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# Question about Mega Millions 5 + 0 odds

Topic closed. Posted 3 years ago. No replies.

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Zeta Reticuli Star System
United States
Member #30470
January 17, 2006
10390 Posts
Offline
 Posted: December 9, 2013, 5:52 pm - IP Logged

One of the things I learned here at LP was the formula for figuring lottery odds.

For example, in a 5/39 game, it's

39 X 38 X 37 X 36 X 36

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1 X 2 X 3 X 4 X 5

or 69090840

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120

= 575, 757.

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Since MM now has a 75 number top matrix, this would be

75 X 74 X 73 X 72 X 71

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1 X 2 X 3 X 4 X 5 (You're shootiing for five numbers if you're going for 5 + 0)

This comes out to 17259390:1

But the MM lists odds of over 18,492,203:1.

I realize there are 15 Mega numbers and you have to play one, which gives this:

The probability for winning \$1,000,000 is thus 14/258,890,850 = .00000005407684358 or “One chance in 18,492,203.57”.

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I just find this a little 'odd'!

Anyone else?

Those who run the lotteries love it when players look for consistency in something that's designed not to have any.

There is one and only one 'proven' system, and that is to book the action. No matter the game, let the players pick their own losers.

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