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Smart Pick-3 System

Topic closed. 22 replies. Last post 1 month ago by Sunglasses.

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amber123's avatar - OpIFNim

United States
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March 12, 2015
2536 Posts
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Posted: October 25, 2016, 10:10 pm - IP Logged

Aware of the premise that most of the time at least one number from the previous winner shows in the next drawing has given me an idea that I never thought of until recently, and it was staring me in the face all this time...lol. So simple I overlooked it.

Here are the rules/filers: 

 

A: No pairs from the last TWO draws. For example, 123 has 3 pairs...12-13-23. None of those pairs should be in your selections for the next drawing.

B: No combinations that are all high, or all low numbers.

C: No combinations that are all even, or all odd.

D: No doubles or triples.

 

Take my second win out of three attempts. https://www.lotterypost.com/thread/307258/29

I used the last winning number midday in Florida today. The winner was 973, so I used the 9, the 7, and the 3.

Starting with the number 9 in 973, I realized there are only a certain amount of pairs hat can be made, thus reducing the cost. And no doubles...... For example...using the 9 example again, you have 09-19-29-39-49-59-69-79-89

So for our first group we use the 09. Our last two winning numbers in Florida were 194 and 973, so no pairs can be included from those two latest winning numbers.

Let's start the list for the first group,

The 9=09-19-29-39-49-59-69-79-89

 

First the 09....so now we have one of the all possible pairs for the number 9, we must find the third digit. We don't want doubles, all low, all high, all even, all odd, so we use those filters when we make combos out of those pairs. 

Okay, our first pair is 09. We need a third digit. Let's start with 0. We can't use 0 because that would be 090, and that's a double, DISQUALIFIED!

Next number to pair with 09 is 1. 091 is also DISQUALIFIED...why? because one of the rules states that no pairs from the previous two winners can be included. Two draws prior, the winner was 194, and there goes the 19.

 

Next is the 2 paired with the 09. 092 is a qualified combo to keep because it violates no rules whatsoever.

So we have 092. how about 093? Yes. it also qualifies, no rules broken.

092-093...094?...NOPE...why? because the pair in 094...94 was in last night's winner...194

 

So we have 092 and 093...

Let's move on to 095..."Which btw was tonight's Florida winner which was on my list of predictions). of course 095 was kept for not breaking any of those rules stated above.

 

096? Yes, no rules broken....092-093-095-096

097?...NOPE, today's mid winner was 973, the 97 pair disqualifies it. 

098? That's good to go, and finally 099 which is a no-no because it's a double.

 

So far for the first group we have 092-093-095-096.

 

Do this with the other two numbers to get all the numbers.

    amber123's avatar - OpIFNim

    United States
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    Posted: October 25, 2016, 10:19 pm - IP Logged

    Forgot to mention that after doing the 09 workout, you'll also have to do the 19 workout, then the 29-39..etc...for that first group. I know it seems like a lot of numbers, but trust me, once you apply the 4 filters that occur so rarely in general, you'll end up with about 35 combos altogether.   

      pavizlo$'s avatar - binary
      OKC, OK
      United States
      Member #120575
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      Posted: October 25, 2016, 11:57 pm - IP Logged

      Forgot to mention that after doing the 09 workout, you'll also have to do the 19 workout, then the 29-39..etc...for that first group. I know it seems like a lot of numbers, but trust me, once you apply the 4 filters that occur so rarely in general, you'll end up with about 35 combos altogether.   

      Thanks Amber.

      This is what they call "a single digit returned", there is also a "two-digit returned". Her is the general concept:

       Example (a,b,c) is previous drawing result: For a single digit returned the next drawing (exclude double and triple) HAS to be in one of the following groups:

      1)  a&[all pairs of[(0:9)-(a,b,c)] This means: Remove the last drawing digits (a,b,c) from the 10 digits 0 to 9, take the remaining to form all possible pairs and

      finally combine those pairs with the digit a.

      2)  b&[all pairs of (0:9)-(a,b,c)]  Apply the same concept as above using digit b

      3)  c&[all pairs of (0:9)-(a,b,c)] Apply the same concept as above using the digit c

      Finally you can apply your preferred filter at your own risk

       

      For two- digit returned: Form the 3 pairs: ab,ac, bc

      then

      1)   ab&[all single digits of(0:9)-(a,b,c)]  this means to combine the pair (ab) with each of the remaining 7 single digits

      2)  ac&[all single digits of (0:9)-(a,b,c)]  do the same as above

      3)  bc&[all single digits of (0:9)-(a,b,c)] .

