Zeta Reticuli Star System United States Member #30470 January 17, 2006 10351 Posts Offline

Posted: November 30, 2013, 7:35 pm - IP Logged

The number 6174 is a really mysterious number. At first glance, it might not seem so obvious. But as we are about to see, anyone who can subtract can uncover the mystery that makes 6174 so special.

Kaprekar's operation

In 1949 the mathematician D. R. Kaprekar from Devlali, India, devised a process now known as Kaprekar's operation. First choose a four digit number where the digits are not all the same (that is not 1111, 2222,...). Then rearrange the digits to get the largest and smallest numbers these digits can make. Finally, subtract the smallest number from the largest to get a new number, and carry on repeating the operation for each new number.

It is a simple operation, but Kaprekar discovered it led to a surprising result. Let's try it out, starting with the number 2005, the digits of last year. The maximum number we can make with these digits is 5200, and the minimum is 0025 or 25 (if one or more of the digits is zero, embed these in the left hand side of the minimum number). The subtractions are:

When we reach 6174 the operation repeats itself, returning 6174 every time. We call the number 6174 a kernel of this operation. So 6174 is a kernel for Kaprekar's operation, but is this as special as 6174 gets? Well not only is 6174 the only kernel for the operation, it also has one more surprise up its sleeve. Let's try again starting with a different number, say 1789.

When we started with 2005 the process reached 6174 in seven steps, and for 1789 in three steps. In fact, you reach 6174 for all four digit numbers that don't have all the digits the same. It's marvellous, isn't it? Kaprekar's operation is so simple but uncovers such an interesting result. And this will become even more intriguing when we think about the reason why all four digit numbers reach this mysterious number 6174.

New Mexico United States Member #86099 January 29, 2010 11119 Posts Offline

Posted: December 6, 2013, 6:07 pm - IP Logged

Quote: Originally posted by Coin Toss on November 30, 2013

The number 6174 is a really mysterious number. At first glance, it might not seem so obvious. But as we are about to see, anyone who can subtract can uncover the mystery that makes 6174 so special.

Kaprekar's operation

In 1949 the mathematician D. R. Kaprekar from Devlali, India, devised a process now known as Kaprekar's operation. First choose a four digit number where the digits are not all the same (that is not 1111, 2222,...). Then rearrange the digits to get the largest and smallest numbers these digits can make. Finally, subtract the smallest number from the largest to get a new number, and carry on repeating the operation for each new number.

It is a simple operation, but Kaprekar discovered it led to a surprising result. Let's try it out, starting with the number 2005, the digits of last year. The maximum number we can make with these digits is 5200, and the minimum is 0025 or 25 (if one or more of the digits is zero, embed these in the left hand side of the minimum number). The subtractions are:

When we reach 6174 the operation repeats itself, returning 6174 every time. We call the number 6174 a kernel of this operation. So 6174 is a kernel for Kaprekar's operation, but is this as special as 6174 gets? Well not only is 6174 the only kernel for the operation, it also has one more surprise up its sleeve. Let's try again starting with a different number, say 1789.

When we started with 2005 the process reached 6174 in seven steps, and for 1789 in three steps. In fact, you reach 6174 for all four digit numbers that don't have all the digits the same. It's marvellous, isn't it? Kaprekar's operation is so simple but uncovers such an interesting result. And this will become even more intriguing when we think about the reason why all four digit numbers reach this mysterious number 6174.

United States Member #65075 September 16, 2008 643 Posts Offline

Posted: December 9, 2013, 11:26 pm - IP Logged

Quote: Originally posted by Coin Toss on November 30, 2013

The number 6174 is a really mysterious number. At first glance, it might not seem so obvious. But as we are about to see, anyone who can subtract can uncover the mystery that makes 6174 so special.

Kaprekar's operation

In 1949 the mathematician D. R. Kaprekar from Devlali, India, devised a process now known as Kaprekar's operation. First choose a four digit number where the digits are not all the same (that is not 1111, 2222,...). Then rearrange the digits to get the largest and smallest numbers these digits can make. Finally, subtract the smallest number from the largest to get a new number, and carry on repeating the operation for each new number.

