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April 11, 2006
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This is something to just try it may work for you it may not so I'm throwing sumthing out there. So here goes nothing take your last two drawings and do this.
Ex-Wisconsin
8/26-571
8/27-401
Put all nine digits in order like so 0-1-2-3-5-6-7-8-9 and then basically just cross out the digits that came in those last two draws in this example I would remove digits 5-7-1 and 4-0-1 so it leaves the digits 2-3-6-8-9 and last night's P-3 Wisconsin was 386. So not to much like tha other wonderful systems on here but its maybe worth looking at. The only potential killers of this elementary system are following factors
1. You get a 1 or 2 digit return from the last nights draw.
2. A double falls.
3. If they shut down your states lottery-just joking on this one he he.
Wisconsin United States
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February 17, 2012
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Quote: Originally posted by fashohits on Aug 29, 2013
This is something to just try it may work for you it may not so I'm throwing sumthing out there. So here goes nothing take your last two drawings and do this.
Ex-Wisconsin
8/26-571
8/27-401
Put all nine digits in order like so 0-1-2-3-5-6-7-8-9 and then basically just cross out the digits that came in those last two draws in this example I would remove digits 5-7-1 and 4-0-1 so it leaves the digits 2-3-6-8-9 and last night's P-3 Wisconsin was 386. So not to much like tha other wonderful systems on here but its maybe worth looking at. The only potential killers of this elementary system are following factors
1. You get a 1 or 2 digit return from the last nights draw.
2. A double falls.
3. If they shut down your states lottery-just joking on this one he he.
United States
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April 11, 2006
341 Posts
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Quote: Originally posted by Nikkicute on Sep 1, 2013
Wow, that really is non-complex lol
Have you won anything playing this way?
Thanks for taking a look and no I could have won using the example I showed I played 683 Straight that night and it was 386. I was pretty mad but that's usually how it goes if i' m not one number off I usually have the number but I play it wrong. Have you tried it yet I actually made a typo when I showed the workout I left out the 4 it was supposed to be 0-1-2-3-4-5-6-7-8-9
8/26-571
8/27-401 eliminate those digits and you have digits 2-3-6-8-9 like I said O played 683 and it was 386.
So test it out and if you have any success let me know.
wisconsin United States
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January 28, 2007
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Numbers were 571 and 401 . The numbers that wasm\n't played was 2-3-6-8-9 . Number called 386 . They have been so crazy with the numbers in Aug. looks like it only worked that time and for the 10th when the 472 was played. will backtest it some more. Interesting thou. Thanks
United States
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April 11, 2006
341 Posts
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Yeah they have hope we have more luck this month if I see anything I will let you know
what games interest you. I track p-3 and supercash mainly sometimes p-4 to many doubles for me.
United States
Member #116,339
September 8, 2011
5,092 Posts
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Quote: Originally posted by fashohits on Aug 29, 2013
This is something to just try it may work for you it may not so I'm throwing sumthing out there. So here goes nothing take your last two drawings and do this.
Ex-Wisconsin
8/26-571
8/27-401
Put all nine digits in order like so 0-1-2-3-5-6-7-8-9 and then basically just cross out the digits that came in those last two draws in this example I would remove digits 5-7-1 and 4-0-1 so it leaves the digits 2-3-6-8-9 and last night's P-3 Wisconsin was 386. So not to much like tha other wonderful systems on here but its maybe worth looking at. The only potential killers of this elementary system are following factors
1. You get a 1 or 2 digit return from the last nights draw.
2. A double falls.
3. If they shut down your states lottery-just joking on this one he he.
All comments and suggestion are welcome.
Thanks In Advance!
Good Luck!
Peace Fashohits
Maybe you might randomize 0-9 before removing the 2 draws. Use this random chart,maybe, just maybe:
R
random sequence
1
8-3-9-6-4-7-0-2-5-1
2
0-3-6-2-5-7-9-1-4-8
3
3-4-1-0-9-2-5-8-6-7
4
9-5-0-3-6-8-2-1-4-7
5
7-5-2-8-9-1-6-0-4-3
6
0-8-3-6-1-5-4-9-2-7
7
6-8-5-2-3-4-1-9-0-7
8
5-7-1-3-6-4-2-0-9-8
9
7-2-6-9-8-1-3-4-5-0
10
2-1-3-6-7-9-8-5-0-4
Lets remove 2 draws 57140 from Randoms(R) 1, 2, 3 ......