       

      An example for single digit returned

      On 10/23 drawing was 251 next day  10/24 the drawing was 583

      Let say on 10/24 you want to play a single digit returned. You would do this:

      1)  2&[ all pairs of(0:9)-(2,5,1)] =2&(all pairs of (0,3,4,6,7,8))

      2) 5&(all pairs of (0,3,4,6,7,8) the winning number 583 is in this group

      3)  1&(all pairs of (0,3,4,6,7,8)

      Of course you would apply your preferred filter to reduce the picks.

      GOOD LUCK EVERYONE

        CARBOB's avatar - FL LOTTERY_LOGO.png
        ORLANDO, FLORIDA
        United States
        Member #4924
        June 3, 2004
        5914 Posts
        Online
        Posted: October 26, 2016, 6:39 am - IP Logged

        Thanks Amber.

        This is what they call "a single digit returned", there is also a "two-digit returned". Her is the general concept:

         Example (a,b,c) is previous drawing result: For a single digit returned the next drawing (exclude double and triple) HAS to be in one of the following groups:

        1)  a&[all pairs of[(0:9)-(a,b,c)] This means: Remove the last drawing digits (a,b,c) from the 10 digits 0 to 9, take the remaining to form all possible pairs and

        finally combine those pairs with the digit a.

        2)  b&[all pairs of (0:9)-(a,b,c)]  Apply the same concept as above using digit b

        3)  c&[all pairs of (0:9)-(a,b,c)] Apply the same concept as above using the digit c

        Finally you can apply your preferred filter at your own risk

         

        For two- digit returned: Form the 3 pairs: ab,ac, bc

        then

        1)   ab&[all single digits of(0:9)-(a,b,c)]  this means to combine the pair (ab) with each of the remaining 7 single digits

        2)  ac&[all single digits of (0:9)-(a,b,c)]  do the same as above

        3)  bc&[all single digits of (0:9)-(a,b,c)] .

         

        An example for single digit returned

        On 10/23 drawing was 251 next day  10/24 the drawing was 583

        Let say on 10/24 you want to play a single digit returned. You would do this:

        1)  2&[ all pairs of(0:9)-(2,5,1)] =2&(all pairs of (0,3,4,6,7,8))

        2) 5&(all pairs of (0,3,4,6,7,8) the winning number 583 is in this group

        3)  1&(all pairs of (0,3,4,6,7,8)

        Of course you would apply your preferred filter to reduce the picks.

        Do you have this in Excel?

          CARBOB's avatar - FL LOTTERY_LOGO.png
          ORLANDO, FLORIDA
          United States
          Member #4924
          June 3, 2004
          5914 Posts
          Online
          Posted: October 26, 2016, 6:43 am - IP Logged

          Aware of the premise that most of the time at least one number from the previous winner shows in the next drawing has given me an idea that I never thought of until recently, and it was staring me in the face all this time...lol. So simple I overlooked it.

          Here are the rules/filers: 

           

          A: No pairs from the last TWO draws. For example, 123 has 3 pairs...12-13-23. None of those pairs should be in your selections for the next drawing.

          B: No combinations that are all high, or all low numbers.

          C: No combinations that are all even, or all odd.

          D: No doubles or triples.

           

          Take my second win out of three attempts. https://www.lotterypost.com/thread/307258/29

          I used the last winning number midday in Florida today. The winner was 973, so I used the 9, the 7, and the 3.

          Starting with the number 9 in 973, I realized there are only a certain amount of pairs hat can be made, thus reducing the cost. And no doubles...... For example...using the 9 example again, you have 09-19-29-39-49-59-69-79-89

          So for our first group we use the 09. Our last two winning numbers in Florida were 194 and 973, so no pairs can be included from those two latest winning numbers.

          Let's start the list for the first group,

          The 9=09-19-29-39-49-59-69-79-89

           

          First the 09....so now we have one of the all possible pairs for the number 9, we must find the third digit. We don't want doubles, all low, all high, all even, all odd, so we use those filters when we make combos out of those pairs. 

          Okay, our first pair is 09. We need a third digit. Let's start with 0. We can't use 0 because that would be 090, and that's a double, DISQUALIFIED!

          Next number to pair with 09 is 1. 091 is also DISQUALIFIED...why? because one of the rules states that no pairs from the previous two winners can be included. Two draws prior, the winner was 194, and there goes the 19.

           

          Next is the 2 paired with the 09. 092 is a qualified combo to keep because it violates no rules whatsoever.

          So we have 092. how about 093? Yes. it also qualifies, no rules broken.

          092-093...094?...NOPE...why? because the pair in 094...94 was in last night's winner...194

           

          So we have 092 and 093...

