48, 5/48, 4/47, 3/46 then create a permutation of the results to make a VTRAC wheel if you like.

Each VTRAC would depend on the higher VTRAC being accurate in its prediction or it all fails over.

So if I understand what your hoping to achieve is correct it would cost a lot of money to do correctly

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

Somerset
United Kingdom
Member #9710
December 17, 2004
182 Posts
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 Posted: January 10, 2013, 6:45 pm - IP Logged

Have you a spread sheet I could look at to understand this fully.

Thanks

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

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