Texas United States Member #150797 December 31, 2013 815 Posts Offline

Posted: September 4, 2014, 3:05 pm - IP Logged

An important statistic in the Pick 3 game is that 80% of the time either zero digits or 1 digit from the previously-drawn combination will reappear. This happens about equally -- just under 40% of the time zero digits will repeat and just over 40% of the time 1 digit will repeat.

So, rather than waiting for the elusive 2 digit return, why not play what is most likely to appear?

This isn't a number selection system, but is a systematic way of creating the most likely combos based on the last few draws, using all 10 digits.

To do this I group the 10 digits into 3 groups:

Digits that hit in the last game (group 1);

Digits that hit in the 2 games before the last game (group 2); and

Digits that have been out for 3 games or more (group 3).

These three groups then hit in certain patterns depending on how many digits repeat.

If you are expecting zero digits to repeat, then the possible patterns are:

zero digits from group 1 (last draw), 1 digit from group 2 and 2 digits from group 3 -- or, Pattern 012

zero digits from group 1, 2 digits from group 2 and 1 digit from group 3 -- or, Pattern 021

all 3 digits from one of groups 2 or 3 -- Patterns 003 or 030.

Similar patterns exist if a 1 digit repeat is expected: Pattern 102, Pattern 120 or Pattern 111 (which hits most often, about 20% of the time).

As an example, here are the last 4 draws of Texas Evening:

September 3, 2014 9-9-1

September 2, 2014 2-1-6

September 1, 2014 3-0-1

August 30, 2014 9-3-0

We would group our digits as follows:

Group 1 (last draw) 1,9

Group 2 (previous 2 draws) 0,2,3,6

Group 3 (digits out 3 draws or more) 4,5,7,8 (digit 7 is out 21 draws !)

Now, Texas Evening has not had a zero digit repeat for 15 draws, and it is overdue for that event. So, I will make up the combos based on that expectation:

Pattern 012: Zero digits from the first group (eliminate 1 & 9), 1 digit from the second group, and a pair from the third group -- this comes out as 0,2,3,6 plus 45,47,57,58 &78 so the combinations are 045, 047, 057, 058, 078, 245, 247, 257, 258, 278, 345, 347, 357, 358, 378, 456, 467, 567, 568, 678.

Pattern 021: Similarly, we make up the combinations that fit the pattern, zero from the first group, 2 from the second group and one from the third group: 02,03,06,23,26,36 + 4,5,7,8.

Pattern 030: Here we make up all the combinations for the second group only, with zero from the first and third groups, digits 0,2,3,6: 023,026,236

Pattern 003: As for 030, we ignore the first two groups and make up our combinations from the third group, digits 4,5,7,8: 457,458, 478.

Of course you can also include doubles if you think they are due, just follow the patterns.

This gives us 46 unmatched combinations, which is a lot, but which are the only combinations possible IF zero digits repeat from the last draw and an unmatched combination is drawn.

These possible combinations can then be filtered down -- in this case I'm certainly looking at the strong possibility of that 7 hitting soon, maybe this evening.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

Park City, UT United States Member #69864 January 18, 2009 993 Posts Offline

Posted: September 4, 2014, 8:26 pm - IP Logged

Quote: Originally posted by Tialuvslotto on September 4, 2014

An important statistic in the Pick 3 game is that 80% of the time either zero digits or 1 digit from the previously-drawn combination will reappear. This happens about equally -- just under 40% of the time zero digits will repeat and just over 40% of the time 1 digit will repeat.

So, rather than waiting for the elusive 2 digit return, why not play what is most likely to appear?

This isn't a number selection system, but is a systematic way of creating the most likely combos based on the last few draws, using all 10 digits.

To do this I group the 10 digits into 3 groups:

Digits that hit in the last game (group 1);

Digits that hit in the 2 games before the last game (group 2); and

Digits that have been out for 3 games or more (group 3).

