|Posted: August 30, 2003, 1:53 pm - IP Logged|
This gets back to the "if you know one number" topic, sort of. I like to come up with ONE NUMBER that I feel will definitely hit, and then combine it with another, ( due, key, repeat, candy, etc.), to come up with a set of ten numbers to play. Lets say 1 is my number and 2 is out 18 games or due, I would play 121, 122, 123, 124, etc. til I have ten sets of numbers. To come up with this ONE NUMBER I can usually narrow it down to three numbers. Since I can't be sure which number it is, my Math Whiz question is; Is there an economical way to play each of these three numbers other than:wheel each one for 36, games (=108 games), wheel all three with due, key, repeat, candy, etc., (7 or 8 number wheel), play each with each due, key, repeat or candy number, (3x4=12x10=120 games, or punt?
The problem is that the pay-back , (unless your position selection is right on or you're very lucky), doesn 't stack up. What a surprise!