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Last digits for Sweet Million New York

Topic closed. 15 replies. Last post 4 years ago by LottoBoner.

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Economy class
Belgium
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February 27, 2012
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 Posted: May 19, 2013, 4:46 pm - IP Logged

Pick 6, 40 numbers, the occurences

3838380 combinations

 pct.\ld ld ld ld ld ld ld 0,014% 4 2 0,150% 4 1 1 0,019% 3 3 1,801% 3 2 1 5,602% 3 1 1 1 0,675% 2 2 2 18,908% 2 2 1 1 50,421% 2 1 1 1 1 22,409% 1 1 1 1 1 1

Explanation for the table: first row, 4 ld's x with 2 ld's y, happen 0.014 percent of the time.
Half of the time you find two same last digits and all the other last digits are distinct.

The percentages were mathematically calculated, not computered.

NY State
United States
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June 10, 2010
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 Posted: May 19, 2013, 6:07 pm - IP Logged

Pick 6, 40 numbers, the occurences

3838380 combinations

 pct.\ld ld ld ld ld ld ld 0,014% 4 2 0,150% 4 1 1 0,019% 3 3 1,801% 3 2 1 5,602% 3 1 1 1 0,675% 2 2 2 18,908% 2 2 1 1 50,421% 2 1 1 1 1 22,409% 1 1 1 1 1 1

Explanation for the table: first row, 4 ld's x with 2 ld's y, happen 0.014 percent of the time.
Half of the time you find two same last digits and all the other last digits are distinct.

The percentages were mathematically calculated, not computered.

Good to know information Serge.  Thanks!

I'll definitely play two numbers on my lines that have the same last digit.

Am I correct in assuming that single digit numbers (0,1,2,3,4,5,6,7,8, & 9) were used in your calculations?

In other words, the last digit in the number 2, is 2.

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: May 19, 2013, 6:32 pm - IP Logged

Hello, give, you can use as if it were two endings in pick3 (final digit of the number 0-9) oo fanstastico. It has the same difficulties and weak point, as if it were
A pick3, although the drawing is with all balls joints, then a good system
And pairs or three digits pick3, can be used to predict, since apart from the front of the number, ranging from 0 to 4, and has positions (and when viewed mounted or increasing order)
Tai to see a good system, 40/6 into two parts (initial and final digit digit)

United States
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July 25, 2012
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 Posted: May 19, 2013, 11:22 pm - IP Logged

Good to know information Serge.  Thanks!

I'll definitely play two numbers on my lines that have the same last digit.

Am I correct in assuming that single digit numbers (0,1,2,3,4,5,6,7,8, & 9) were used in your calculations?

In other words, the last digit in the number 2, is 2.

Yes, the last digit of the number 2 is 2.  But no, Serge is not talking about just single-digit numbers 0 through 9.  He is talking about a 6/40 lotto game (like NY Sweet Million, as his subject lines says) where we choose any 6 from 1 through 40.  So the group 10,20,30,40 all end in 0; 1,11,21,31 all end in 1; 2,21,22,32 all end in 2, etc.  Note that all 5 groups have 4 elements.  That makes the combinatorial calculation relatively easy.

I think a 6/49 lotto is more common; but the relative percentages are similar.  And I prefer to show the actual number of combinations as well as percentages, for those who prefer to avoid any rounding error.  See the table below.

6/40 Lotto                          6/49 Lotto
5+1                                                                          396        0.0028%
4+2                              540      0.014%                 3,960        0.0283%
4+1+1                       5,760      0.150%               39,600        0.2832%
3+3                              720      0.019%                 3,960        0.0283%
3+2+1                     69,120      1.801%             316,800        2.2655%
3+1+1+1               215,040      5.602%             924,000        6.6076%
2+2+2                     25,920      0.675%             105,600        0.7552%
2+2+1+1               725,760    18.908%          2,772,000      19.8229%
2+1+1+1+1        1,935,360    50.421%          6,930,000      49.5573%
1+1+1+1+1+1       860,160    22.409%          2,887,500      20.6489%
TOTAL                  3,838,380    99.999%        13,983,816    100.0000%

(Compare the totals with COMBIN(40,6) and COMBIN(49,6) in Excel.)

