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# Lottery odds by removing combinations?Prev TopicNext Topic

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• Seattle, WA
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December 26, 2021
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Lets say you want to remove a set of combinations, for example a single pair, "1,5". Or a triple, "1,5,15", etc. How would you calculate the odds by removing certain combinations, is there a formula or website you can do it with?

• 700 light yrs West of Milky Way Galaxy's Center
United States
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September 1, 2019
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Quote: Originally posted by loser777 on Sep 2, 2024

Lets say you want to remove a set of combinations, for example a single pair, "1,5". Or a triple, "1,5,15", etc. How would you calculate the odds by removing certain combinations, is there a formula or website you can do it with?

"How would you calculate the odds by removing certain combinations,"

It'z not the pairs  or triplez that count in the probabilitiez.. It'z the remaing numberz used AFTER removement verses the Total numberz in the Game'z POOL..that determinez the Probability,... it also helpz approximately %,..if you uze the Math of a  Stat\$talker....

• United States
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August 12, 2024
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Statstalker...are you a lotto official?  Lotto officials are statstalkers. So statstalker is a lotto official. "As above...so below"

• Kentucky
United States
Member #32,651
February 14, 2006
10,375 Posts
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Quote: Originally posted by loser777 on Sep 2, 2024

Lets say you want to remove a set of combinations, for example a single pair, "1,5". Or a triple, "1,5,15", etc. How would you calculate the odds by removing certain combinations, is there a formula or website you can do it with?

Back in the day when all pick 5, 5 + 1,  and 6 tickets were a \$1, played abbreviated wheels that included eliminating numbers and obviously the combos they are in. My favorite was a 14 number 3 if 4 wheel with 19 lines I used playing Ohio's 5/39 Rolling Cash game. Winning the jackpot meant none of the 25 numbers I wasn't using could be drawn.

A full 14 number pick 5 wheel has 2002 combinations so the odds of one of those combos being drawn are 2002 divided by the total of the 575,757 possible combos, ,034% or 1 in 288 chance the five numbers drawn will be included in the 14 number in the wheel. That creates a new set of odds because with only 19 of the possible 2002 combos, the odds against winning the jackpot if all five drawn numbers are in the 14 number group are 1 in 105. So after beating odds 288 to 1, I still had to beat odd of 105 to 1.

The pair 1 and 5 are in 7770 of the 575,757 5/39 game combinations and the triple 1-5-15 has 210 combos.  By removing 7770 pairs, subtract it from the total possible combos and do the same with 210 the triples and than divide that by the total combos.

Knew a co-worker that keyed on three numbers. played them with pairing the other 36 numbers in 18 combos, and hit the jackpot.

"Some people have something to say while other people feel the need to say something"

• United States
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August 12, 2024
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Holy crap!!

• Kentucky
United States
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February 14, 2006
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Quote: Originally posted by metafortune77 on Sep 2, 2024

Statstalker...are you a lotto official?  Lotto officials are statstalkers. So statstalker is a lotto official. "As above...so below"

"It'z the remaing numberz used AFTER removement verses the Total numberz in the Game'z POOL..that determinez the  Probability"

If three numbers are removed from 5/39 game or any pick 5 game, it's a fact five of the remaining numbers will be drawn. But if saying there is a "100% probability" makes you feel smarter, go for it.

"Some people have something to say while other people feel the need to say something"

• Kentucky
United States
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February 14, 2006
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Quote: Originally posted by metafortune77 on Sep 2, 2024

Holy crap!!

Abbreviated wheels are mostly designed for guaranteeing winning smaller prizes so the odds against are much smaller.

"Some people have something to say while other people feel the need to say something"

• 700 light yrs West of Milky Way Galaxy's Center
United States
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September 1, 2019
4,349 Posts
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Quote: Originally posted by metafortune77 on Sep 2, 2024

Statstalker...are you a lotto official?  Lotto officials are statstalkers. So statstalker is a lotto official. "As above...so below"

"Statstalker...are you a lotto official?"

Daammn Naaaww..!!

They couldn't GIVE me a job down there @ Hdqrts... How daaare you insult MEEE wit such Garbage.!

Naah on da uther hand, you'd be moe on track, suspecting dat cottoneyedjoe, or Texez 2 Stepper ((who got investmenz in the Industry) than Ole Stat\$...

I'm in da trenchez wit my comradez, at War wit The   "BEAST"  BaBy..!!

-Stat\$talker

• 700 light yrs West of Milky Way Galaxy's Center
United States
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September 1, 2019
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Quote: Originally posted by Stack47 on Sep 2, 2024

"It'z the remaing numberz used AFTER removement verses the Total numberz in the Game'z POOL..that determinez the  Probability"

If three numbers are removed from 5/39 game or any pick 5 game, it's a fact five of the remaining numbers will be drawn. But if saying there is a "100% probability" makes you feel smarter, go for it.

