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Cash 3, Florida on October 31, November 1 and 2.

Topic closed. 4 replies. Last post 3 years ago by Uluska.

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Uluska's avatar - strawberry

United States
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November 2, 2012
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Posted: October 31, 2013, 12:38 pm - IP Logged

Cash 3, Florida on October 31, November 1 and 2. Games during those days might have numbers 1, 7 in any possible combination: 11a, a11, 1a1; 77a, a77, 7a7; 17a, a17, 1a7, 71a, a71, 7a1, where letter "a" should be filled with  any possible numbers from 0 to 9. Altogether it makes 120 tickets. Too many. However, one can pick at least 10 tickets.

I would just stick with 17 and 71:17a, a17, 1a7, 71a, a71, 7a1

    Uluska's avatar - strawberry

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    Posted: November 2, 2013, 2:07 pm - IP Logged

    Well, Today, November 2, Midday game had 777. :) People who worked 77a, and a77 or 7a7 must be winners.

    Truly hope my prediction helped someone. ( Myself I got nothing:().

      Uluska's avatar - strawberry

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      Posted: November 2, 2013, 2:24 pm - IP Logged

      There is some chance that Evening game today, November 2, will have 77a, a77, 7a7, a11, 11a,  or 17a, a17, 1a7, 7a1, 71a, a71 or number 4.

        Uluska's avatar - strawberry

        United States
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        Posted: November 2, 2013, 8:19 pm - IP Logged

        Result , November 2, Evening is 947. Somehow I did not suspect for 4 and 7 to come together.

          Uluska's avatar - strawberry

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          November 2, 2012
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          Posted: November 2, 2013, 8:29 pm - IP Logged

          If someone bought all 120 tiskets, they won $500 three times, $1500 alltogether. I ma talking about 777 result on November 2, Midday. It is better not to eliminate identical combinations when they form among different variations. In case of hit they increase winnings.