United States Member #142494 May 13, 2013 2852 Posts Offline

Posted: March 20, 2014, 12:00 am - IP Logged

Allright , im hoping someone knows this info, or can easily figure it out, since there are so many people here on this part of the forum who are math wiz's... or there may even be a few people around here who know this off the top of their head...

How many drawings is a vtrac combo expected on average to hit ( triple - single - double)

so the answers im looking for is what goes in the questino marks..

v123 is expected on average to hit once every ???? drawings

v112 is expected on average to hit once every ??? drawings

v444 is expected on average to hit once every ??? drawings

im not looking for how often a double or single should hit, but rather how often any 1 particular single, double or triple vtrac combination should hit on average...

there are 10 single combos which have 8 numbers each = 80 numbers

there are 20 double combos which have 6 numbers each = 120 numbers

there are 5 triple combos which have 4 numbers each = 20 numbers

that adds up to 220 which should account for the total combos for pick 3 ... so i think this is correct ...

thanks in advancce , sorry if this is a stupid question... im good at certain things , but not math problems such as this ....

winning numbers are found using odds , patterns, history, and a little work - anything else is just a coincidence, unless your psychic..

United States Member #132100 August 26, 2012 1076 Posts Offline

Posted: March 20, 2014, 8:20 am - IP Logged

Quote: Originally posted by ineedahit on March 20, 2014

Allright , im hoping someone knows this info, or can easily figure it out, since there are so many people here on this part of the forum who are math wiz's... or there may even be a few people around here who know this off the top of their head...

How many drawings is a vtrac combo expected on average to hit ( triple - single - double)

so the answers im looking for is what goes in the questino marks..

v123 is expected on average to hit once every ???? drawings

v112 is expected on average to hit once every ??? drawings

v444 is expected on average to hit once every ??? drawings

im not looking for how often a double or single should hit, but rather how often any 1 particular single, double or triple vtrac combination should hit on average...

there are 10 single combos which have 8 numbers each = 80 numbers

there are 20 double combos which have 6 numbers each = 120 numbers

there are 5 triple combos which have 4 numbers each = 20 numbers

that adds up to 220 which should account for the total combos for pick 3 ... so i think this is correct ...

thanks in advancce , sorry if this is a stupid question... im good at certain things , but not math problems such as this ....

There are 1000 pick 3 Straights

There are 125 Straight VTracs

Each VTrac equals 8 Straights

There are 60 Singles VTracs such as 123

There are 60 Doubles VTracs such as 112

There are 5 Triples VTracs such as 444

60 + 60 + 5 = 125 Straights VTracs and each of them equals 8 pick 3 Straights

--------------------

A Straight pick 3 is expected to hit 1 time each 1000 drawings or 0.1% of the time

A Straight VTrac is expected to hit 8 times each 1000 drawings or 0.8% of the time

60 VTracs = 480 pick 3 Straights so they might hit maybe 48% of the time.

That goes for the Singles and also for the Doubles VTracs.

As there are only 5 VTrac Triples they = 40 pick 3 Straights

So all of the Triple VTracs together might hit maybe 4% of the time.

But I don't know anything at all about Math, nothing, so I am not sure about any of this.

United States Member #116477 September 11, 2011 353 Posts Offline

Posted: March 20, 2014, 8:39 am - IP Logged

I dont understand vtracs at all! So youre not alone! Ive asked about them on here but the replies just make it more confusing! They talk "legalize" only with Lotto

language only they understand!!! Can anyone tell us about v tracs in Laymans language????

ORLANDO, FLORIDA United States Member #4924 June 3, 2004 5896 Posts Offline

Posted: March 20, 2014, 10:02 am - IP Logged

Quote: Originally posted by Wentworth on March 20, 2014

I dont understand vtracs at all! So youre not alone! Ive asked about them on here but the replies just make it more confusing! They talk "legalize" only with Lotto

language only they understand!!! Can anyone tell us about v tracs in Laymans language????

United States Member #116477 September 11, 2011 353 Posts Offline

Posted: March 20, 2014, 10:07 am - IP Logged

what does that mean???????? are you maybe refering to this vtracs 1o1 course person? again if so its hard to understand what shes teaching... TNT????????

nj United States Member #145657 August 10, 2013 974 Posts Offline

Posted: March 20, 2014, 11:36 am - IP Logged

the only good way to make some advancment with vtrac is to keep trac of the missing vtrac pair .there is only a few of them andwhen one is missing more then 5draws ,then is time to act.but there is a better way to get ahead in p3 , by tracking the pair that is due like you were doing a while ago

Pennsylvania United States Member #2218 September 1, 2003 5387 Posts Online

Posted: March 20, 2014, 12:15 pm - IP Logged

VTRAC 101

We are reducing 10 digits down to 5.

