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P-3 System Theory

Topic closed. 11 replies. Last post 2 years ago by helpmewin.

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United States
Member #128790
June 2, 2012
5431 Posts
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Posted: July 22, 2014, 11:35 am - IP Logged

Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

Florida, last ten days below,

(Top number oldest mid-July 12)

2 6 9

3 6 7

0 4 4

1 2 3

3 7 9

3 4 8

2 4 6

3 5 7

0 1 7

0 5 8

5 9 9

1 7 9

2 3 7

0 3 4

5 5 6

2 4 9

2 3 4

3 3 9

0 3 9

1 3 8-Last night's winner.

 

In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

The middle column has mostly 3-4-5 in it.

The third column has mostly 7-8-9

 

First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

 

So we have 359. Now, my preference is to not play that number in that order. I choose 539.

 

Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

539 for the midday Florida draw. let's see what happens.

Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

In my first column I chose 3, but the number 2 came in second.

3

2

 

In my second column choice I chose 5, but my second choice would be 3 was the second choice.

3 5

2 3

 

And my third column I chose the 9, but the 8 was second in line.

3 5 9

2 3 8

Now make combos: 359-358-339-338/259-258-239-238

Have fun.

    Avatar
    backwoods ga
    United States
    Member #155844
    May 31, 2014
    1886 Posts
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    Posted: July 22, 2014, 2:20 pm - IP Logged

    Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

    Florida, last ten days below,

    (Top number oldest mid-July 12)

    2 6 9

    3 6 7

    0 4 4

    1 2 3

    3 7 9

    3 4 8

    2 4 6

    3 5 7

    0 1 7

    0 5 8

    5 9 9

    1 7 9

    2 3 7

    0 3 4

    5 5 6

    2 4 9

    2 3 4

    3 3 9

    0 3 9

    1 3 8-Last night's winner.

     

    In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

    As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

    The middle column has mostly 3-4-5 in it.

    The third column has mostly 7-8-9

     

    First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

    Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

    Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

     

    So we have 359. Now, my preference is to not play that number in that order. I choose 539.

     

    Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

    539 for the midday Florida draw. let's see what happens.

    Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

    In my first column I chose 3, but the number 2 came in second.

    3

    2

     

    In my second column choice I chose 5, but my second choice would be 3 was the second choice.

    3 5

    2 3

     

    And my third column I chose the 9, but the 8 was second in line.

    3 5 9

    2 3 8

    Now make combos: 359-358-339-338/259-258-239-238

    Have fun.

    This is honestly the best post I've ever read from you on lotterypost..

    keep up good work

      Avatar
      Ridgewood NJ
      United States
      Member #52539
      May 29, 2007
      901 Posts
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      Posted: July 22, 2014, 2:54 pm - IP Logged

      Take your last ten day's winning numbers and make a list of both mid and eve on top of each other. WHILE MAKING THE LIST, WRITE THE NUMBERS FROM LOW TO HIGH, EX: 294=249)

      Florida, last ten days below,

      (Top number oldest mid-July 12)

      2 6 9

      3 6 7

      0 4 4

      1 2 3

      3 7 9

      3 4 8

      2 4 6

      3 5 7

      0 1 7

      0 5 8

      5 9 9

      1 7 9

      2 3 7

      0 3 4

      5 5 6

      2 4 9

      2 3 4

      3 3 9

      0 3 9

      1 3 8-Last night's winner.

       

      In my test, I'm looking to see what comes most often after the last number for example after the 1 in 138. You may want to use more data than ten days, but I feel a short term trend is better to analyze.

      As a general rule, If you look at the list in this particular list, the first column mostly has a 0-1-2 or 3.

      The middle column has mostly 3-4-5 in it.

      The third column has mostly 7-8-9

       

      First position: For my first position I choose 3. Why? Well there's not enough data to see what comes after the number 1. The other choice is a 2, but since most of the time, one number will repeat in the next draw, I chose the number 3 because 3 was in the last winning number 318.

      Second position: For my second position, you can see that a 5 and a 3 follows the number 3, but the last time was a 3, so I'm choosing the 5, since it may be it's turn to show.

      Third position: For the last column I choose the number 9. There's a lot of 8 and 9's next to each other, and once again, since the last time an 8 showed up after a 8, I chose 9 as my third column number.

       

      So we have 359. Now, my preference is to not play that number in that order. I choose 539.

       

      Now when making your own decisions, just keep in mind the general rules mentioned above, then use your own intuition and some common sense to see what the finer choices may be. There are no rules set in stone in this, except for the general rule above.

      539 for the midday Florida draw. let's see what happens.

      Also, that's just one combo. I could easily combine the second most possible numbers and include them too.

      In my first column I chose 3, but the number 2 came in second.

      3

      2

       

      In my second column choice I chose 5, but my second choice would be 3 was the second choice.

      3 5

      2 3

       

      And my third column I chose the 9, but the 8 was second in line.

      3 5 9

      2 3 8

      Now make combos: 359-358-339-338/259-258-239-238

      Have fun.

      cool post, onlymoney!

      funny that this very design is how my own home designed software program attacks the game.

      It takes a probability measure, but also interrogates the summation within the pairs to find the most likely. In example it performs a similar decision as you have here with a qualifier on likely sums making up the number i.e. if pair sums 7, 8, or 9 is due then computations occur that give a 7 sum (maybe 25 pair), 8 sum (maybe 17 pair), and 9 sum (maybe 27 pair). 

      Best of luck to all!!

      ~A


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        May 8, 2011
        885 Posts
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        Posted: July 22, 2014, 4:16 pm - IP Logged

        Nice job! 