          Let's move on to 095..."Which btw was tonight's Florida winner which was on my list of predictions). of course 095 was kept for not breaking any of those rules stated above.

           

          096? Yes, no rules broken....092-093-095-096

          097?...NOPE, today's mid winner was 973, the 97 pair disqualifies it. 

          098? That's good to go, and finally 099 which is a no-no because it's a double.

           

          So far for the first group we have 092-093-095-096.

           

          Do this with the other two numbers to get all the numbers.

          amber, please clarify the statement below

          A: No pairs from the last TWO draws. For example, 123 has 3 pairs...12-13-23. None of those pairs should be in your selections for the next drawing.

          if that is true, should there be another set of pairs?

            helpmewin's avatar - dandy
            u$a
            United States
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            Posted: October 26, 2016, 10:12 am - IP Logged

            So is this all there is to it or is there more info COMING SOON! Naughty

            Let it Snow Snowman

              amber123's avatar - OpIFNim

              United States
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              Posted: October 26, 2016, 11:28 am - IP Logged

              amber, please clarify the statement below

              A: No pairs from the last TWO draws. For example, 123 has 3 pairs...12-13-23. None of those pairs should be in your selections for the next drawing.

              if that is true, should there be another set of pairs?

              No, I think I should clarify.

              Yesterday's Florida winning numbers were 973 and 059. 973 pairs=97 93 73.....059=05 09 59

              After you make your combos, there should be NO combos on your list that have 97 93 73 05 09 59 in them.

              For example, one of my combos at the end of my workout is 327. This combo should be deleted from my list because there's a 73 in it. It's basically another filter.

              I hope that explains.

                amber123's avatar - OpIFNim

                United States
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                Posted: October 26, 2016, 11:30 am - IP Logged

                So is this all there is to it or is there more info COMING SOON! Naughty

                That's it, unless there's something you don't understand. I would like to reduce the amount of sets to play, but that becomes too risky. 

                The problem with this is that it doesn't cover doubles, and Florida is due for a double, so I may wait and see before playing in Florida.

                  helpmewin's avatar - dandy
                  u$a
                  United States
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                  February 22, 2011
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                  Posted: October 26, 2016, 11:39 am - IP Logged

                  OK TY Smiley

                  Let it Snow Snowman

                    CARBOB's avatar - FL LOTTERY_LOGO.png
                    ORLANDO, FLORIDA
                    United States
                    Member #4924
                    June 3, 2004
                    5914 Posts
                    Online
                    Posted: October 26, 2016, 12:10 pm - IP Logged

                    No, I think I should clarify.

                    Yesterday's Florida winning numbers were 973 and 059. 973 pairs=97 93 73.....059=05 09 59

                    After you make your combos, there should be NO combos on your list that have 97 93 73 05 09 59 in them.

                    For example, one of my combos at the end of my workout is 327. This combo should be deleted from my list because there's a 73 in it. It's basically another filter.

                    I hope that explains.

                    Thank you.

                      amber123's avatar - OpIFNim

                      United States
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                      March 12, 2015
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                      Posted: October 26, 2016, 2:54 pm - IP Logged

                      Florida mid winner today was 063. That would've been a winner. The 0 repeated from last night's winning number 059.

                      And 063 would've been included because it violated none of the rules.

                       

                      Tonight's prediction. https://www.lotterypost.com/thread/307258/4838453

                        SWMcCaig's avatar - 9b740053d1be538a3bed55bad1c5746d
                        Broken Arrow, OK
                        United States
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                        May 11, 2014
                        1875 Posts
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                        Posted: October 26, 2016, 2:57 pm - IP Logged

                        Hey Amber, great system, and thanks for sharing. Only one thing that I'm confused about....let's say the last two drawings were 123 and 456. Now, I understand that none of the PAIRS from either of these drawing can be used again in the workout, but do you get your PICKS from both of these drawings or only from the LAST drawing. in other words, would I ONLY use these:

                        10 thru 19

                        20 thru 29

                        30 thru 39

                        or would I ALSO use 40 thru 49, 50 thru 59, and 60 thru 69 to create picks for the next drawing? When I use BOTH sets, I come up with an average of about 46 combos to play, but only around 35 combos if I ONLY use the first set? Thanks again!

                        "What lies behind us and what lies before us are tiny matters compared to what lies within us"

                        Ralph Waldo Emerson

                          Sunglasses's avatar - nicebear
                          Zaperlopopotam
                          Belgium
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                          March 26, 2016
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                          Posted: October 26, 2016, 3:17 pm - IP Logged

                          Aware of the premise that most of the time at least one number from the previous winner shows in the next drawing has given me an idea that I never thought of until recently, and it was staring me in the face all this time...lol. So simple I overlooked it.