From R1>83962> 839-836-832-396-392-962
R2>36298> 362-369-368-628-629-298
R3>39286>392-398-396-928-926-286
NB: You do not have to use all R1 to R2, two r is will suffice.See how the pattern plays, I will out first digits of reduced R as key for combo, ie 8, 3,3 (R1,R2,R3). Most of the picks will be repeats in different form(reduced permutation you may say). Your ideal is nice, but the event is not linear 12345.......
United States
Member #37,169
April 11, 2006
341 Posts
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Quote: Originally posted by adobea78 on Sep 2, 2013
Maybe you might randomize 0-9 before removing the 2 draws. Use this random chart,maybe, just maybe:
R
random sequence
1
8-3-9-6-4-7-0-2-5-1
2
0-3-6-2-5-7-9-1-4-8
3
3-4-1-0-9-2-5-8-6-7
4
9-5-0-3-6-8-2-1-4-7
5
7-5-2-8-9-1-6-0-4-3
6
0-8-3-6-1-5-4-9-2-7
7
6-8-5-2-3-4-1-9-0-7
8
5-7-1-3-6-4-2-0-9-8
9
7-2-6-9-8-1-3-4-5-0
10
2-1-3-6-7-9-8-5-0-4
Lets remove 2 draws 57140 from Randoms(R) 1, 2, 3 ......
From R1>83962> 839-836-832-396-392-962
R2>36298> 362-369-368-628-629-298
R3>39286>392-398-396-928-926-286
NB: You do not have to use all R1 to R2, two r is will suffice.See how the pattern plays, I will out first digits of reduced R as key for combo, ie 8, 3,3 (R1,R2,R3). Most of the picks will be repeats in different form(reduced permutation you may say). Your ideal is nice, but the event is not linear 12345.......
Adobea 78 you are great and one of the many posters who help all of us out when we need a helping hand. I truly do commend you and all the others on here who do the same. I know my idea makes no sense but I am just trying to help out. I am lost on what you sent and it is a great puzzle that I will unravel and if you could break it down for me a little more. Thanks again for everything thing you do and share!
Numbers can be a wonderful exercise for the mind but it can get overwhelming!
Hope to hear from you and other suggestions are truly welcome
Crested Butte, CO United States
Member #69,862
January 18, 2009
1,393 Posts
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Quote: Originally posted by fashohits on Sep 1, 2013
Thanks for taking a look and no I could have won using the example I showed I played 683 Straight that night and it was 386. I was pretty mad but that's usually how it goes if i' m not one number off I usually have the number but I play it wrong. Have you tried it yet I actually made a typo when I showed the workout I left out the 4 it was supposed to be 0-1-2-3-4-5-6-7-8-9
8/26-571
8/27-401 eliminate those digits and you have digits 2-3-6-8-9 like I said O played 683 and it was 386.
So test it out and if you have any success let me know.
Good luck
In general it's not a good strategy. If a single (i.e. 6-way box) was drawn in the previous draw then their is a 71% chance that if the next draw is a single a digit will repeat from it. Since you are eliminating those digits you are playing against the odds. If the last draw was a double or trip then the odds are more in favor of your strategy.
Wisconsin United States
Member #123,284
February 17, 2012
4,929 Posts
Offline
Quote: Originally posted by jimjwright on Sep 2, 2013
In general it's not a good strategy. If a single (i.e. 6-way box) was drawn in the previous draw then their is a 71% chance that if the next draw is a single a digit will repeat from it. Since you are eliminating those digits you are playing against the odds. If the last draw was a double or trip then the odds are more in favor of your strategy.
Jimmy
Aren't we always playing against the odds?
In general it's a non-complex P3 strategy has he stated, any suggestions on how to
add numbers for when you think a repeat, double or triple is welcomed I"m sure.