Here's how:

Digits 0 & 5 = VTRAC 1

Digits 1 & 6 = VTRAC 2

Digits 2 & 7 = VTRAC 3

Digits 3 & 8 = VTRAC 4

Digits 4 & 9 = VTRAC 5

Some folks call them VTRAC's others may call them mirror digits.

1. Look for VTRAC's that have NOT hit in last 5 or more drawings. For example, if a VTRAC 1 (Digits 0 & 5) has not hit in the last 5 or more draws you would want to include both the digits 0 & 5

2. Decide what strategy to play. Play just double vtrac set(s) or no-match VTRAC set(s). Each set consists of 8 digit combinations.

3. Sums: VTRAC Sums 8, 9, and 10 are most frequent. Look for one of these sums that have not hit after 10 draws.

Pennsylvania United States Member #2218 September 1, 2003 5387 Posts Online

Posted: March 20, 2014, 12:26 pm - IP Logged

Quote: Originally posted by winsumloosesum on March 20, 2014

VTRAC 101

We are reducing 10 digits down to 5.

Here's how:

Digits 0 & 5 = VTRAC 1

Digits 1 & 6 = VTRAC 2

Digits 2 & 7 = VTRAC 3

Digits 3 & 8 = VTRAC 4

Digits 4 & 9 = VTRAC 5

Some folks call them VTRAC's others may call them mirror digits.

1. Look for VTRAC's that have NOT hit in last 5 or more drawings. For example, if a VTRAC 1 (Digits 0 & 5) has not hit in the last 5 or more draws you would want to include both the digits 0 & 5

2. Decide what strategy to play. Play just double vtrac set(s) or no-match VTRAC set(s). Each set consists of 8 digit combinations.

3. Sums: VTRAC Sums 8, 9, and 10 are most frequent. Look for one of these sums that have not hit after 10 draws.

United States Member #1987 August 5, 2003 8968 Posts Offline

Posted: March 20, 2014, 6:29 pm - IP Logged

Quote: Originally posted by ineedahit on March 20, 2014

Allright , im hoping someone knows this info, or can easily figure it out, since there are so many people here on this part of the forum who are math wiz's... or there may even be a few people around here who know this off the top of their head...

How many drawings is a vtrac combo expected on average to hit ( triple - single - double)

so the answers im looking for is what goes in the questino marks..

v123 is expected on average to hit once every ???? drawings

v112 is expected on average to hit once every ??? drawings

v444 is expected on average to hit once every ??? drawings

im not looking for how often a double or single should hit, but rather how often any 1 particular single, double or triple vtrac combination should hit on average...

there are 10 single combos which have 8 numbers each = 80 numbers

there are 20 double combos which have 6 numbers each = 120 numbers

there are 5 triple combos which have 4 numbers each = 20 numbers

that adds up to 220 which should account for the total combos for pick 3 ... so i think this is correct ...

thanks in advancce , sorry if this is a stupid question... im good at certain things , but not math problems such as this ....

Hello there ineedahit, the best way in which to find out how many times a Vtrac will hit in your state is to count how many times the Vtrac has come out in a six month timespan & then divide by six. The answer is the average amount of times that Vtrac will hit in your state. If you would then like to narrow the timespan you can do that as well.

In the Vtracs search engine load the Vtrac, set the parameters, when you get the results save it to your favorites, that way you can click on what you have saved & not have to key in all of the #s over & over again.

As for me I only look at Vtracs in the ascending order.

United States Member #142494 May 13, 2013 2852 Posts Offline

Posted: March 21, 2014, 2:07 am - IP Logged

thanks guys - i appreciate the responses ...im kind of surprised this isnt common knowledge to someone around here .. ive been tracking the due vtrac pairs and combos and the ones due do not take too long at all to hit .... i would like to have some averages to look at though , so i can see how many draws a due vtrac combo is over its average .... i started a thread yesterday using 9 states and their most overdue vtrac combos and there were 2 hits today..... ill see how it goes , im expecting most states to have a hit within a week or less ...

thanks for the tip laverne, havent seen ya in a while.. , i may end up having to do that , but the right math could give you the answer, i think i know , but im not sure if im correct ...

actually let me ask you guys this ... one combo... lets say 123 ... could hit 6 ways ... so that combo has a 6 out of 1000 chance of winning right ... now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total straight possiblities ... so that vtrac hitting has a 48 out of 1000 odds of hitting .. which is 4.8 percent ... which means it should hit 4.8 times per 100 draws .... right? .... which means it should hit once every 20.8 drawings ... right??

please let me know if anyone knows if this is correct or incorrect ... if it is correct , i guess i could do the same thing with the double and triple vtrac combos... and figure those out ...

thanks alot guys ... !!!

winning numbers are found using odds , patterns, history, and a little work - anything else is just a coincidence, unless your psychic..