"But if saying there is a "100% probability" makes you feel smarter, go for it."

YOU just Luuuvv takin pot-shotz at Me..don"t cha ?

THAT one , wuz across MY bow, even tho ya replied to metafortune77...

• 100
Texas
United States
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October 23, 2007
18,592 Posts
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Quote: Originally posted by Stack47 on Sep 2, 2024

Back in the day when all pick 5, 5 + 1,  and 6 tickets were a \$1, played abbreviated wheels that included eliminating numbers and obviously the combos they are in. My favorite was a 14 number 3 if 4 wheel with 19 lines I used playing Ohio's 5/39 Rolling Cash game. Winning the jackpot meant none of the 25 numbers I wasn't using could be drawn.

A full 14 number pick 5 wheel has 2002 combinations so the odds of one of those combos being drawn are 2002 divided by the total of the 575,757 possible combos, ,034% or 1 in 288 chance the five numbers drawn will be included in the 14 number in the wheel. That creates a new set of odds because with only 19 of the possible 2002 combos, the odds against winning the jackpot if all five drawn numbers are in the 14 number group are 1 in 105. So after beating odds 288 to 1, I still had to beat odd of 105 to 1.

The pair 1 and 5 are in 7770 of the 575,757 5/39 game combinations and the triple 1-5-15 has 210 combos.  By removing 7770 pairs, subtract it from the total possible combos and do the same with 210 the triples and than divide that by the total combos.

Knew a co-worker that keyed on three numbers. played them with pairing the other 36 numbers in 18 combos, and hit the jackpot.

Now THAT  was an intelligent answer.

CAN'T WIN IF YOU'RE NOT IN

A DOLLAR AND A DREAM (OR \$2)

JUST LOOK AT THE ODDS OF ANY JACKPOT GAME, THAT WILL TELL YOU EVERYTHING YOU NEED TO KNOW

• United States
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August 12, 2024
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I got my answer for sure

• Kentucky
United States
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February 14, 2006
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Quote: Originally posted by rcbbuckeye on Sep 2, 2024

Now THAT  was an intelligent answer.

Thanks.

When the Ohio Lotto was 6/44 and two lines for a buck, wrote down all the numbers, mixed them up, and created combos by drawing each number one at a time. Cost \$4 for eight lines. About a month later caught 5 out of 6 and won just under \$900, Games have changed and costs have made playing wheels almost obsolete.

The pick 5 games that pay \$1 for matching two and \$10 for matching three, are still worth wheeling.

"Some people have something to say while other people feel the need to say something"

• Ohio
United States
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December 3, 2018
505 Posts
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I remember reading if 5's were removed from a shoe playing blackjack. It would help the player statistically. I wonder if it would be beneficial if we could eliminate numbers that have just ran a hot streak or haven't hit in 25 draws or so. The hot streak could be from 8 to 10 hits in 20 draws. 37 hit 9 times in 20 draws. It hasn't hit last 13 draws in the rolling cash five. 25 is coldest number. Out 33 draws. There's my two. Anyone have any other suggestions. I have pattern eliminators. Say there's 10 numbers that have hit one time in last 20 draws. I have percentages for 1,2 or 3 hitting from those ten 1 counts ... 43.9%/28.5%/6.1%. I break each count down that way.

GET IT DONE

• Kentucky
United States
Member #32,651
February 14, 2006
10,375 Posts
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Quote: Originally posted by Cmoore50 on Sep 5, 2024

I remember reading if 5's were removed from a shoe playing blackjack. It would help the player statistically. I wonder if it would be beneficial if we could eliminate numbers that have just ran a hot streak or haven't hit in 25 draws or so. The hot streak could be from 8 to 10 hits in 20 draws. 37 hit 9 times in 20 draws. It hasn't hit last 13 draws in the rolling cash five. 25 is coldest number. Out 33 draws. There's my two. Anyone have any other suggestions. I have pattern eliminators. Say there's 10 numbers that have hit one time in last 20 draws. I have percentages for 1,2 or 3 hitting from those ten 1 counts ... 43.9%/28.5%/6.1%. I break each count down that way.

Edward O Thorp wasn't the first to explore Blackjack card counting, was one of the more famous and he mentioned the effect if fives were removed from the deck. If all four fives were dealt on the first hand from a single deck, players would have a huge advantage. Comparing that to lottery drawings is like shuffling the deck after every hand.

One of the first PC lottery programs I had was based on hot and cold numbers. It was a designed to place the favored hot and cold numbers into wheels. Hit lots of 4 of 6 using it.

"Some people have something to say while other people feel the need to say something"

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