Welcome Guest
You last visited December 7, 2016, 11:24 am
All times shown are
Eastern Time (GMT-5:00)

# P-3 Assimilation System

Topic closed. 23 replies. Last post 2 years ago by lakerben.

 Page 1 of 2

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 6, 2014, 6:49 pm - IP Logged
 I did a short test in Florida and out of the 5 random tests, it created 3 boxed hits and one straight. I only tested for eve to eve. You'll need a regular calculator for this.Take your last winning number and look at the sum. Example: Florida, yesterday's eve winner was 421=sum 7.Look back to see when the last sum 7 was in the eve draws.The last winning number I found was on August 10 eve-205= sum 7Then look for the following eve's winning number which would be on Aug. 11, eve-948Subtract 948 from 205 using REGULAR math= 743Divide 743 by 2 using a calculator. Then divide again by 2, and again, etc...until your two digit number is as close to the number 28. Now, we go back to last night's winning number which was 421 from above. We simply add 28 to the 421, 8 times.421+28=449449+28=477477+28=505505+28=533533+28=561561+28=589589+28=617617+28=645 Play those in the eve for the next 3 nights.

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 6, 2014, 6:52 pm - IP Logged

Sometimes you'll get a two digit number that will not be 28, but that's ok. It could be 27, or even 26, or 29, 30, whatever you get as close to 28 is acceptable.

GA
United States
Member #158157
August 13, 2014
99 Posts
Offline
 Posted: September 6, 2014, 8:15 pm - IP Logged
 I did a short test in Florida and out of the 5 random tests, it created 3 boxed hits and one straight. I only tested for eve to eve. You'll need a regular calculator for this.Take your last winning number and look at the sum. Example: Florida, yesterday's eve winner was 421=sum 7.Look back to see when the last sum 7 was in the eve draws.The last winning number I found was on August 10 eve-205= sum 7Then look for the following eve's winning number which would be on Aug. 11, eve-948Subtract 948 from 205 using REGULAR math= 743Divide 743 by 2 using a calculator. Then divide again by 2, and again, etc...until your two digit number is as close to the number 28. Now, we go back to last night's winning number which was 421 from above. We simply add 28 to the 421, 8 times.421+28=449449+28=477477+28=505505+28=533533+28=561561+28=589589+28=617617+28=645 Play those in the eve for the next 3 nights.

few questions

1. at the beginning with 421 are you adding it to root sum lets say 960 = 6 or 5 in last digit sum.

2. when subtracting the 948 etc, do you change the order or not eg: 948, 849, 498

3. at the bottom you have 421+28. following your rules shouldn't  743/2 = 23.2  as it is the closest you get to the number 28 when continuously dividing.

thanks

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 6, 2014, 8:31 pm - IP Logged

few questions

1. at the beginning with 421 are you adding it to root sum lets say 960 = 6 or 5 in last digit sum.

2. when subtracting the 948 etc, do you change the order or not eg: 948, 849, 498

3. at the bottom you have 421+28. following your rules shouldn't  743/2 = 23.2  as it is the closest you get to the number 28 when continuously dividing.

thanks

1: I never wrote ROOT sum, only sum. No, just finding what sum it is. We only add to the 421 whatever the two digit we get when we do our workout.

2: You keep the original combination orientation.  948 stays 948.

3: You're absolutely correct. I should've made a clause, but was writing in haste, I had 28 on my mind from an earlier workout.. The other option would be 46. So 23 is closer to 28 than 46.   23 is only 5 steps away, and 46 is 18 steps away from 28. .

You can try the 46, it's not written in stone.

Good catch ! Thanks

So let's do the correct math with 23,

421+23=444

444+23=467

467+23=490

490+23=513

513+23=536

536+23=559

559+23=582

582+23=605

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 6, 2014, 8:49 pm - IP Logged

No winner tonight, Fl was 614. Two more nights left.

New Mexico
United States
Member #86099
January 29, 2010
11119 Posts
Offline
 Posted: September 6, 2014, 9:02 pm - IP Logged

Cool!  Excel it somebody!

What percentage of the doubles in the last 10,000 draws simulates this test?

South Carolina
United States
Member #18322
July 9, 2005
1704 Posts
Offline
 Posted: September 6, 2014, 9:18 pm - IP Logged
 I did a short test in Florida and out of the 5 random tests, it created 3 boxed hits and one straight. I only tested for eve to eve. You'll need a regular calculator for this.Take your last winning number and look at the sum. Example: Florida, yesterday's eve winner was 421=sum 7.Look back to see when the last sum 7 was in the eve draws.The last winning number I found was on August 10 eve-205= sum 7Then look for the following eve's winning number which would be on Aug. 11, eve-948Subtract 948 from 205 using REGULAR math= 743Divide 743 by 2 using a calculator. Then divide again by 2, and again, etc...until your two digit number is as close to the number 28. Now, we go back to last night's winning number which was 421 from above. We simply add 28 to the 421, 8 times.421+28=449449+28=477477+28=505505+28=533533+28=561561+28=589589+28=617617+28=645 Play those in the eve for the next 3 nights.