These three groups then hit in certain patterns depending on how many digits repeat.

If you are expecting zero digits to repeat, then the possible patterns are:

zero digits from group 1 (last draw), 1 digit from group 2 and 2 digits from group 3 -- or, Pattern 012

zero digits from group 1, 2 digits from group 2 and 1 digit from group 3 -- or, Pattern 021

all 3 digits from one of groups 2 or 3 -- Patterns 003 or 030.

Similar patterns exist if a 1 digit repeat is expected: Pattern 102, Pattern 120 or Pattern 111 (which hits most often, about 20% of the time).

As an example, here are the last 4 draws of Texas Evening:

September 3, 2014 9-9-1

September 2, 2014 2-1-6

September 1, 2014 3-0-1

August 30, 2014 9-3-0

We would group our digits as follows:

Group 1 (last draw) 1,9

Group 2 (previous 2 draws) 0,2,3,6

Group 3 (digits out 3 draws or more) 4,5,7,8 (digit 7 is out 21 draws !)

Now, Texas Evening has not had a zero digit repeat for 15 draws, and it is overdue for that event. So, I will make up the combos based on that expectation:

Pattern 012: Zero digits from the first group (eliminate 1 & 9), 1 digit from the second group, and a pair from the third group -- this comes out as 0,2,3,6 plus 45,47,57,58 &78 so the combinations are 045, 047, 057, 058, 078, 245, 247, 257, 258, 278, 345, 347, 357, 358, 378, 456, 467, 567, 568, 678.

Pattern 021: Similarly, we make up the combinations that fit the pattern, zero from the first group, 2 from the second group and one from the third group: 02,03,06,23,26,36 + 4,5,7,8.

Pattern 030: Here we make up all the combinations for the second group only, with zero from the first and third groups, digits 0,2,3,6: 023,026,236

Pattern 003: As for 030, we ignore the first two groups and make up our combinations from the third group, digits 4,5,7,8: 457,458, 478.

Of course you can also include doubles if you think they are due, just follow the patterns.

This gives us 46 unmatched combinations, which is a lot, but which are the only combinations possible IF zero digits repeat from the last draw and an unmatched combination is drawn.

These possible combinations can then be filtered down -- in this case I'm certainly looking at the strong possibility of that 7 hitting soon, maybe this evening.

I like it. It is always interesting to represent numbers or group of numbers in alternate forms for pattern analysis.

I use to re-arrange pick 5 draws into their digit form as follows:

You will notice that the strings 11 22 33 44 ... typically are dominant. Of course you need RL's digit program to help with filtering.

Anyway the alternate representation helps visually to see any digit pattern trends if you are in to that kind of thing.

Jimmy

Thanks, Jim. That's interesting.

One thing with Pick 3, a high proportion of doubles are 300 patterns (030, 003), that is both of the digits in the combination are from only one of the groups. This happens for about 1/3 of doubles, with a slight edge to the second group, i.e. numbers that have been out 1-2 games.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

United States Member #155994 June 5, 2014 497 Posts Offline

Posted: September 5, 2014, 10:17 am - IP Logged

Well, that's very interesting. But, what about the overlap between Groups 1 and 2(i.e. 991 and 216)? In this case, you left the 1 out of Group 2. Also, what's needed is a way to determine when a certain pattern is ,more specifically, expected to hit. Anyway, nice work

Texas United States Member #150797 December 31, 2013 815 Posts Offline

Posted: September 5, 2014, 11:11 am - IP Logged

Quote: Originally posted by Pick3Guy on September 5, 2014

Well, that's very interesting. But, what about the overlap between Groups 1 and 2(i.e. 991 and 216)? In this case, you left the 1 out of Group 2. Also, what's needed is a way to determine when a certain pattern is ,more specifically, expected to hit. Anyway, nice work

I left out Group 1 (1 & 9) because I was expecting that no digits would repeat from one draw to the next. That's the point of this strategy -- to only make the combinations that are likely to hit.

