Thank you for sharing. I expanded on your system quite a bit. Instead of picking numbers directly from pyramid in a diagonal/line/etc, I'm going to see if there is a way we can methodically extract the winning numbers using the pyramid's numbers and, of course, math. I made these pyramids alongside AI because my eyes were straining to pick out all the numbers, so I pray it's all correct. Relevant numbers are underlined and drawn lotto numbers are bolded, italicized, and underlined.
Super Pπ Pyramid System
Detecting PB 12/7 with 12/4 numbers
12/4: 1 - 23 - 25 - 28 - 61 + 13
12,325,286,113 × π
38721028305.99309820056491596120619329613881915202654265316794870451597617375297767420575368526957597202064674261168100416603335477387369835174912034293986763669270861893686863236211169496444787
12/7: 1 - 31 - 43 - 55 - 57 + 22
99
30 98
20 05 64
91 59 61 20
61 93 29 61 38
81 91 52 02 65 42
65 31 67 94 87 04 51
59 76 17 37 52 97 76 74
20 57 53 68 52 69 57 59 72
02 06 46 74 26 11 68 10 04 16
60 33 35 47 73 87 36 98 35 17 49
12 03 42 93 98 67 63 66 92 70 86 18
93 68 68 63 23 62 11 16 94 96 44 47 87
100 - 99 = 1 OR 99 - 98 = 1
> three ones in first column together - indicator?
30 + 1 = 31
51 + 4 (ones of 74) = 55
49 + 6 (ones of 16) = 55
87 - 1 = 86 / 2 = 43
47 - 4 = 43
42 + 1 = 43
20 + 2 = 22
100 - 69 = 31
** btw 43 + 57 = 100 **
Honorable Mentions:
64 - 2 (tenths of 20) = 62 (one above 61)
20 + 38 = 58 (one above 57)
16 + 49 = 65 (10 above 55)
49 + 18 = 67 (10 above 57)
The hardest to find for me was the white ball 31 and powerball 22. I would've liked to have more ways to extract them both.
Predicting PB 12/4 with 12/2 numbers
12/2: 3 - 9 - 26 - 61 - 67 + 13
3,926,616,713 × π
12335830219.0237015763618099349441607754203089508784622727838033904048431414590265154238356155343928219412598621440242017676696831232862756099736350778890820070852015042676402544715937377948119497
12/4: 1 - 23 - 25 - 28 - 61 + 13
02
37 01
57 63 61
80 99 34 94
41 60 77 54 20
30 89 50 87 84 62
27 27 83 80 33 90 40
48 43 14 14 59 02 65 15
42 38 35 61 55 34 39 28 21
94 12 59 86 21 44 02 42 01 76
76 69 68 31 23 28 62 75 60 99 73
63 50 77 88 90 82 00 70 85 20 15 04
26 76 40 25 44 71 59 37 37 79 48 11 94
2 - 1 = 1
26 - 1 = 25
26 / 2 = 13
27 + 1 = 28
21 + 7 (tenths of 76) = 28
62 - 1 = 61
14 - 1 = 13
** btw 61 + 25 + 13 = 99**
Honorable Mentions:
76 / 2 = 38 (10 above)
Hardest to find for me was 23, it does have a direct match but it's in the middle of the pyramid. Suppose you correctly guess 28 from row 9 and pick 23 based off that. I couldn't find any other instances so far. Maybe 100 - 76 + 1 = 23, but that is two steps...
Predicting PB 12/2 with 11/30 numbers
11/30: 4 - 24 - 29 - 39 - 63 + 25
42,429,396,325 × π
133295879790.86977128953672981630490612258227988924857221696042200194388869765478298457027086034283879196152918751244236533972664240658653364437826288055075185257697767738755285777216732263325639
12/2: 3 - 9 - 26 - 61 - 67 + 13
86
97 71
28 95 36
72 98 16 30
49 06 12 25 82
27 98 89 24 85 72
21 69 60 42 20 01 94
38 88 69 76 54 78 29 84
57 02 70 86 03 42 83 87 91
96 15 29 18 75 12 44 23 65 33
97 26 64 24 06 58 65 33 64 43 78
26 28 80 55 07 51 85 25 76 97 76 77
38 75 52 85 77 72 16 73 22 63 32 56 39
100 - 97 = 3 (two 97's in 1st column)
97 - 71 = 26
28 - 2 (one of 72) = 26
27 - 1 = 26
94 -> 9 + 4 = 13
100 - 91 = 9
100 - 87 = 13
2 3's --> play 3
33 - 7 = 26
100 - 33 = 67
39 (one place) --> 9
100 - 39 = 61
** btw 61 + 26 + 13 = 100**
Honorable Mention:
71 - 10 = 61
57 + 10 = 67
73 - 16 = 57 (10 below)
77 - 10 = 67
Hardest one to find was 13... not quite satisfied with the ways I found it here.
Now... praying I've crunched all the numbers right, what I've gathered from three PowerBall drawings is to first focus on the ninth row - at least one of the white balls may be in there. If a number from that row repeats anywhere else in that pyramid, it might increase the chances of it coming out. You also want to focus on the first three numbers in the top corner pyramid. They can be an exact match or combine (add/minus), or subtract 100 to make a matching number. The 11th row may also be important, especially if you see replicate numbers anywhere else in the pyramid. To get the other numbers, you have to do a variation of operations like adding +/-1 or neighboring numbers (including only their tenths or ones place). I've ignored all numbers that aren't in our right diagonal, the first column, and the 9th and 11th rows for the sake of narrowing the amount of numbers we have to play with. Even then, it's still a lot.
More pyramids need to be drawn up to see if the procedure holds up or if there is a pattern/recommendation for the operations to use day by day. There are some flaws:
- For any number 1 - 26, we can't discern which ones will be the bonus ball
- The mathematical assumptions needed to get the winning numbers jumps around quite a bit
And perhaps more I haven't though of. But it seems promising for now.
DO NOT BE AFRAID.