It is a simple operation, but Kaprekar discovered it led to a surprising result. Let's try it out, starting with the number 2005, the digits of last year. The maximum number we can make with these digits is 5200, and the minimum is 0025 or 25 (if one or more of the digits is zero, embed these in the left hand side of the minimum number). The subtractions are:

When we reach 6174 the operation repeats itself, returning 6174 every time. We call the number 6174 a kernel of this operation. So 6174 is a kernel for Kaprekar's operation, but is this as special as 6174 gets? Well not only is 6174 the only kernel for the operation, it also has one more surprise up its sleeve. Let's try again starting with a different number, say 1789.

When we started with 2005 the process reached 6174 in seven steps, and for 1789 in three steps. In fact, you reach 6174 for all four digit numbers that don't have all the digits the same. It's marvellous, isn't it? Kaprekar's operation is so simple but uncovers such an interesting result. And this will become even more intriguing when we think about the reason why all four digit numbers reach this mysterious number 6174.

So I played around too for SC draws. Some of you won't follow this, but those of you familiar with some 999 Book of Numbers titles will follow along nicely with the concepts. I won't get into too much explanation.

You'll see some number substitutions in this method. The rules for those are 3=6; 0=1; 7=9. So anytime I have one of those digits on the X line, I will have to make allowances for the fact that these digits often mask as twins.

So here goes...

First I took a draw, lets say 4145 on Nov 27 in SC, then I wrote it from low to high, i.e. 1445

Next I took the "difference" between the rewritten combination and the constant 6174. When you are dealing with differences, you do not care which combination is on the top of the equation or the bottom because the answer will be the same. You are not adding or substracting, but finding the difference value of the digits.

So:

1445

6174

5330--5331--5333

5X31

5X61

In this case, the difference was 5331.

Next, I stretched out the third line by going one down on the left side, and two up on the right side.

On the fourth line I decided where my X value would go based on my difference combo calculated on line 3 (5331). In this case I put it as a 2nd digit place holder. Anytime I deal with Pick 4, I am only trying to get three of the four digits because that narrows my plays down to just 10 combinations.

I had to create a fifth line in the example above because there is a 3 on my X line, so I have to also have a 6 substitution there. I should also do the same for the 1 there which should be substituted for a 0, but for the purposes of this demonstration, I will leave it out. The third X equation if I did the 1=0 substitution would read 5X30 and 5X60, if I wanted to play 40 combinations instead of 20.

What was the result?

On December 4, 5-1-6-1 showed--That's a straight hit off the 5X61 line.

Ex 2: Let's take the 6124 drawn on Nov 23

Turn that draw combination into 1246 (from low to high), then find the difference between that and the constant "6174"

1246

6174

5131--5132--5134

5x32

5x62

On Nov 25, just three draws later, 5-7-3-2 showed--That's a straight hit off the5X32 line.

Straight is good. I did a few more random samples that did not yield straights, ie 5521 (drawn on Nov 30) yielded 5121 as the difference line (line 3), turned that into 5x21 and 5x20, resulting in a 5x20 hit five draws later as 5002.

Anyway, this method is just using a "constant" variable (i.e 6174 which seemingly has some special properties) to predict 3 of 4 digits in the Pick 4. Of course this method needs more testing to see how consistent it will be as a straight predictor, and also whether it works just in non-computerized drawing states or others as well.

Final: Ex 3: 1123 drawing on Nov 29

1123

6174

5051

5x51--draw #2 showed as 5512

5x50

Note: For anyone who might want to do more testing on this method, you should also keep in mind that when you have a "double" number on your X line, you will also want to consider the complement of that double, ie 5x51 is also 5X11 (551=511).

New Mexico United States Member #86099 January 29, 2010 11119 Posts Offline

Posted: January 7, 2014, 12:51 pm - IP Logged

Quote: Originally posted by SBIP$999 on December 9, 2013

Very interesting.

So I played around too for SC draws. Some of you won't follow this, but those of you familiar with some 999 Book of Numbers titles will follow along nicely with the concepts. I won't get into too much explanation.

You'll see some number substitutions in this method. The rules for those are 3=6; 0=1; 7=9. So anytime I have one of those digits on the X line, I will have to make allowances for the fact that these digits often mask as twins.

So here goes...

First I took a draw, lets say 4145 on Nov 27 in SC, then I wrote it from low to high, i.e. 1445

Next I took the "difference" between the rewritten combination and the constant 6174. When you are dealing with differences, you do not care which combination is on the top of the equation or the bottom because the answer will be the same. You are not adding or substracting, but finding the difference value of the digits.