The hit rate for the patterns is as follows:

111 20%

300 14%

012 16%

021 11%

102 12%

120 11%

201 8%

210 9%

Not much to choose between them, but you can see that if you are expecting one digit to return that the 111 pattern is more likely.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

Stone Mountain*Georgia United States Member #828 November 2, 2002 10491 Posts Offline

Posted: September 19, 2014, 6:15 pm - IP Logged

Quote: Originally posted by Tialuvslotto on September 4, 2014

An important statistic in the Pick 3 game is that 80% of the time either zero digits or 1 digit from the previously-drawn combination will reappear. This happens about equally -- just under 40% of the time zero digits will repeat and just over 40% of the time 1 digit will repeat.

So, rather than waiting for the elusive 2 digit return, why not play what is most likely to appear?

This isn't a number selection system, but is a systematic way of creating the most likely combos based on the last few draws, using all 10 digits.

To do this I group the 10 digits into 3 groups:

Digits that hit in the last game (group 1);

Digits that hit in the 2 games before the last game (group 2); and

Digits that have been out for 3 games or more (group 3).

These three groups then hit in certain patterns depending on how many digits repeat.

If you are expecting zero digits to repeat, then the possible patterns are:

zero digits from group 1 (last draw), 1 digit from group 2 and 2 digits from group 3 -- or, Pattern 012

zero digits from group 1, 2 digits from group 2 and 1 digit from group 3 -- or, Pattern 021

all 3 digits from one of groups 2 or 3 -- Patterns 003 or 030.

Similar patterns exist if a 1 digit repeat is expected: Pattern 102, Pattern 120 or Pattern 111 (which hits most often, about 20% of the time).

As an example, here are the last 4 draws of Texas Evening:

September 3, 2014 9-9-1

September 2, 2014 2-1-6

September 1, 2014 3-0-1

August 30, 2014 9-3-0

We would group our digits as follows:

Group 1 (last draw) 1,9

Group 2 (previous 2 draws) 0,2,3,6

Group 3 (digits out 3 draws or more) 4,5,7,8 (digit 7 is out 21 draws !)

Now, Texas Evening has not had a zero digit repeat for 15 draws, and it is overdue for that event. So, I will make up the combos based on that expectation:

Pattern 012: Zero digits from the first group (eliminate 1 & 9), 1 digit from the second group, and a pair from the third group -- this comes out as 0,2,3,6 plus 45,47,57,58 &78 so the combinations are 045, 047, 057, 058, 078, 245, 247, 257, 258, 278, 345, 347, 357, 358, 378, 456, 467, 567, 568, 678.

Pattern 021: Similarly, we make up the combinations that fit the pattern, zero from the first group, 2 from the second group and one from the third group: 02,03,06,23,26,36 + 4,5,7,8.

Pattern 030: Here we make up all the combinations for the second group only, with zero from the first and third groups, digits 0,2,3,6: 023,026,236

Pattern 003: As for 030, we ignore the first two groups and make up our combinations from the third group, digits 4,5,7,8: 457,458, 478.

Of course you can also include doubles if you think they are due, just follow the patterns.

This gives us 46 unmatched combinations, which is a lot, but which are the only combinations possible IF zero digits repeat from the last draw and an unmatched combination is drawn.

These possible combinations can then be filtered down -- in this case I'm certainly looking at the strong possibility of that 7 hitting soon, maybe this evening.

Wish we could preserve some of these post ......in a permanent area for new and old players to see.

Say, Tia how about saving some of these in your Blog? Just too good to just go away so fast ...... down the stream and then poof gone ! LOL

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

Actually, it doesn't surprise me that someone else has worked with this idea in the past -- full credit goes to IWish for posting this first.

I do my method a little differently in that I use all the 10 digits grouped by last game, 2 games before that and, finally, digits that did not play in the last 3 draws. I notice that IWish draws his numbers from the last 3 games only. Both methods have their merits, but my way of doing this will give more combinations while IWish's method will be more economical to play.

