how to use the statistical universe in lotteries?Prev TopicNext Topic

• dr san

  

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  May 13, 2021, 8:59 pm

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  how to use the statistical universe in lotteries?
  is the hot cold parameter ideal, or do we need to cross more strategies?
• BobP

  

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  May 14, 2021, 1:52 am

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  In response to dr san

  Quote: Originally posted by dr san on May 13, 2021

  how to use the statistical universe in lotteries?
  is the hot cold parameter ideal, or do we need to cross more strategies?

  I'm not touching the "statistical universe" thingie beyond saying it's an eliptoid spheroid full of combinations.
  
  Hot cold is not ideal, you want hot, average, cold and it's just a filter set among many that improve your chances when correct and eliminate them when wrong. 
  
  BobP  
• Stat$talker

  

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  In response to BobP

  Quote: Originally posted by BobP on May 14, 2021

  I'm not touching the "statistical universe" thingie beyond saying it's an eliptoid spheroid full of combinations.
  
  Hot cold is not ideal, you want hot, average, cold and it's just a filter set among many that improve your chances when correct and eliminate them when wrong. 
  
  BobP  

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• Speler

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  Three groups? The winning numbers can come from one, two or all three groups. If you add more patterns, they all must be right to win the first prize. It would be simpler to pick the correct numbers immediately and not think about patterns?
• dr san

  

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  hello speller, but defaults is a way to reduce and then filter by columns, well then we can use the veen graph, to avoid conflict in the filters?
• Speler

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  John Venn's? You can can draw it in your paintshop pro or in paint.exe?
• Speler

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  Quote: Originally posted by dr san on May 14, 2021

  hello speller, but defaults is a way to reduce and then filter by columns, well then we can use the veen graph, to avoid conflict in the filters?

  You can do the opposite, you filter first and reduce afterwards by picking lines of running a program to keep a coverage, as you probably fail to do good by picking. And you forget about the graph.
• dr san

  

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  May 14, 2021, 8:27 am

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  hello speller, to avoid conflict in the lottery filters you must create the veen chart! OK! in fact speller is a good job, it is to make the graph of veen to avoid conflict in the lottery filters
• Speler

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  I want to see your veenbes graph on a worked out case.
• dr san

  

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  May 14, 2021, 2:42 pm

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  Set A: numbers divisible by 2
  2,4,6,8,10,12,14,16,18,20,22,24
  
  Set B: numbers divisible by 3
  3,6,9,12,15,18,21,24
  
  Overlap:
  6,12,18,24
  
  en.wikipedia.org/wiki/Venn_diagram
  pt.wikipedia.org/wiki/Diagrama_de_Venn

  Using two filters and a 2-circle venn diagram, you'll need three numbers:
  The hit ratio of the first filter, the hit ratio of the second filter, and the hit ratio of both filters when used together.
  
  The first ratio goes in one crescent, the second goes in the other crescent, and the third number goes in the overlapping oval.
  
  How the measured overlap compares to the mathematically expected overlap tells you whether or not to use those two filters together or at all.
  
   Example: Filter A has hit ratio 0.5 and filter B has hit ratio 0.333.
  If the measured combined (oval) hit ratio is less than 1/6, the two filters shouldn't be used together.

  speller, my lottery (one of them) uses from 01 to 25 where 15 numbers (lotofacil) are drawn, can you put some filters on the graph of veen?
• dr san

  

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  https://en.wikipedia.org/wiki/File:Venn3tab.svg
• Speler

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  A = {2; ... }

  B = {3; ... }

  A ∩ B = {6; ... }

  6 mod 2 == 0 && 6 mod 3 == 0

  6 ≡ ...
• Speler

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  May 14, 2021, 6:17 pm

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  "speller, my lottery (one of them) uses from 01 to 25 where 15 numbers (lotofacil) are drawn, can you put some filters on the graph of veenbes ¿"

  You need 15 numbers. You have A union B so far. Do you have 15 numbers ¿
• BobP

  

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  In response to Speler

  Quote: Originally posted by Speler on May 14, 2021

  Three groups? The winning numbers can come from one, two or all three groups. If you add more patterns, they all must be right to win the first prize. It would be simpler to pick the correct numbers immediately and not think about patterns?

  Agreed it is possible all the winning numbers can all come from one, two or all three groups, though it is 2-2-2 that is most probable. 
  
  http://web.archive.org/web/20050126053842/http://www.geocities.com/wallstreet/7746/hwc.html
  
  BobP
• Speler

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  6/45

  3 groups of 15 numbers.

  15	15	15	Combin	Combin	Combin	Product * Order	p	1/p
  2	2	2	105	105	105	1157625	0.14	7.04
  3	2	1	455	105	15	4299750	0.53	1.89
  3	3	0	455	455	1	621075	0.08	13.11
  4	1	1	1365	15	15	921375	0.11	8.84
  4	2	0	1365	105	1	859950	0.11	9.47
  5	1	0	3003	15	1	270270	0.03	30.14
  6	0	0	5005	1	1	15015	0	542.46
  Check SUM:	8145060

   

  Fractions rounded: 0.00