                          Here are the rules/filers: 

                           

                          A: No pairs from the last TWO draws. For example, 123 has 3 pairs...12-13-23. None of those pairs should be in your selections for the next drawing.

                          B: No combinations that are all high, or all low numbers.

                          C: No combinations that are all even, or all odd.

                          D: No doubles or triples.

                           

                          Take my second win out of three attempts. https://www.lotterypost.com/thread/307258/29

                          I used the last winning number midday in Florida today. The winner was 973, so I used the 9, the 7, and the 3.

                          Starting with the number 9 in 973, I realized there are only a certain amount of pairs hat can be made, thus reducing the cost. And no doubles...... For example...using the 9 example again, you have 09-19-29-39-49-59-69-79-89

                          So for our first group we use the 09. Our last two winning numbers in Florida were 194 and 973, so no pairs can be included from those two latest winning numbers.

                          Let's start the list for the first group,

                          The 9=09-19-29-39-49-59-69-79-89

                           

                          First the 09....so now we have one of the all possible pairs for the number 9, we must find the third digit. We don't want doubles, all low, all high, all even, all odd, so we use those filters when we make combos out of those pairs. 

                          Okay, our first pair is 09. We need a third digit. Let's start with 0. We can't use 0 because that would be 090, and that's a double, DISQUALIFIED!

                          Next number to pair with 09 is 1. 091 is also DISQUALIFIED...why? because one of the rules states that no pairs from the previous two winners can be included. Two draws prior, the winner was 194, and there goes the 19.

                           

                          Next is the 2 paired with the 09. 092 is a qualified combo to keep because it violates no rules whatsoever.

                          So we have 092. how about 093? Yes. it also qualifies, no rules broken.

                          092-093...094?...NOPE...why? because the pair in 094...94 was in last night's winner...194

                           

                          So we have 092 and 093...

                          Let's move on to 095..."Which btw was tonight's Florida winner which was on my list of predictions). of course 095 was kept for not breaking any of those rules stated above.

                           

                          096? Yes, no rules broken....092-093-095-096

                          097?...NOPE, today's mid winner was 973, the 97 pair disqualifies it. 

                          098? That's good to go, and finally 099 which is a no-no because it's a double.

                           

                          So far for the first group we have 092-093-095-096.

                           

                          Do this with the other two numbers to get all the numbers.

                          a) 123 456 eliminate all doubles from listed.
                          b)c)d) done

                          330 straight combinations left,
                          55 boxed combinations left.

                          I was generous picking 6 digits for two combinations.

                            Blackapple's avatar - nw rogue2.jpg
                            Wyncote,Pa
                            United States
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                            Posted: October 26, 2016, 4:52 pm - IP Logged

                            https://www.lotterypost.com/thread/152722/816410

                              Blackapple's avatar - nw rogue2.jpg
                              Wyncote,Pa
                              United States
                              Member #3206
                              January 3, 2004
                              60746 Posts
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                              Posted: October 26, 2016, 8:08 pm - IP Logged

                              A: No pairs from the last TWO draws.

                              I like it....helps focus on missing pairs

                               

                               

                              Tue, Oct 25, 2016   2-6-8    1-4-2

                              Most folk are familiar with

                              The 27 unhit Pick3 pairs after  142  hit  Pa.10/15 evening
                               
                              00 01 02 03 04 05 07 08 09
                              11 13 18
                              22 23 25 27 29
                              36 38 39
                              45 46
                              55 56 58
                              67
                              78
                              89
                               
                               
                               

                              0     16      019 028 037 046 055 118 136 226 235 127 299 389 145 569 578 677
                              1     17      001 029 038 047 056 119 137 128 227 236 245 399 146 155 588 678 489
                              2     17      002 011 039 048 057 138 228 237 255 129 336 345 246 156 589 679 778
                              3     16      003 012 049 058 067 139 148 229 238 256 247 346 445 355 788 689
                              4     16      004 013 022 059 077 068 112 158 239 257 356 338 455 446 167 789
                              5     16      005 014 023 078 069 113 168 122 258 267 249 366 348 339 456 889
                              6     18      006 015 024 033 079 088 114 123 178 259 277 367 358 349 457 466 556 899
                              7     17      007 016 025 034 089 115 133 188 223 278 269 368 359 458 467 557 566
                              8     19      008 017 026 035 044 099 116 134 189 224 233 125 279 369 378 459 468 558 567
                              9     17      009 018 027 036 045 117 135 225 234 289 388 379 469 559 568 667 478