Where do you get the 28 from, in the first place ? Is 28 a CONSTANT ?? Or is it supposed to be 23 or 46, as in the following posts ??  Where do these numbers come from ? Are they CONSTANTS ???

u\$a
United States
Member #106665
February 22, 2011
19818 Posts
Online
 Posted: September 7, 2014, 1:23 am - IP Logged

Wow i bet you'll be Surprised

Let it Snow

GA
United States
Member #158157
August 13, 2014
99 Posts
Offline
 Posted: September 7, 2014, 1:55 am - IP Logged

Ok just to clarify before i make sure i am backtesting correctly.

example 948 = 21 = 1 last digit sum? is this how you sum up your combinations to go back and look for a matching sum?

Bowling Green ,Florida
United States
Member #108735
March 30, 2011
4091 Posts
Offline
 Posted: September 7, 2014, 9:16 am - IP Logged

Ok just to clarify before i make sure i am backtesting correctly.

example 948 = 21 = 1 last digit sum? is this how you sum up your combinations to go back and look for a matching sum?

If your back testing why not use Sum, Root Sum, and LDR

And see which one works the best??

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 7, 2014, 10:22 am - IP Logged

Cool!  Excel it somebody!

What percentage of the doubles in the last 10,000 draws simulates this test?

LOL, 38.912

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 7, 2014, 10:23 am - IP Logged

Where do you get the 28 from, in the first place ? Is 28 a CONSTANT ?? Or is it supposed to be 23 or 46, as in the following posts ??  Where do these numbers come from ? Are they CONSTANTS ???

Different amounts produce different two digit numbers. The last one on my mind was the 28 because it was from one of the back test workouts.

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 7, 2014, 10:38 am - IP Logged

Ok just to clarify before i make sure i am backtesting correctly.

example 948 = 21 = 1 last digit sum? is this how you sum up your combinations to go back and look for a matching sum?

Wow, no, you're way off base.

The 948 is just the number that showed after the 205. 948 has no relevancy to the sums part of the workout. The theory behind this system is that when a number shows (948) after the sum we're looking for, which in this case happens to be (205=7 sum), I'm assuming that whatever controlling force is behind 948 showing after 205 can be broken into sub-parts, which is why I divide it down by 2 until I get to a two digit number as in 23. 23 is sort of like a small representation of the larger whole/building block of the "Controlling Force" mentioned earlier. Basically It's like taking apart a piece of skin down to the molecular level to see what makes it tick/or what pattern it's currently in. Then when you find the PRIMER, you hope that it will continue to leave it's trace/fingerprint for about three more days or so, until the primer changes. After the three days, you do the whole process over again with whatever the winning number is 3 days later.

You subtract the 205 from the 948, which gives us 743. Then divide the 743 by two until you reach a two digit number close to 28, which happened to be 23, because the next step up would be 46, and that's too high. You could try 46, it may work just as well.

Then you go back to your original number 421=sum 7, and keep adding 23 eight times.

United States
Member #128790
June 2, 2012
5431 Posts
Offline
 Posted: September 7, 2014, 11:27 am - IP Logged

Here's a recent example from Florida, for those who don't quite understand.

Imagine today was Aug 30 eve, winning number 613. 613=10 sum.

Now we go back to see the last winning number that has a sum of 10. It occurred on Aug. 25 eve-055. 055=sum 10

What fell after 055?...185 showed the next night. so 185-055=130

Take 130 and divide by 2 until we get close to 28.

130/2= 65

65/2=32.5

We will use 32 as our adding number.

Now, remember we used 613, so we add 32 to 613 8 times.

613+32=645---two nights later-boxed hit

645+32=677

677+32=709

709+32=741

741+32=773

773+32=805

805+32=837

837+32=869

 Mon, Sep 1, 2014 4-6-5?Prize Payouts Sun, Aug 31, 2014 3-5-3?Prize Payouts Sat, Aug 30, 2014 6-1-3?Prize Payouts Fri, Aug 29, 2014 9-8-5?Prize Payouts Thu, Aug 28, 2014 3-0-1?Prize Payouts Wed, Aug 27, 2014 6-2-6?Prize Payouts Tue, Aug 26, 2014 1-8-5?Prize Payouts Mon, Aug 25, 2014 0-5-5?Prize Payouts
South Carolina
United States
Member #18322
July 9, 2005
1704 Posts
Offline
 Posted: September 7, 2014, 4:36 pm - IP Logged

Here's a recent example from Florida, for those who don't quite understand.

Imagine today was Aug 30 eve, winning number 613. 613=10 sum.

Now we go back to see the last winning number that has a sum of 10. It occurred on Aug. 25 eve-055. 055=sum 10

What fell after 055?...185 showed the next night. so 185-055=130

Take 130 and divide by 2 until we get close to 28.

130/2= 65

65/2=32.5

We will use 32 as our adding number.

Now, remember we used 613, so we add 32 to 613 8 times.

613+32=645---two nights later-boxed hit

645+32=677

677+32=709

709+32=741

741+32=773

773+32=805

805+32=837

837+32=869

 Mon, Sep 1, 2014 4-6-5?Prize Payouts Sun, Aug 31, 2014 3-5-3?Prize Payouts Sat, Aug 30, 2014 6-1-3?Prize Payouts Fri, Aug 29, 2014 9-8-5?Prize Payouts Thu, Aug 28, 2014 3-0-1?Prize Payouts Wed, Aug 27, 2014 6-2-6?Prize Payouts Tue, Aug 26, 2014 1-8-5?Prize Payouts Mon, Aug 25, 2014 0-5-5?Prize Payouts

I still don't understand why you keep using the number 28, as if you're holding it CONSTANT  ??  When would you change 28 to some other number, and how long would you hold onto a new "CONSTANT" ??

 Page 1 of 2