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# P-3 System Theory

Topic closed. 11 replies. Last post 2 years ago by helpmewin.

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United States
Member #128790
June 2, 2012
5431 Posts
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 Posted: July 22, 2014, 11:35 am - IP Logged

Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

Florida, last ten days below,

(Top number oldest mid-July 12)

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8-Last night's winner.

In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

The middle column has mostly 3-4-5 in it.

The third column has mostly 7-8-9

First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

So we have 359. Now, my preference is to not play that number in that order. I choose 539.

Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

539 for the midday Florida draw. let's see what happens.

Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

In my first column I chose 3, but the number 2 came in second.

3

2

In my second column choice I chose 5, but my second choice would be 3 was the second choice.

3 5

2 3

And my third column I chose the 9, but the 8 was second in line.

3 5 9

2 3 8

Now make combos: 359-358-339-338/259-258-239-238

Have fun.

backwoods ga
United States
Member #155844
May 31, 2014
1886 Posts
Offline
 Posted: July 22, 2014, 2:20 pm - IP Logged

Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

Florida, last ten days below,

(Top number oldest mid-July 12)

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8-Last night's winner.

In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

The middle column has mostly 3-4-5 in it.

The third column has mostly 7-8-9

First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

So we have 359. Now, my preference is to not play that number in that order. I choose 539.

Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

539 for the midday Florida draw. let's see what happens.

Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

In my first column I chose 3, but the number 2 came in second.

3

2

In my second column choice I chose 5, but my second choice would be 3 was the second choice.

3 5

2 3

And my third column I chose the 9, but the 8 was second in line.

3 5 9

2 3 8

Now make combos: 359-358-339-338/259-258-239-238

Have fun.

This is honestly the best post I've ever read from you on lotterypost..

keep up good work

Ridgewood NJ
United States
Member #52539
May 29, 2007
901 Posts
Offline
 Posted: July 22, 2014, 2:54 pm - IP Logged

Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

Florida, last ten days below,

(Top number oldest mid-July 12)

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8-Last night's winner.

In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

The middle column has mostly 3-4-5 in it.

The third column has mostly 7-8-9

First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

So we have 359. Now, my preference is to not play that number in that order. I choose 539.

Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

539 for the midday Florida draw. let's see what happens.

Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

In my first column I chose 3, but the number 2 came in second.

3

2

In my second column choice I chose 5, but my second choice would be 3 was the second choice.

3 5

2 3

And my third column I chose the 9, but the 8 was second in line.

3 5 9

2 3 8

Now make combos: 359-358-339-338/259-258-239-238

Have fun.

cool post, onlymoney!

funny that this very design is how my own home designed software program attacks the game.

It takes a probability measure, but also interrogates the summation within the pairs to find the most likely. In example it performs a similar decision as you have here with a qualifier on likely sums making up the number i.e. if pair sums 7, 8, or 9 is due then computations occur that give a 7 sum (maybe 25 pair), 8 sum (maybe 17 pair), and 9 sum (maybe 27 pair).

Best of luck to all!!

~A

United States
Member #110594
May 8, 2011
885 Posts
Offline
 Posted: July 22, 2014, 4:16 pm - IP Logged

Nice job!

United States
Member #152758
February 24, 2014
327 Posts
Offline
 Posted: July 23, 2014, 9:11 am - IP Logged

backwoods ga
United States
Member #155844
May 31, 2014
1886 Posts
Offline
 Posted: July 23, 2014, 9:15 am - IP Logged

This can't be. Onlymoney posting a system this good... Guess it takes 200 bad systems to get 1 good 1

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: July 23, 2014, 12:49 pm - IP Logged

Thanks everyone. Missed the last two draws, but it's going to take some time, patience and some luck to get a hit.

Below is the updated list.

My choices for mid are,

2 3 9

1 5 7

Combos: 239-237-259-257/139-137-159-157 (not necessarily in that order)

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8

3 4 7

0 8 8

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: July 24, 2014, 3:16 pm - IP Logged

Check this out. I just noticed that If we ALWAYS use the number 3 as the lowest number, obviously, the numbers after that can't possibly be less than 3. So If i had to make an ALL STAR list to play ALL the time, it would look like this below. I think I'm just going to play these ALL the time.

Pairs: 34-35-36, and then just add 7-8-9 to them for a total of nine combos to play ALL the time. Or, just play the combos that haven't come out yet, in black.

OR, JUST PLAY THOSE SETS ONLY WHEN THE LAST WINNING NUMBER HAS A NUMBER 3 IN IT BECAUSE WE KNOW THAT MOST OF THE TIME, ONE OR MORE NUMBERS REPEAT FROM THE LAST WINNING COMBO.

347-348-349

357-358-359

367-368-369

If you look below on the list, you'll see how often one of those combos show in red.

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8

3 4 7

0 8 8

3 4 5

2 2 9

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: July 24, 2014, 10:36 pm - IP Logged

Check this out. I just noticed that If we ALWAYS use the number 3 as the lowest number, obviously, the numbers after that can't possibly be less than 3. So If i had to make an ALL STAR list to play ALL the time, it would look like this below. I think I'm just going to play these ALL the time.

Pairs: 34-35-36, and then just add 7-8-9 to them for a total of nine combos to play ALL the time. Or, just play the combos that haven't come out yet, in black.

OR, JUST PLAY THOSE SETS ONLY WHEN THE LAST WINNING NUMBER HAS A NUMBER 3 IN IT BECAUSE WE KNOW THAT MOST OF THE TIME, ONE OR MORE NUMBERS REPEAT FROM THE LAST WINNING COMBO.

347-348-349

357-358-359

367-368-369

If you look below on the list, you'll see how often one of those combos show in red.

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8

3 4 7

0 8 8

3 4 5

2 2 9

347-348-349

357-358-359

367-368-369

Winner eve was 361. Looks like i should add a lower part.

Example: 340-341-342

350-351-352

360-361-362

Yes I know, it's easy to see the solution after the fact. But at the same time, that's the only way I know how to learn.

United States
Member #111017
May 16, 2011
10244 Posts
Offline
 Posted: July 24, 2014, 10:45 pm - IP Logged

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: July 24, 2014, 11:05 pm - IP Logged

Thanks Mr. Lotto-nc

Sorry Floss, Sheniqua axed first. I'll give you Mozambique after. Thanks for your patience.

The number for the HUTU tribe and the surrounding town is 358.

Floss, Mozambique has only one draw a day. I'll do my best..lol

I threw some bones in the air and it landed as 396. Eve draw for both predictions.

Spend wisely.

u\$a
United States
Member #106665
February 22, 2011
19740 Posts
Offline
 Posted: July 25, 2014, 10:03 am - IP Logged

Looking forwards to seeing all your WINNING Tickets posted

Let it Snow

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