Alas, after reading through the thread, I found that no one could answer the most important question for this method: "How do you select a pattern to play?"

Ah well, maybe in another 10 years...

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

bgonÃ§alves Brasil Member #92564 June 9, 2010 2126 Posts Offline

Posted: September 20, 2014, 3:25 pm - IP Logged

Hello, could join the statistic of 5 5 hot and cold digits digits Demand for the pair to use as fixed (pivot) not to walk in a circle, Indeed the great difficulty of pick3 and other lotteries find a reference A basic pattern need not be 100% to be 75% and 80% of the time

houston texas United States Member #130267 July 10, 2012 6300 Posts Offline

Posted: September 21, 2014, 4:01 pm - IP Logged

Quote: Originally posted by Tialuvslotto on September 4, 2014

An important statistic in the Pick 3 game is that 80% of the time either zero digits or 1 digit from the previously-drawn combination will reappear. This happens about equally -- just under 40% of the time zero digits will repeat and just over 40% of the time 1 digit will repeat.

So, rather than waiting for the elusive 2 digit return, why not play what is most likely to appear?

This isn't a number selection system, but is a systematic way of creating the most likely combos based on the last few draws, using all 10 digits.

To do this I group the 10 digits into 3 groups:

Digits that hit in the last game (group 1);

Digits that hit in the 2 games before the last game (group 2); and

Digits that have been out for 3 games or more (group 3).

These three groups then hit in certain patterns depending on how many digits repeat.

If you are expecting zero digits to repeat, then the possible patterns are:

zero digits from group 1 (last draw), 1 digit from group 2 and 2 digits from group 3 -- or, Pattern 012

zero digits from group 1, 2 digits from group 2 and 1 digit from group 3 -- or, Pattern 021

all 3 digits from one of groups 2 or 3 -- Patterns 003 or 030.

Similar patterns exist if a 1 digit repeat is expected: Pattern 102, Pattern 120 or Pattern 111 (which hits most often, about 20% of the time).

As an example, here are the last 4 draws of Texas Evening:

September 3, 2014 9-9-1

September 2, 2014 2-1-6

September 1, 2014 3-0-1

August 30, 2014 9-3-0

We would group our digits as follows:

Group 1 (last draw) 1,9

Group 2 (previous 2 draws) 0,2,3,6

Group 3 (digits out 3 draws or more) 4,5,7,8 (digit 7 is out 21 draws !)

Now, Texas Evening has not had a zero digit repeat for 15 draws, and it is overdue for that event. So, I will make up the combos based on that expectation:

Pattern 012: Zero digits from the first group (eliminate 1 & 9), 1 digit from the second group, and a pair from the third group -- this comes out as 0,2,3,6 plus 45,47,57,58 &78 so the combinations are 045, 047, 057, 058, 078, 245, 247, 257, 258, 278, 345, 347, 357, 358, 378, 456, 467, 567, 568, 678.

Pattern 021: Similarly, we make up the combinations that fit the pattern, zero from the first group, 2 from the second group and one from the third group: 02,03,06,23,26,36 + 4,5,7,8.

Pattern 030: Here we make up all the combinations for the second group only, with zero from the first and third groups, digits 0,2,3,6: 023,026,236

Pattern 003: As for 030, we ignore the first two groups and make up our combinations from the third group, digits 4,5,7,8: 457,458, 478.

Of course you can also include doubles if you think they are due, just follow the patterns.

This gives us 46 unmatched combinations, which is a lot, but which are the only combinations possible IF zero digits repeat from the last draw and an unmatched combination is drawn.

These possible combinations can then be filtered down -- in this case I'm certainly looking at the strong possibility of that 7 hitting soon, maybe this evening.

Hello Tialuvslotto, I am from Texas and have been trying to figure this out for tomorrow, I hope it is right,