Note that a 6/49 lotto has an additional pattern, 5+1; that is, 5 numbers with the same last digit, and 1 number with a different last digit.  Also, note that the group 10,20,30,40 has 4 elements, but the other groups have 5 elements (e.g. 1,11,21,31,41).  That makes little difference for players; but it makes the combinatorial calculation more interesting.

My numbers are also "mathematically calculated", not counted by an exhaustive computer algorithm.  But I don't know what difference that makes.  Both are equally good methods, IMHO.

If anyone is interested in the combinatorial calculation, I would be happy to post some examples or the complete set.  Or see the calculations described in http://www.lotterypost.com/thread/255827/2904841.  They are for "poker" patterns; but it might give you some idea of the calculation.  Also see the caveat about how to use such patterns ("It is tempting to think ...").

(Note:  In that posting, I believe I use terms like "quad" differently from what is common among lotto aficionados.  I mean:  4 numbers in the same "teen", e.g. 11,13,17,19.)

Economy class
Belgium
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February 27, 2012
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 Posted: May 20, 2013, 10:35 am - IP Logged

Yes, the last digit of the number 2 is 2.  But no, Serge is not talking about just single-digit numbers 0 through 9.  He is talking about a 6/40 lotto game (like NY Sweet Million, as his subject lines says) where we choose any 6 from 1 through 40.  So the group 10,20,30,40 all end in 0; 1,11,21,31 all end in 1; 2,21,22,32 all end in 2, etc.  Note that all 5 groups have 4 elements.  That makes the combinatorial calculation relatively easy.

I think a 6/49 lotto is more common; but the relative percentages are similar.  And I prefer to show the actual number of combinations as well as percentages, for those who prefer to avoid any rounding error.  See the table below.

6/40 Lotto                          6/49 Lotto
5+1                                                                          396        0.0028%
4+2                              540      0.014%                 3,960        0.0283%
4+1+1                       5,760      0.150%               39,600        0.2832%
3+3                              720      0.019%                 3,960        0.0283%
3+2+1                     69,120      1.801%             316,800        2.2655%
3+1+1+1               215,040      5.602%             924,000        6.6076%
2+2+2                     25,920      0.675%             105,600        0.7552%
2+2+1+1               725,760    18.908%          2,772,000      19.8229%
2+1+1+1+1        1,935,360    50.421%          6,930,000      49.5573%
1+1+1+1+1+1       860,160    22.409%          2,887,500      20.6489%
TOTAL                  3,838,380    99.999%        13,983,816    100.0000%

(Compare the totals with COMBIN(40,6) and COMBIN(49,6) in Excel.)

Note that a 6/49 lotto has an additional pattern, 5+1; that is, 5 numbers with the same last digit, and 1 number with a different last digit.  Also, note that the group 10,20,30,40 has 4 elements, but the other groups have 5 elements (e.g. 1,11,21,31,41).  That makes little difference for players; but it makes the combinatorial calculation more interesting.

My numbers are also "mathematically calculated", not counted by an exhaustive computer algorithm.  But I don't know what difference that makes.  Both are equally good methods, IMHO.

If anyone is interested in the combinatorial calculation, I would be happy to post some examples or the complete set.  Or see the calculations described in http://www.lotterypost.com/thread/255827/2904841.  They are for "poker" patterns; but it might give you some idea of the calculation.  Also see the caveat about how to use such patterns ("It is tempting to think ...").

(Note:  In that posting, I believe I use terms like "quad" differently from what is common among lotto aficionados.  I mean:  4 numbers in the same "teen", e.g. 11,13,17,19.)

The sum of the relative chances shows a difference of 1/10000 due to the precision.

The groups of last digits for Sweet Million are distinct quads.

The combinatorial calculation is not that easy for everyone.

Last digits can be perceived without programming.

This makes a huge difference for the player.

6/49 is not perfect for last digit, so you are not allowed to compare 6/49 to 6/40.

If you want to compare the calculation to pick 3, you have to think boxed as in lotto the order does not matter for the payout.

Comparable lotto games are x/20, x/30, x/40, ... x/80.

Economy class
Belgium
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February 27, 2012
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 Posted: May 20, 2013, 11:01 am - IP Logged

Good to know information Serge.  Thanks!

I'll definitely play two numbers on my lines that have the same last digit.

