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dr san

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Jul 18, 2019, 10:45 am

how to rate the best criteria
of taking advantage of a lottery?
then from the database of the sweepstakes
even the best filters are those criteria
which gives the best answer in a lottery system
would it have to create an evolutionary algorithm of analysis of better uses? please
Todd

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Jul 18, 2019, 12:48 pm

<Moved to Lottery Discussion forum>

Please post in the appropriate forum ... thank you.

The Systems forum is only for the discussion of specific systems. It is not for discussing systems in general, concepts that might be used in a system, or for requesting systems. Thanks for your help in keeping the forums organized properly by posting the the proper forum!
garyo1954

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Jul 18, 2019, 4:15 pm

Quote: Originally posted by dr san on Jul 18, 2019
how to rate the best criteria
of taking advantage of a lottery?
then from the database of the sweepstakes
even the best filters are those criteria
which gives the best answer in a lottery system
would it have to create an evolutionary algorithm of analysis of better uses? please

What do you consider the best criteria?

G

I'm probably here unless I'm not.
Dreaming would be a perfectly useless function if it's only purpose was to entertain.
Stack47

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Jul 18, 2019, 8:49 pm

Quote: Originally posted by dr san on Jul 18, 2019
how to rate the best criteria
of taking advantage of a lottery?
then from the database of the sweepstakes
even the best filters are those criteria
which gives the best answer in a lottery system
would it have to create an evolutionary algorithm of analysis of better uses? please

Almost every US Lottery keeps around 50% based on the payoffs. For instance, a pick-3 straight pays $500 for $1, but the odds against catching a straight is 1000 to 1. There is also the overall chance of winning something that varies from game to game. PB and MM both have around a 1 in 24 chance and only slightly lower than the 1 in 22 most All-or-Nothing games give.

In poker some players get an advantage over other players and why a judge ruled it was a "game of skill". However with lottery games and casino games, the house always has the advantage.

So we can rate the best or any criteria, can you tell us what you believe is an advantage worth exploiting?
dr san

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Jul 19, 2019, 7:57 am

hello,STACK47 I think trying the hit
of the first digits or numbers
Let's see an example
on pick3
478 = 1st digit is 4 then you have 401 to 499
to filter if it hits the digtio 4 is inside
if it is out, then in pick3 the 1st digit is important, in spick 5.6, also
ex = pick is fundamentally important hits the first two numbers, example
on pick 6,49 / 6 = 05 12 if you hit 05 12
the remaining 4 numbers will follow
of deltas, pair; odd number with the initial double 05 12, etc., a multitude of filters of the initial reference of the sequences, but if you miss the two numbers you initially lose, you can set up a study of the first numbers
JeetKuneDoLotto

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Jul 20, 2019, 12:06 am

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Stack47

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Jul 22, 2019, 7:05 pm

Quote: Originally posted by dr san on Jul 19, 2019
hello,STACK47 I think trying the hit
of the first digits or numbers
Let's see an example
on pick3
478 = 1st digit is 4 then you have 401 to 499
to filter if it hits the digtio 4 is inside
if it is out, then in pick3 the 1st digit is important, in spick 5.6, also
ex = pick is fundamentally important hits the first two numbers, example
on pick 6,49 / 6 = 05 12 if you hit 05 12
the remaining 4 numbers will follow
of deltas, pair; odd number with the initial double 05 12, etc., a multitude of filters of the initial reference of the sequences, but if you miss the two numbers you initially lose, you can set up a study of the first numbers

Maybe it got lost in the translation, but I asked for a definition about the "advantage" you mentioned.

Knowing which digit will be drawn in the first or any position is an advantage, but can only get a 4 to 1 payoff on 100 to 1 odds wager. And "knowing which digit" is not as easy as you make it sound. I don't see it as being much of an advantage, but you could create ten lines using each digit from the first or any digit position and get 100 to 1 odds and certainly an advantage over playing hundred lines.

Are you asking for a criteria for finding something you think is an advantage?
dr san

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Jul 22, 2019, 7:34 pm

ok if you could use the criterion of 3 frequencies in each position or column, 50% 35% 15%
hot / medium and cold in a given number of sweepstakes ex = 10 to 12 last pick3 sweepstakes
helps you search the 1st digits
the 1st can also be what repeats in 67% a digit repeats
ex 471 = if you know it is the 4th
you have 401 to 499 one hundred number to filter,
see the importance of 1st digits
Stack47

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Jul 23, 2019, 11:21 pm

Quote: Originally posted by dr san on Jul 22, 2019
ok if you could use the criterion of 3 frequencies in each position or column, 50% 35% 15%
hot / medium and cold in a given number of sweepstakes ex = 10 to 12 last pick3 sweepstakes
helps you search the 1st digits
the 1st can also be what repeats in 67% a digit repeats
ex 471 = if you know it is the 4th
you have 401 to 499 one hundred number to filter,
see the importance of 1st digits

You asked about "taking an advantage" and unless the balls used in your drawings have memories, past drawing frequencies are not even close. Is there a difference between using high/low, even/odd or hot/medium/cold?

There is a topic about using "gaps" and considering there are only 10 possible gaps between the first and second digit and another 10 between the second and third, examining that potential IMO makes more sense than most filters.