So:

1445

6174

5330--5331--5333

5X31

5X61

In this case, the difference was 5331.

Next, I stretched out the third line by going one down on the left side, and two up on the right side.

On the fourth line I decided where my X value would go based on my difference combo calculated on line 3 (5331). In this case I put it as a 2nd digit place holder. Anytime I deal with Pick 4, I am only trying to get three of the four digits because that narrows my plays down to just 10 combinations.

I had to create a fifth line in the example above because there is a 3 on my X line, so I have to also have a 6 substitution there. I should also do the same for the 1 there which should be substituted for a 0, but for the purposes of this demonstration, I will leave it out. The third X equation if I did the 1=0 substitution would read 5X30 and 5X60, if I wanted to play 40 combinations instead of 20.

What was the result?

On December 4, 5-1-6-1 showed--That's a straight hit off the 5X61 line.

Ex 2: Let's take the 6124 drawn on Nov 23

Turn that draw combination into 1246 (from low to high), then find the difference between that and the constant "6174"

1246

6174

5131--5132--5134

5x32

5x62

On Nov 25, just three draws later, 5-7-3-2 showed--That's a straight hit off the5X32 line.

Straight is good. I did a few more random samples that did not yield straights, ie 5521 (drawn on Nov 30) yielded 5121 as the difference line (line 3), turned that into 5x21 and 5x20, resulting in a 5x20 hit five draws later as 5002.

Anyway, this method is just using a "constant" variable (i.e 6174 which seemingly has some special properties) to predict 3 of 4 digits in the Pick 4. Of course this method needs more testing to see how consistent it will be as a straight predictor, and also whether it works just in non-computerized drawing states or others as well.

Final: Ex 3: 1123 drawing on Nov 29

1123

6174

5051

5x51--draw #2 showed as 5512

5x50

Note: For anyone who might want to do more testing on this method, you should also keep in mind that when you have a "double" number on your X line, you will also want to consider the complement of that double, ie 5x51 is also 5X11 (551=511).

Austin United States Member #151153 January 8, 2014 11 Posts Offline

Posted: January 9, 2014, 8:04 pm - IP Logged

The funny number 6174 had to be a multiple of the magic 9 and it sure is (6+1+7+4=18=multiple of 9). And I've got news for those that try to find some meaning* that could be used in some lottery system: the number contains the Jackpot symbol 777:

6174 = 2X9X7X7X7

*like in at least being related to some well-known gambling-related lucky charm/symbol.

Michigan United States Member #81740 October 28, 2009 40456 Posts Online

Posted: January 19, 2014, 9:40 am - IP Logged

Quote: Originally posted by Coin Toss on November 30, 2013

The number 6174 is a really mysterious number. At first glance, it might not seem so obvious. But as we are about to see, anyone who can subtract can uncover the mystery that makes 6174 so special.

Kaprekar's operation

In 1949 the mathematician D. R. Kaprekar from Devlali, India, devised a process now known as Kaprekar's operation. First choose a four digit number where the digits are not all the same (that is not 1111, 2222,...). Then rearrange the digits to get the largest and smallest numbers these digits can make. Finally, subtract the smallest number from the largest to get a new number, and carry on repeating the operation for each new number.

It is a simple operation, but Kaprekar discovered it led to a surprising result. Let's try it out, starting with the number 2005, the digits of last year. The maximum number we can make with these digits is 5200, and the minimum is 0025 or 25 (if one or more of the digits is zero, embed these in the left hand side of the minimum number). The subtractions are:

When we reach 6174 the operation repeats itself, returning 6174 every time. We call the number 6174 a kernel of this operation. So 6174 is a kernel for Kaprekar's operation, but is this as special as 6174 gets? Well not only is 6174 the only kernel for the operation, it also has one more surprise up its sleeve. Let's try again starting with a different number, say 1789.

When we started with 2005 the process reached 6174 in seven steps, and for 1789 in three steps. In fact, you reach 6174 for all four digit numbers that don't have all the digits the same. It's marvellous, isn't it? Kaprekar's operation is so simple but uncovers such an interesting result. And this will become even more intriguing when we think about the reason why all four digit numbers reach this mysterious number 6174.