Am I correct in assuming that single digit numbers (0,1,2,3,4,5,6,7,8, & 9) were used in your calculations?

In other words, the last digit in the number 2, is 2.

The last digit is called final at roulette.

The last digit of a number with length one is the number itself.

Dallas, Texas
United States
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May 2, 2004
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 Posted: May 20, 2013, 12:48 pm - IP Logged

Kudos SergeM! This is, without doubt, the most interesting idea I've seen on Lottery Post in quite some time.

My hats off to you. It som impressed me I went ahead and worked it out for the Texas 2Step. The left side of the chart is the hits in the overall 4/35 matrix. Under Pos X denotes a hit; 0 denotes a miss.

The right side of the chart is the same for the actual drawings. The totals are below the chart. NOTE: To say Quads 5 hits make up .01% is stretching it a bit. The percentage is more like 0.0000954%. Of course, Excel rounds up to the nearest two decimal places.

We can see the drawings are following the matrix. Trips should hit 1 to 2 times per 100. Pairs should hit 37 to 38 times per hundred. Good information to know when choosing back digits.

Now to work up a hit and skip chart.

Thanks you, Sir! Very insightful! Very worthwhile (to me at least).

G

(Crap! LP gremlins strike again. Meant to give you 5 STARS for this.  Sorry!)

My greatest accomplishment is teaching cats about Vienna Sausage. When I need a friend, all I need do is walk outside, pop open a can, and every little critter in the neighborhood drops by to say "Hi!"

Economy class
Belgium
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February 27, 2012
4035 Posts
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 Posted: May 20, 2013, 1:36 pm - IP Logged

Kudos SergeM! This is, without doubt, the most interesting idea I've seen on Lottery Post in quite some time.

My hats off to you. It som impressed me I went ahead and worked it out for the Texas 2Step. The left side of the chart is the hits in the overall 4/35 matrix. Under Pos X denotes a hit; 0 denotes a miss.

The right side of the chart is the same for the actual drawings. The totals are below the chart. NOTE: To say Quads 5 hits make up .01% is stretching it a bit. The percentage is more like 0.0000954%. Of course, Excel rounds up to the nearest two decimal places.

We can see the drawings are following the matrix. Trips should hit 1 to 2 times per 100. Pairs should hit 37 to 38 times per hundred. Good information to know when choosing back digits.

Now to work up a hit and skip chart.

Thanks you, Sir! Very insightful! Very worthwhile (to me at least).

G

(Crap! LP gremlins strike again. Meant to give you 5 STARS for this.  Sorry!)

You could work out the chart positionally by order of drawing or order low to high, as offered by Texas lottery.

For 35 numbers you have the same problem as for 49 numbers, it has a rest after division by ten.

If I get a rating of less than five stars by OnlyMoney, I will stop posting for a year at least.

If any comment is deleted again, I do the same. Some people here have sensible toes.

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: May 20, 2013, 4:52 pm - IP Logged

Hello, mathead, who look at this example initial and final digit
Initial digits of 49/6 = 0,1,2,3,4 initial digits
Agoral the last digit high = 5,6,7,8,9, usually a 49/6 we have two digits in this
High group last digit = 5,6,7,8,9
Example 466 = 20,24,40,43,48,45 sweepstakes in the last digit given high 5.8 (two digits)
The other initial and end to complete the number given within 0,1,2,3,4
20,24,40,43, then we have 4 numbers within 0,1,2,3,4, two high = 5.8
In total the draw = 466 had six digits (adding the digits start and end)
So we have to see how many numbers of the combination should be at 0,1,2,3,4, with two of the
High 5,6,7,8,9, uam to give good reduction and see the ups 5,6,7,8,9, arrears ok.
Or filters, not to cross 0,1,2,3,4 all this with only two other group 5,6,7,8,9
(Sometimes this group of 3 digits high).

bgonÃ§alves
Brasil
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 Posted: May 20, 2013, 5:07 pm - IP Logged

Hello, mathead, who look at this example initial and final digit
Initial digits of 49/6 = 0,1,2,3,4 initial digits
Agoral the last digit high = 5,6,7,8,9, usually a 49/6 we have two digits in this
High group last digit = 5,6,7,8,9
Example 466 = 20,24,40,43,48,45 sweepstakes in the last digit given high 5.8 (two digits)
The other initial and end to complete the number given within 0,1,2,3,4
20,24,40,43, then we have 4 numbers within 0,1,2,3,4, two high = 5.8
In total the draw = 466 had six digits (adding the digits start and end)
So we have to see how many numbers of the combination should be at 0,1,2,3,4, with two of the
High 5,6,7,8,9, uam to give good reduction and see the ups 5,6,7,8,9, arrears ok.
Or filters, not to cross 0,1,2,3,4 all this with only two other group 5,6,7,8,9
(Sometimes this group of 3 digits high).

