**Quote:** Originally posted by EC$JM! on Aug 8, 2024

Hey everyone,

been awhile since i posted, but I've been following along silently. Thought I would share something that I noticed as far as narrowing down which version of a number to play. This is something I use to cut down how much I spend per number. I don't know if it's ever been posted before, but it does work overall more times than not. Let's use 372 as an example. I had this number straight, but one day too early and missed it. As you know, there are 6 possible versions of any number that has no repeating numbers. What I do is use page 1 and 2 of the previous winning numbers list on the CA lottery website, and find the pairs pertaining to the number I like.

So for 372 those were 37(from 371), 27(from 276), and 72(from 720)....In this instance, the 72 was on the third page. Ideally, you want the first three pairs, so every once in awhile, you may have to go to the third page for the third pair. So with the first three pairs you want to use them as they fell without rearranging their order...if you do that you will only get 3 possible plays...327, **372**, 237....this allows you to play $3 straight or straight/boxed instead of $6...most times I double up on the same 3 numbers to score bigger.

Last nights 176...if you look there were 5 pairs to draw from the first 2 pages....**76**, **71**, **16**, 61, 67...if you only use the first 3 you will get 761, 716, **176..**

With 539 there were four pairs....**59**, **39,** **95**, 53....which gives you **539**, 359, 395

059 is an example of where it did not work...showing a possible five pairs..90, 09, 95, 50, 05...it's still in there, just not in the first three pairs...if i really like a number in this situation i will just play all 6 ways.

Anyways, nothing is 100%, but hopefully this helps some of you win more and spend less. As always back test any theories to see if it works for you.