"the 1st can also be what repeats in 67% a digit repeats"

Each digit has a 10% chance of repeating. Where did you get "67%" from?
dr san

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Jul 24, 2019, 6:47 am

hello, STACK47 the 67% repetition is not in 1st position but in any of the three
positions, and probabilities of repeating in the same position as the last draw, is 10%, so ex
457
589 = digit repeated but not in 2nd position of last, so digit 5 could only be 1st or last
this deserves study and filters, we have to create a system to predict the 1st digits of pick3, the frequency repetition, cycle, delay, are good ingredients for a system to find the 1st digits of pick3,
Stack47

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Jul 24, 2019, 10:08 am

Quote: Originally posted by dr san on Jul 24, 2019
hello, STACK47 the 67% repetition is not in 1st position but in any of the three
positions, and probabilities of repeating in the same position as the last draw, is 10%, so ex
457
589 = digit repeated but not in 2nd position of last, so digit 5 could only be 1st or last
this deserves study and filters, we have to create a system to predict the 1st digits of pick3, the frequency repetition, cycle, delay, are good ingredients for a system to find the 1st digits of pick3,

Here we go again.

"on pick3 478 = 1st digit is 4 then you have 401 to 499"

Because of how live ball drawings are held, IE usually three machines each with ten numbered balls from 0 to 9 that produce three different digit positions, a digit in another digit position is not the same digit.

"the 67% repetition is not in 1st position but in any of the three positions"

I'm not sure you understand how many three digit combos can be created using all three digits from the previous drawing. And suggesting picking one of the three gives a 33% chance of picking the correct in 67% of the drawings is not creating an advantage.
dr san

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Jul 24, 2019, 3:02 pm

hello STACK47 In a 3 digit game there are 1000 combinations of numbers. That means that roughly once every 100 drawings the same last two digits will appears in a drawing. The first digit then has a 1 in 10 chance of appearing every time that pair shows.

So if you want to know the most likely pairs to appear in the next 1-25 drawings, look at the last few 100-150 drawings until there are 25 remaining pair that have not yet appeared. There is a reasonably good chance that one of them will appear.

Once you have isolated that pair look at the last 5 drawings where that pair has appeared and since which 1st digit that it appeared with. You will probably wind up with 5-7 digits for you to choose from that have not yet appeared with that pair. And you can probably use some other methodology based on how many times that number has appeared with other pairs in the last X drawings to reduce your choice down to 2-3 numbers.

If you want to factor the number of times that digit was odd versus even as a means of narrowing own your choices you can certainly do that, but in the end all you are doing is widening the number of drawings that it will take for that pattern to reappear.

The more conditions used to define the strategy, the larger the window between drawings when that pattern has a chance of winning. There is no way to circumvent that which is what keeps the lotteries in business.

If you play all odd or all even numbers there are 250 combinations where the numbers are all odd or all even. There are only 50 pairs where the last two digits are all odds or all even. This means roughly once every four drawings you will see that kind of result, no system is going to alter that fact although in the short term there may be times when it occurs once every two drawing or once every ten.
adobea78

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Jul 24, 2019, 6:10 pm

Quote: Originally posted by dr san on Jul 24, 2019
hello STACK47 In a 3 digit game there are 1000 combinations of numbers. That means that roughly once every 100 drawings the same last two digits will appears in a drawing. The first digit then has a 1 in 10 chance of appearing every time that pair shows.

So if you want to know the most likely pairs to appear in the next 1-25 drawings, look at the last few 100-150 drawings until there are 25 remaining pair that have not yet appeared. There is a reasonably good chance that one of them will appear.

Once you have isolated that pair look at the last 5 drawings where that pair has appeared and since which 1st digit that it appeared with. You will probably wind up with 5-7 digits for you to choose from that have not yet appeared with that pair. And you can probably use some other methodology based on how many times that number has appeared with other pairs in the last X drawings to reduce your choice down to 2-3 numbers.

If you want to factor the number of times that digit was odd versus even as a means of narrowing own your choices you can certainly do that, but in the end all you are doing is widening the number of drawings that it will take for that pattern to reappear.

The more conditions used to define the strategy, the larger the window between drawings when that pattern has a chance of winning. There is no way to circumvent that which is what keeps the lotteries in business.

If you play all odd or all even numbers there are 250 combinations where the numbers are all odd or all even. There are only 50 pairs where the last two digits are all odds or all even. This means roughly once every four drawings you will see that kind of result, no system is going to alter that fact although in the short term there may be times when it occurs once every two drawing or once every ten.

However you slice it, the game is random!. Random is a central issue which many try to avoid.

You can add/subtract, sum up, root etc for any logical formula, it will not help .Understanding randomness is critical.
dr san

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Jul 25, 2019, 12:01 pm

adobea78 we have to divide the enemy to weaken it and attack on its weaknesses, ie divide the lottery into sectors
Stack47

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Jul 28, 2019, 10:30 pm

Quote: Originally posted by dr san on Jul 25, 2019
adobea78 we have to divide the enemy to weaken it and attack on its weaknesses, ie divide the lottery into sectors

State and national lottery games are designed to give the lotteries a significant edge and in most the edge is usually at least 50%. Even if we divide the odds in half, we can only expect to break even.

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