United States
Member #116,339
September 8, 2011
5,092 Posts
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Quote: Originally posted by picktowin on Sep 1, 2013
Numbers were 571 and 401 . The numbers that wasm\n't played was 2-3-6-8-9 . Number called 386 . They have been so crazy with the numbers in Aug. looks like it only worked that time and for the 10th when the 472 was played. will backtest it some more. Interesting thou. Thanks
The ideal is 6C3 > 6!/3!3! for 20 picks, the reduced 23689(5C3>10 picks)236, 238, 239, 268, 269, 289, 368, 369, 389, 689 , Now follow the removal step ,see how the combos behave, meaning take 2 successive draws, do a combo with either 6c3 or 5c3, you will see repeat picks. I like your thought, is all about the punchline, not the odds!
United States
Member #37,169
April 11, 2006
341 Posts
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Quote: Originally posted by jimjwright on Sep 2, 2013
In general it's not a good strategy. If a single (i.e. 6-way box) was drawn in the previous draw then their is a 71% chance that if the next draw is a single a digit will repeat from it. Since you are eliminating those digits you are playing against the odds. If the last draw was a double or trip then the odds are more in favor of your strategy.
Jimmy
A duh can you read the title it's just something for people to try I now see why individuals who do contribute their hardwork never give all the details because it always some criticism. But constructive criticism is always good. But anyways thanks for your thoughts sir.
United States
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September 8, 2011
5,092 Posts
Offline
Quote: Originally posted by fashohits on Sep 2, 2013
Adobea 78 you are great and one of the many posters who help all of us out when we need a helping hand. I truly do commend you and all the others on here who do the same. I know my idea makes no sense but I am just trying to help out. I am lost on what you sent and it is a great puzzle that I will unravel and if you could break it down for me a little more. Thanks again for everything thing you do and share!
Numbers can be a wonderful exercise for the mind but it can get overwhelming!
Hope to hear from you and other suggestions are truly welcome
Your ideal make sense, why? is a simple proposition, see, in random events, you're aiming a PUNCHLINE, not odds, looking at so called ' normal distrubution curve' the house always win (see the prediction table from month to lifetime), your aim is the prize. Indulging in too much statics will mess your puncline, deal with what you can control. Static parameters(percentiles, sums, skips etc) are broad brushes and are best for polls, population census, not for discrete events.
United States
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September 8, 2011
5,092 Posts
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Quote: Originally posted by fashohits on Sep 2, 2013
A duh can you read the title it's just something for people to try I now see why individuals who do contribute their hardwork never give all the details because it always some criticism. But constructive criticism is always good. But anyways thanks for your thoughts sir.
Trust me, take the philosophical approach and everything will fall in place, the core of each event is Randomness.
United States
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September 8, 2011
5,092 Posts
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Quote: Originally posted by adobea78 on Sep 2, 2013
Maybe you might randomize 0-9 before removing the 2 draws. Use this random chart,maybe, just maybe:
R
random sequence
1
8-3-9-6-4-7-0-2-5-1
2
0-3-6-2-5-7-9-1-4-8
3
3-4-1-0-9-2-5-8-6-7
4
9-5-0-3-6-8-2-1-4-7
5
7-5-2-8-9-1-6-0-4-3
6
0-8-3-6-1-5-4-9-2-7
7
6-8-5-2-3-4-1-9-0-7
8
5-7-1-3-6-4-2-0-9-8
9
7-2-6-9-8-1-3-4-5-0
10
2-1-3-6-7-9-8-5-0-4
Lets remove 2 draws 57140 from Randoms(R) 1, 2, 3 ......
From R1>83962> 839-836-832-396-392-962
R2>36298> 362-369-368-628-629-298
R3>39286>392-398-396-928-926-286
NB: You do not have to use all R1 to R2, two r is will suffice.See how the pattern plays, I will out first digits of reduced R as key for combo, ie 8, 3,3 (R1,R2,R3). Most of the picks will be repeats in different form(reduced permutation you may say). Your ideal is nice, but the event is not linear 12345.......
WS Data(Using your ideal in random way, see chart in txt)
NB: Workout from R1 to R10 is for illustration, you don't use all R, but each R brings a digit in first position
for a combo to consider, a reduce R1 takes you to base 8680851(interprete this for a triad),
R2 take to base 102105108( interprete this for triad)
Excessive Rs is not recommended when waging a punchline(base), removing 4 distinct digits is best for P4(meaning you have 5 to consider , first digit has the edge in combo)