|Posted: February 13, 2013, 12:51 pm - IP Logged|
Hello, help me in this idea, want to join row and column, i.e. 3 vertical and 4 horizontal and vice versa, i.e. in a 7 x 7 array I join 3 segments and mirrors, if three symmetrical segments of us are number hit = lottery 6/49
Perhaps the array below may be of some use to you. So, 3 numbers in a row, 4 numbers in a column. And since 7 * 4 is more than 7 * 3, 2 and 6 columns sacrifize you, once you least like these two numbers in a row.
I believe that this mirror array and is together cover all 10 combinations of different numbers of 2 and 6:0 pm its first six lines. That is, 12 lines with eight mirror and 4 combinations containing two lines repeated only (symmetrical) combinations. The last line contains the number 6 (mirror 2). Hope this helps with your problem.
To cover all 35, I don't know if you can compose five such arrays. It would be a lot of work to try to (if you don't know any formula to help you, what not to do). But certainly can't be with arrays of mirror, since there are five of them, then at least one of them must mirror themselves. But there are ony 3 combinatios only, not seven.