Hello, below the array with the numbers of the 25 digit combination of initial and final
0,1,2,3,4
0 0
0 1
0 2
0 3
0 4
1 0
1 1
1 2
1 3
1 4
2 0
2 1
2 2
2 3
2 4
3 0
3 1
3 2
3 3
3 4
4 0
4 1
4 2
4 3
4 4
Sometimes a sweepstakes of two consecutive sample = 12.13 or 33.34, here needs filters, not to play with the numbers 25, two or three clear lack of high 5,6,7,8,9
But we have a good base reduction

bgonÃ§alves
Brasil
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 Posted: May 20, 2013, 5:45 pm - IP Logged

Hello, for those who die in Pennsylvania, and the lottery game 39/5
The matrix 0,1,2,3
It = 16 numbers =
0 0
0 1
0 2
0 3
1 0
1 1
1 2
1 3
2 0
2 1
2 2
2 3
3 0
3 1
3 2
3 3
Of course the lack of a two-digit high = 5,6,7,8,9
Sometimes the numbers in sequence = 22.23 or 31.32. Etc. ..
You can see the ups = 5,6,7,8,9 late now to filter out 16 numbers
From = 0,1,2,3, can use pairs in delays, and other filters. if you win remember me please. thank you

NY State
United States
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 Posted: May 20, 2013, 8:27 pm - IP Logged

I made a spreadsheet in Excel that shows how many times any given pair of last digit numbers were drawn together.  Unfortunately I cant get it into The Lottery Post without it losing all of it's formatting.  When I pasted it in here, it became scrambled and becomes usless.  I made the spreadsheet for all drawings of Sweet Million since it began in September 2009.

But I can tell you that the 9/39 pair is the top pair, having been drawn together fifteen times.

Here's the first section of the spreadsheet

1     11   21  31

1      X

11    8     X

21    7     6     X

31    7     7     6     X

1 paired withh 11 eight times, it paired with 21 seven times, and it paired with 31 seven times.

I dont know if anyone will find this helpful or not, but I thought I'd go ahead and post it anyway.

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

Economy class
Belgium
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 Posted: May 21, 2013, 12:30 pm - IP Logged
 0 2 3 15 18 21 29 1 1 7 14 17 38 40 2 4 6 10 23 34 35 3 19 24 32 4 11 22 26 5 5 6 8 30 7 9 13 25 33 8 16 28 9 39 10 11 31 12 12 13 27 14 15 36 16 17 20 18 37

Economy class
Belgium
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February 27, 2012
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 Posted: May 21, 2013, 7:49 pm - IP Logged

I made a spreadsheet in Excel that shows how many times any given pair of last digit numbers were drawn together.  Unfortunately I cant get it into The Lottery Post without it losing all of it's formatting.  When I pasted it in here, it became scrambled and becomes usless.  I made the spreadsheet for all drawings of Sweet Million since it began in September 2009.

But I can tell you that the 9/39 pair is the top pair, having been drawn together fifteen times.

Here's the first section of the spreadsheet

1     11   21  31

1      X

11    8     X

21    7     6     X

31    7     7     6     X

1 paired withh 11 eight times, it paired with 21 seven times, and it paired with 31 seven times.

I dont know if anyone will find this helpful or not, but I thought I'd go ahead and post it anyway.

 1 8 11 11 6 21 7 7 6 31

...

United States
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March 14, 2012
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 Posted: May 27, 2013, 4:41 pm - IP Logged
 11 4's 3's 1 1 2 3's 3 1 4 2 4's 3 1 4 2 5 3 6 4 3's 5 1 6 2 7 3 8 4 9 5 4's 6 1 7 2 8 3 3's 4 1 5 3's 4's 1 1 3's 2 1 4's 2 1 3 2 3's 3♥

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