United States Member #132100 August 26, 2012 1076 Posts Offline

Posted: March 21, 2014, 11:24 pm - IP Logged

Quote: Originally posted by ineedahit on March 21, 2014

thanks guys - i appreciate the responses ...im kind of surprised this isnt common knowledge to someone around here .. ive been tracking the due vtrac pairs and combos and the ones due do not take too long at all to hit .... i would like to have some averages to look at though , so i can see how many draws a due vtrac combo is over its average .... i started a thread yesterday using 9 states and their most overdue vtrac combos and there were 2 hits today..... ill see how it goes , im expecting most states to have a hit within a week or less ...

thanks for the tip laverne, havent seen ya in a while.. , i may end up having to do that , but the right math could give you the answer, i think i know , but im not sure if im correct ...

actually let me ask you guys this ... one combo... lets say 123 ... could hit 6 ways ... so that combo has a 6 out of 1000 chance of winning right ... now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total straight possiblities ... so that vtrac hitting has a 48 out of 1000 odds of hitting .. which is 4.8 percent ... which means it should hit 4.8 times per 100 draws .... right? .... which means it should hit once every 20.8 drawings ... right??

please let me know if anyone knows if this is correct or incorrect ... if it is correct , i guess i could do the same thing with the double and triple vtrac combos... and figure those out ...

thanks alot guys ... !!!

I just now had enough time to take a good look at your post, sorry.

You posted:

"Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total straight possiblities"

Wrong!!!

You should have posted this:

"Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total Boxed possiblities"

So that vtrac hitting has a 48 out of 1000 BOXED odds of hitting .. which is 4.8 percent ... which means it should hit 4.8 times per 100 draws .... right? RIGHT!!! which means it should hit once every 20.8 drawings ... right?? RIGHT!!!

So that vtrac hitting has a 48 out of 1000 BOXED odds of hitting .. which is 4.8 percent ... which means it should hit 4.8 times per 100 draws .... right? RIGHT!!! which means it should hit once every 20.8 drawings ... right?? RIGHT!!!

I think that I am right, but I can't be 100% sure.

Good Luck!!!

Fernando.

awesome Thank you MoneI .... im actually only looking for the average any single vtrac combo should hit boxed so that works .... so thats what i needed ... the reason i was saying straight is because i used how many times each number in the vtrac can hit straight and it was 48 ...but i see how i worded it wrong, but it got me to the right answer i guess in the end... thank you for responding... here is what i have been doing... i actually have a thread posting this test im doing..... i took 9 states and figured out each states 2 most overdue vtrac combos , and grouped states together that shared similar overdue vtracs, i did this the day before yesterday and here are the results so far .... if anyone has some input they would like to add, im interested...

actually, these are the results after 3 drawings - i put the numbers in real numbers and didnt use the vtracs numbers so people would know what to look for

So that vtrac hitting has a 48 out of 1000 BOXED odds of hitting .. which is 4.8 percent ... which means it should hit 4.8 times per 100 draws .... right? RIGHT!!! which means it should hit once every 20.8 drawings ... right?? RIGHT!!!

United States Member #132100 August 26, 2012 1076 Posts Offline

Posted: March 22, 2014, 8:21 am - IP Logged

Quote: Originally posted by ineedahit on March 22, 2014

awesome Thank you MoneI .... im actually only looking for the average any single vtrac combo should hit boxed so that works .... so thats what i needed ... the reason i was saying straight is because i used how many times each number in the vtrac can hit straight and it was 48 ...but i see how i worded it wrong, but it got me to the right answer i guess in the end... thank you for responding... here is what i have been doing... i actually have a thread posting this test im doing..... i took 9 states and figured out each states 2 most overdue vtrac combos , and grouped states together that shared similar overdue vtracs, i did this the day before yesterday and here are the results so far .... if anyone has some input they would like to add, im interested...

actually, these are the results after 3 drawings - i put the numbers in real numbers and didnt use the vtracs numbers so people would know what to look for

United States Member #132100 August 26, 2012 1076 Posts Offline

Posted: March 23, 2014, 3:23 pm - IP Logged

Quote: Originally posted by MonEl on March 22, 2014

"Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total Boxed possiblities"

But that is only right if you play the 8 combinations BOXED.

---------------------

Ifyou play the 8 combinations of a VTrac straight, then there are only 8 possibilities out of 1 thousand or 0.8%.

------------

If You play the 8 straight combinations of a VTrac BOXED, then you will have 48 BOXED possibilities out of 1 thousand or 4.8%.

--------------------

Good Luck!

You can of course play each of the 48 boxed combinations straight instead of boxed, but then you will spend $48 at $1 each or $24 at 50 cents each, instead of the $8 or $4, otherwise.