|Posted: March 13, 2014, 4:55 pm - IP Logged|
Are correct this calculation? , Please recommend it correct calculation
Regular ball a total of 75 numbers
The probability of select the first number in the Mega million = 1/75
The probability of select the second number in the Mega million = 1/74
The probability of select the third number in the Mega million = 1/73
The probability of select the fourth number in the Mega million = 1/72
The probability of select the fifth number in the Mega million = 1/71
The selected numbers or winning numbers are not replaced in the basket, then the probability of choosing five numerous is the sum of the prior probabilities = 1/75 + 1/74 + 1/73 + 1/72 + 1/71 =
1) Close, but you don't add. You multiply and get probability = 4.82829E-10
2) Divide 1/probability found in #1 = 2,071,126,800
3) Find 5! (factorial 5, or 5*4*3*2*1) since you can choose the 5 numbers in any order = 120
4) Divide #2 by #3 = 17,259,390
5) For MM, multiply #4 by 15 since there are 15 different Mega balls = 258,890,850
Those are the odds. You can divide 1 by 258,890,850 to get the probability in decimal form. Note that if you compare #4 to the odds for 2nd prize in MM, it will be different. This is because their odds are the odds of matching only that prize and no other prize (which is harder). To get these odds you would multiply #4 by 15/14 to get approximately 18,492,204.
If the chances of winning the jackpot are so slim, why play when the jackpot is so small? Your chances never change, but the potential payoff does.
If a crystal ball showed you the future of the rest of your life, and in that future you will never win a jackpot, would you still play?
2016: -48.28% (13 tickets) ||
P&L % = Total Win($)/Total Wager($) - 1