        Still waiting for Mozambique...please.


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          Member #152758
          February 24, 2014
          327 Posts
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          Posted: July 23, 2014, 9:11 am - IP Logged

          what  about   warsaw   poland

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            backwoods ga
            United States
            Member #155844
            May 31, 2014
            1886 Posts
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            Posted: July 23, 2014, 9:15 am - IP Logged

            This can't be. Onlymoney posting a system this good... Guess it takes 200 bad systems to get 1 good 1


              United States
              Member #128790
              June 2, 2012
              5431 Posts
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              Posted: July 23, 2014, 12:49 pm - IP Logged

              Thanks everyone. Missed the last two draws, but it's going to take some time, patience and some luck to get a hit. 

              Below is the updated list. 

              My choices for mid are,

              2 3 9

              1 5 7

              Combos: 239-237-259-257/139-137-159-157 (not necessarily in that order)

               

               

              0 4 4

              1 2 3

              3 7 9

              3 4 8

              2 4 6

              3 5 7

              0 1 7

              0 5 8

              5 9 9

              1 7 9

              2 3 7

              0 3 4

              5 5 6

              2 4 9

              2 3 4

              3 3 9

              0 3 9

              1 3 8

              3 4 7

              0 8 8


                United States
                Member #128790
                June 2, 2012
                5431 Posts
                Offline
                Posted: July 24, 2014, 3:16 pm - IP Logged

                Check this out. I just noticed that If we ALWAYS use the number 3 as the lowest number, obviously, the numbers after that can't possibly be less than 3. So If i had to make an ALL STAR list to play ALL the time, it would look like this below. I think I'm just going to play these ALL the time.

                Pairs: 34-35-36, and then just add 7-8-9 to them for a total of nine combos to play ALL the time. Or, just play the combos that haven't come out yet, in black.

                OR, JUST PLAY THOSE SETS ONLY WHEN THE LAST WINNING NUMBER HAS A NUMBER 3 IN IT BECAUSE WE KNOW THAT MOST OF THE TIME, ONE OR MORE NUMBERS REPEAT FROM THE LAST WINNING COMBO.

                347-348-349

                357-358-359

                367-368-369

                 

                If you look below on the list, you'll see how often one of those combos show in red.

                 

                2 6 9

                3 6 7

                0 4 4

                1 2 3

                3 7 9

                3 4 8

                2 4 6

                3 5 7

                0 1 7

                0 5 8

                5 9 9

                1 7 9

                2 3 7

                0 3 4

                5 5 6

                2 4 9

                2 3 4

                3 3 9

                0 3 9

                1 3 8

                3 4 7

                0 8 8

                3 4 5

                2 2 9


                  United States
                  Member #128790
                  June 2, 2012
                  5431 Posts
                  Offline
                  Posted: July 24, 2014, 10:36 pm - IP Logged

                  Check this out. I just noticed that If we ALWAYS use the number 3 as the lowest number, obviously, the numbers after that can't possibly be less than 3. So If i had to make an ALL STAR list to play ALL the time, it would look like this below. I think I'm just going to play these ALL the time.

                  Pairs: 34-35-36, and then just add 7-8-9 to them for a total of nine combos to play ALL the time. Or, just play the combos that haven't come out yet, in black.

                  OR, JUST PLAY THOSE SETS ONLY WHEN THE LAST WINNING NUMBER HAS A NUMBER 3 IN IT BECAUSE WE KNOW THAT MOST OF THE TIME, ONE OR MORE NUMBERS REPEAT FROM THE LAST WINNING COMBO.

                  347-348-349

                  357-358-359

                  367-368-369

                   

                  If you look below on the list, you'll see how often one of those combos show in red.

                   

                  2 6 9

                  3 6 7

                  0 4 4

                  1 2 3

                  3 7 9

                  3 4 8

                  2 4 6

                  3 5 7

                  0 1 7

                  0 5 8

                  5 9 9

                  1 7 9

                  2 3 7

                  0 3 4

                  5 5 6

                  2 4 9

                  2 3 4

                  3 3 9

                  0 3 9

                  1 3 8

                  3 4 7

                  0 8 8

                  3 4 5

                  2 2 9

                  347-348-349

                  357-358-359

                  367-368-369

                   

                  Winner eve was 361. Looks like i should add a lower part.

                  Example: 340-341-342

                                350-351-352

                                360-361-362

                   

                  Yes I know, it's easy to see the solution after the fact. But at the same time, that's the only way I know how to learn.

                    mrlotto-nc's avatar - Sphere animated2.gif

                    United States
                    Member #111017
                    May 16, 2011
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                    Posted: July 24, 2014, 10:45 pm - IP Logged

                    Thumbs Up


                      United States
                      Member #128790
                      June 2, 2012
                      5431 Posts
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                      Posted: July 24, 2014, 11:05 pm - IP Logged

                      Thumbs Up

                      Thanks Mr. Lotto-nc

                      Sorry Floss, Sheniqua axed first. I'll give you Mozambique after. Thanks for your patience.

                      The number for the HUTU tribe and the surrounding town is 358.

                      Floss, Mozambique has only one draw a day. I'll do my best..lol

                      I threw some bones in the air and it landed as 396. Eve draw for both predictions.

                      Spend wisely.

                        helpmewin's avatar - dandy
                        u$a
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                        Member #106665
                        February 22, 2011
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                        Posted: July 25, 2014, 10:03 am - IP Logged

                        Looking forwards to seeing all your WINNING Tickets posted Party

                        Let it Snow Snowman