Best way to find next pair in pick 3 or pick 4Prev Topic Next Topic

New Topic New Poll

pick3master0267

United States
Member #179,896
February 11, 2017
135 Posts
Offline

Nov 3, 2018, 8:02 pm

Good for pick 3 and pick 4
pick3master0267

United States
Member #179,896
February 11, 2017
135 Posts
Offline

Nov 3, 2018, 8:03 pm

A pair appear within three draw.

Take last result.

For non double it work like this

For : last result which equal too..

Non mirror pair, non straight pair,
non all even combo, non all odd combo

Example if hit result is = 369, 074, 259, 148, 269, 037.

Expected hit pair within 3 days.

A) 369 = 31, 34, 68, 64, 91, 98 pairs to play

B) 074 = 02, 09, 75, 79, 42, 45 pairs to play

C) 148 = 19, 13, 46, 43, 89, 86 pairs to play

D) 269 = 21, 24, 67, 64, 91, 97 pairs to play

E) 037 = 08, 02, 35, 32, 75, 78 pairs to play

How we look at it?

If a pair fall within these group in recent draw.

369 = pair 36, 69, 39 we play pair in group A
074 = pair 07, 74, 94 we play pair in group B
148 = pair 14, 48, 18 we play pair in group C
269 = pair 26, 69, 29 we play pair in group D
037 = pair 03, 37, 07 we play pair in group E
angelchick

United States
Member #187,574
January 31, 2018
667 Posts
Offline

Nov 3, 2018, 8:27 pm

I have some questions for you pick3master.

What if 589 come out?.... Which pairs should I play?
oate

United States
Member #193,169
October 22, 2018
489 Posts
Offline

Nov 3, 2018, 8:44 pm

Quote: Originally posted by angelchick on Nov 3, 2018
I have some questions for you pick3master.

What if 589 come out?.... Which pairs should I play?

According to Pick3master, your seed value of 589 generates the pairs 53, 54, 80, 84, 90, 93.

Here is a python script to automate it. It will also work for doubles and triples, you will just need to disregard the repeats.

def mirror_pairs(a): # "a" is your pick 3 seed in quotes, like this "023"
a_digits = [a[0], a[1], a[2]]
m_digits = [str((int(a[0])+5)%10), str((int(a[1])+5)%10), str((int(a[2])+5)%10)]
pick3pairs = []
for i in range(3):
for j in range(3):
if j != i:
pick3pairs.append(a_digits[i]+m_digits[j])
print(pick3pairs)

Only my hairdresser knows for sure.
pick3master0267

United States
Member #179,896
February 11, 2017
135 Posts
Offline

Nov 3, 2018, 9:56 pm

Quote: Originally posted by oate on Nov 3, 2018
According to Pick3master, your seed value of 589 generates the pairs 53, 54, 80, 84, 90, 93.

Here is a python script to automate it. It will also work for doubles and triples, you will just need to disregard the repeats.

def mirror_pairs(a): # "a" is your pick 3 seed in quotes, like this "023"
a_digits = [a[0], a[1], a[2]]
m_digits = [str((int(a[0])+5)%10), str((int(a[1])+5)%10), str((int(a[2])+5)%10)]
pick3pairs = []
for i in range(3):
for j in range(3):
if j != i:
pick3pairs.append(a_digits[i]+m_digits[j])
print(pick3pairs)

No that's not what you do.

589, we have a straight pair in 89. We skip until there we find a non pair mirror, none straight, none all even combo, ex. 246 or none all odd combo, ex 135.

Find a pair that relate to the combo I mention. That's it. No math involve. C'mon this so easy to follow. This is really simple. I did the pairing you just have to locate it. And I show you how.
oate

United States
Member #193,169
October 22, 2018
489 Posts
Offline

Nov 3, 2018, 11:45 pm

Your algorithm for generating pairs from a 3-digit seed works for any seed, regardless of whether they have consecutive digits, all even digits, all odd digits, or mirror pairs. It's simple arithmetic.

Avoiding numbers with consecutive digits, all evens, all odds, or mirrored pairs is a personal choice that you are free to make for yourself.

Once you put a lottery system out there, people are free to apply it however they like, including apply it to numbers that you personally avoid out of superstition.

Best of luck to you in the next pick 3 drawing.

