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Excel question

Topic closed. 6 replies. Last post 1 year ago by lakerben.

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lakerben's avatar - spherewall
New Mexico
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January 29, 2010
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Posted: June 15, 2015, 9:26 am - IP Logged

In my many work experiences I worked with electronics.  We used Polar and rectangular for ac electronics.  I would like to try it for pick 3.

Say for example draw 003.

sum 3 root 3. How can that be expressed dealing with the largest sum 27 with polar and rectangular.  Is this feasabile?

 

Any thoughts?

Guitar

How about them cowboys!

 

 

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    CARBOB's avatar - FL LOTTERY_LOGO.png
    ORLANDO, FLORIDA
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    Posted: June 15, 2015, 9:45 am - IP Logged

    In my many work experiences I worked with electronics.  We used Polar and rectangular for ac electronics.  I would like to try it for pick 3.

    Say for example draw 003.

    sum 3 root 3. How can that be expressed dealing with the largest sum 27 with polar and rectangular.  Is this feasabile?

     

    Any thoughts?

    Guitar

    I suggest contacting Jadelottery.

      JADELottery's avatar - MeAtWork 03.PNG
      The Quantum Master
      West Concord, MN
      United States
      Member #21
      December 7, 2001
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      Posted: June 15, 2015, 12:12 pm - IP Logged

      In my many work experiences I worked with electronics.  We used Polar and rectangular for ac electronics.  I would like to try it for pick 3.

      Say for example draw 003.

      sum 3 root 3. How can that be expressed dealing with the largest sum 27 with polar and rectangular.  Is this feasabile?

       

      Any thoughts?

      Guitar

      What do you want assign as x and y?

      Sum = x? Root = x? Sum = y? Root = y?

      Once we get by that, all else is easy.

      Presented 'AS IS' and for Entertainment Purposes Only.
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      Use at your own risk.

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      Jehocifer

        lakerben's avatar - spherewall
        New Mexico
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        Posted: June 17, 2015, 1:12 pm - IP Logged

        What do you want assign as x and y?

        Sum = x? Root = x? Sum = y? Root = y?

        Once we get by that, all else is easy.

        Sum =x, root =y.  And maybe a pulldown feature to change these.

        thanks jade.

         

        PS :I used to have a lab named Tejas who looked exactly like the avatar you are using.  He lived to 12 years old and was a great dog.

         

        Dance

        How about them cowboys!

         

         

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          JADELottery's avatar - MeAtWork 03.PNG
          The Quantum Master
          West Concord, MN
          United States
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          Posted: June 17, 2015, 1:58 pm - IP Logged

          Sum =x, root =y.  And maybe a pulldown feature to change these.

          thanks jade.

           

          PS :I used to have a lab named Tejas who looked exactly like the avatar you are using.  He lived to 12 years old and was a great dog.

           

          Dance

          I'll work it with sum - x and root - y.

           

          That's my baby, Nikki. She's a Border Lab.

          Presented 'AS IS' and for Entertainment Purposes Only.
          Any gain or loss is your responsibility.
          Use at your own risk.

          Order is a Subset of Chaos
          Knowledge is Beyond Belief
          Wisdom is Not Censored
          Douglas Paul Smallish
          Jehocifer

            JADELottery's avatar - MeAtWork 03.PNG
            The Quantum Master
            West Concord, MN
            United States
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            December 7, 2001
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            Posted: June 17, 2015, 4:21 pm - IP Logged

            We have one method.

            The radial vector would always be above the x-axis.

            Where x = Sum and y = Root, then r = √((x - 13.5)(x - 13.5) + y²) and in radians θ = arccos(x / r) or in degrees θ = (180°/π) · arccos(x / r)

            Presented 'AS IS' and for Entertainment Purposes Only.
            Any gain or loss is your responsibility.
            Use at your own risk.

            Order is a Subset of Chaos
            Knowledge is Beyond Belief
            Wisdom is Not Censored
            Douglas Paul Smallish
            Jehocifer

              lakerben's avatar - spherewall
              New Mexico
              United States
              Member #86099
              January 29, 2010
              11119 Posts
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              Posted: June 18, 2015, 12:18 pm - IP Logged

              We have one method.

              The radial vector would always be above the x-axis.

              Where x = Sum and y = Root, then r = √((x - 13.5)(x - 13.5) + y²) and in radians θ = arccos(x / r) or in degrees θ = (180°/π) · arccos(x / r)

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              How about them cowboys!

               

               

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