For entertainment purposes only!
This is a method to generate a box sets for pick 3 games starting with one pick 3 selection as the seed. It's sort of like a very primitive pseudorandom number generator.
Step 1: Choose your seed. For this example, let's use 045.
Step 2: Mirror your seed. In this example, the mirror of 045 is 590.
Step 3: Mulitply the two numbers. In this example, 45 x 590 = 26550.
Step 4: Make all possible 3-digit sets using the digits of the number you got in Step 4. In this example, the sets are
025, 026, 055, 056, 255, 256, 556
These could be the box sets you play the next time you play pick 3. Here's a python script for it if you don't want to do it by hand:
# python 3 program for generating box combos from a seed and its mirror
def mirror_mult(a): # "a" is your pick 3 seed in quotes, like this "023"
m = ""
for i in range(len(a)):
m += str(int((5+int(a[i]))%10)) # creates mirror string
p = str(int(int(a)*int(m))) # product of a and m as numbers
while len(p)<3:
p = "0" + p # appends 0s to the front of p if necessary
plist_int = []
for i in range(len(p)):
plist_int.append(int(p[i]))
plist_int.sort()
pick_3 = []
for i in range(len(plist_int)):
for j in range(i+1,len(plist_int)):
for k in range(j+1,len(plist_int)):
tempstr = ""
tempstr += str(plist_int[i])+str(plist_int[j])+str(plist_int[k])
pick_3.append(tempstr) # all 3-digit box combos from digits of p
pick_3_list = list(set(pick_3)) # set function removes duplicate box combos
pick_3_list2 = sorted(pick_3_list, key = lambda x: float(x)) # box combos ordered numerically
print(pick_3_list2)
mirror_mult("045")
Here are a few more examples
Seed 441: ['233', '234', '236', '239', '246', '249', '269', '334', '336', '339', '346', '349', '369', '469']
Seed 789: ['124', '126', '128', '146', '148', '166', '168', '246', '248', '266', '268', '466', '468', '668']
Seed 102: ['014', '016', '017', '046', '047', '067', '146', '147', '167', '467']
No guarantees that this will help you beat the odds, just a method for generating pseudorandom numbers.