Maine United States Member #99 January 27, 2002 1013 Posts Offline

Posted: February 6, 2014, 12:58 pm - IP Logged

Quote: Originally posted by SBIP$999 on December 9, 2013

Very interesting.

So I played around too for SC draws. Some of you won't follow this, but those of you familiar with some 999 Book of Numbers titles will follow along nicely with the concepts. I won't get into too much explanation.

You'll see some number substitutions in this method. The rules for those are 3=6; 0=1; 7=9. So anytime I have one of those digits on the X line, I will have to make allowances for the fact that these digits often mask as twins.

So here goes...

First I took a draw, lets say 4145 on Nov 27 in SC, then I wrote it from low to high, i.e. 1445

Next I took the "difference" between the rewritten combination and the constant 6174. When you are dealing with differences, you do not care which combination is on the top of the equation or the bottom because the answer will be the same. You are not adding or substracting, but finding the difference value of the digits.

So:

1445

6174

5330--5331--5333

5X31

5X61

In this case, the difference was 5331.

Next, I stretched out the third line by going one down on the left side, and two up on the right side.

On the fourth line I decided where my X value would go based on my difference combo calculated on line 3 (5331). In this case I put it as a 2nd digit place holder. Anytime I deal with Pick 4, I am only trying to get three of the four digits because that narrows my plays down to just 10 combinations.

I had to create a fifth line in the example above because there is a 3 on my X line, so I have to also have a 6 substitution there. I should also do the same for the 1 there which should be substituted for a 0, but for the purposes of this demonstration, I will leave it out. The third X equation if I did the 1=0 substitution would read 5X30 and 5X60, if I wanted to play 40 combinations instead of 20.

What was the result?

On December 4, 5-1-6-1 showed--That's a straight hit off the 5X61 line.

Ex 2: Let's take the 6124 drawn on Nov 23

Turn that draw combination into 1246 (from low to high), then find the difference between that and the constant "6174"

1246

6174

5131--5132--5134

5x32

5x62

On Nov 25, just three draws later, 5-7-3-2 showed--That's a straight hit off the5X32 line.

Straight is good. I did a few more random samples that did not yield straights, ie 5521 (drawn on Nov 30) yielded 5121 as the difference line (line 3), turned that into 5x21 and 5x20, resulting in a 5x20 hit five draws later as 5002.

Anyway, this method is just using a "constant" variable (i.e 6174 which seemingly has some special properties) to predict 3 of 4 digits in the Pick 4. Of course this method needs more testing to see how consistent it will be as a straight predictor, and also whether it works just in non-computerized drawing states or others as well.

Final: Ex 3: 1123 drawing on Nov 29

1123

6174

5051

5x51--draw #2 showed as 5512

5x50

Note: For anyone who might want to do more testing on this method, you should also keep in mind that when you have a "double" number on your X line, you will also want to consider the complement of that double, ie 5x51 is also 5X11 (551=511).

I've been playing around with this in Maryland Pick4 a little and have noticed some interesting things. In the last 60 games there are only six games that do not have a 6 or a 1 or a 7 or a 4 in the winning combo. Also when there is no 6-1-7-or 4 present.....the next game will have a double 6-1-7 or 4 present. I also found that the number you get when subtracting the winning number from 6 1 7 4 often has three of the winning numbers for the next two to three games if you use the mirror numbers of the subtracted result and combine them. Of course that is eight numbers so it's no big surprise ....but ofen the three are in the mirror numbers only. There is also some kind of relationship between every 12th winning combo that I don't quite get yet. Quite an interesting number 6174.

If it wasn't impossible I wouldn't even consider it!

Maine United States Member #99 January 27, 2002 1013 Posts Offline

Posted: February 6, 2014, 2:01 pm - IP Logged

This is what happened today after my last post. Maryland pick 4 day was 4746!! The 6174 minus 2545 (eve winner) = 3629, mirror # 8174 (using real math), then 6174 minus 2545 = 4431, mirror # 9986 (using lottery math). 3269 and 8174 there's the 746.....4431 and 9986 there's the 446! How you pick out the correct triads is a mystery but maybe with a little practice and history it will be easier. Also the winning number twelve games ago was 5767...there's the 67...so maybe that's a clue? Just saying............

If it wasn't impossible I wouldn't even consider it!