Only my hairdresser knows for sure.
lakerben

50

New Mexico
United States
Member #86,096
January 29, 2010
24,966 Posts
Offline

Nov 4, 2018, 12:41 am

Quote: Originally posted by oate on Nov 3, 2018
Your algorithm for generating pairs from a 3-digit seed works for any seed, regardless of whether they have consecutive digits, all even digits, all odd digits, or mirror pairs. It's simple arithmetic.

Avoiding numbers with consecutive digits, all evens, all odds, or mirrored pairs is a personal choice that you are free to make for yourself.

Once you put a lottery system out there, people are free to apply it however they like, including apply it to numbers that you personally avoid out of superstition.

Best of luck to you in the next pick 3 drawing.

Is it possible to post this already compiled?

Say hey!
angelchick

United States
Member #187,574
January 31, 2018
667 Posts
Offline

Nov 4, 2018, 7:41 am

Quote: Originally posted by pick3master0267 on Nov 3, 2018
No that's not what you do.

589, we have a straight pair in 89. We skip until there we find a non pair mirror, none straight, none all even combo, ex. 246 or none all odd combo, ex 135.

Find a pair that relate to the combo I mention. That's it. No math involve. C'mon this so easy to follow. This is really simple. I did the pairing you just have to locate it. And I show you how.

Thank you Pick3master.

I will wait until one of the five combos come out to choose a pair.
oate

United States
Member #193,169
October 22, 2018
489 Posts
Offline

Nov 4, 2018, 1:34 pm

Quote: Originally posted by lakerben on Nov 4, 2018
Is it possible to post this already compiled?

Happy Sunday to you, lakerben.

To compile it, copy and paste the code it into notepad, then add the line mirror_pairs("723") at the end, (replace 723 with whatever number you want but keep the quotes), then save it as a .py file. Then you can run it from command prompt the usual way you run your python programs.

winsumloosesum knows how to write the excel macros and maybe he can convert it to a spreadsheet document and post online for downloading.

Only my hairdresser knows for sure.
lakerben

50

New Mexico
United States
Member #86,096
January 29, 2010
24,966 Posts
Offline

Nov 4, 2018, 3:13 pm

Quote: Originally posted by oate on Nov 4, 2018
Happy Sunday to you, lakerben.

To compile it, copy and paste the code it into notepad, then add the line mirror_pairs("723") at the end, (replace 723 with whatever number you want but keep the quotes), then save it as a .py file. Then you can run it from command prompt the usual way you run your python programs.

winsumloosesum knows how to write the excel macros and maybe he can convert it to a spreadsheet document and post online for downloading.

Say hey!
deebo2018

United States
Member #187,024
January 9, 2018
919 Posts
Offline

Nov 10, 2018, 1:15 pm

Quote: Originally posted by pick3master0267 on Nov 3, 2018
A pair appear within three draw.

Take last result.

For non double it work like this

For : last result which equal too..

Non mirror pair, non straight pair,
non all even combo, non all odd combo

Example if hit result is = 369, 074, 259, 148, 269, 037.

Expected hit pair within 3 days.

A) 369 = 31, 34, 68, 64, 91, 98 pairs to play

B) 074 = 02, 09, 75, 79, 42, 45 pairs to play

C) 148 = 19, 13, 46, 43, 89, 86 pairs to play

D) 269 = 21, 24, 67, 64, 91, 97 pairs to play

E) 037 = 08, 02, 35, 32, 75, 78 pairs to play

How we look at it?

If a pair fall within these group in recent draw.

369 = pair 36, 69, 39 we play pair in group A
074 = pair 07, 74, 94 we play pair in group B
148 = pair 14, 48, 18 we play pair in group C
269 = pair 26, 69, 29 we play pair in group D
037 = pair 03, 37, 07 we play pair in group E

How we look at it?

If a pair fall within these group in recent draw.

369 = pair 36, 69, 39 we play pair in group A
074 = pair 07, 74, 49 we play pair in group B
148 = pair 14, 48, 18 we play pair in group C
269 = pair 26, 69, 29 we play pair in group D
037 = pair 03, 37, 07 we play pair in group E

do dat 49 suppose to be par 04

New Topic New Poll

Subscribe to this topic

Best way to find next pair in pick 3 or pick 4Prev TopicNext Topic

Best way to find next pair in pick 3 or pick 4Prev Topic Next Topic