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# sample size for 6/49 ??

Topic closed. 8 replies. Last post 13 years ago by lottoking.

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Member #2735
November 9, 2003
123 Posts
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 Posted: December 7, 2003, 1:24 am - IP Logged

guru what is the ideal sample size for the 6/49 game i have heard 600 400 500  what will give me the best chance of grabbing some winning numbers???

www.winnerslost .com;www.649-lottery.com
China
Member #2526
October 15, 2003
976 Posts
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 Posted: December 7, 2003, 6:22 am - IP Logged

underdog,the winning number ,if lucky, would be picked up by one draw...

Member #2612
October 25, 2003
122 Posts
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 Posted: December 7, 2003, 7:29 am - IP Logged

Hi LottoKing, good to see you back!! The forum wouldn't be the same without you!  In regards to your remainder number theory.....Using the example you provided on how to determine it. For example the winning number of a draw was 1 , 10, 35, 37, 43  and bonus 30, from all your calculations, you arrive at the remainder numbers as 1, 4, 5, 6.  My question is this.......in order to win a future draws, do I try an select future winning number set that also works out to its remainder numbers as 1, 4, 5, 6.  If so, how do I do it?

www.winnerslost .com;www.649-lottery.com
China
Member #2526
October 15, 2003
976 Posts
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 Posted: December 7, 2003, 7:58 am - IP Logged

study the past two or three draws first then fix one number in the reminder thats gonna appear.Then I will handle the other work to make the prediction. 1 2 3 6 are not  going to appear for the future draws too soon so you need to predict for the next reminder...

if you need to understand this completely,give me a remibder number as 1 2 4 5 ,etc,and see if i work the winning number out before you tell me what it really is..then everthings gonna be clear! thanks

lottoking

Member #2612
October 25, 2003
122 Posts
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 Posted: December 7, 2003, 8:32 am - IP Logged

Hi LottoKing, thanks my friend for you prompt reply.  What I'd like to do first is let you double check my calculations for arriving at the remainder number, then we will proceed.

These were the winning numbers for the Lotto 6/49 draw recently.

3 11 27 31 33 35    Bonus 1

Arranged      1 3 11 27 31 33 35

49(total Balls)/3 = 16.3 or 16

1, 3, 11, 11, 15, (33-16-16=1), (35-16-16=2)

1,3,11,11,15,1, 2

Arranged again    1, 1, 2, 3 ,11,11,15

Remove duplicates    1,2,3,11,15

16/3=5.3 or 5

Subtract 5 from above(if negative leave number same)

1, 2, 3,(11-5-5=1),(15-5-5=5)

1,2,3,1,5

Remove duplicates, so remainder numbers are 1,2,3,5

Is this correct?

Member #2612
October 25, 2003
122 Posts
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 Posted: December 7, 2003, 8:42 am - IP Logged

Hi LottoKing, disregard the 2 as a remainder number(35-16-16=3)

Remainders should be 1, 3, 5

Member #2612
October 25, 2003
122 Posts
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 Posted: December 7, 2003, 10:01 pm - IP Logged

Hi LottoKing, when you have a moment can you read the posts I made prior to this one, to let me know if I have your remainder number system calculated correctly?

Member #2612
October 25, 2003
122 Posts
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 Posted: December 8, 2003, 5:14 am - IP Logged

Hi Lotto King, just waiting for your replies.

www.winnerslost .com;www.649-lottery.com
China
Member #2526
October 15, 2003
976 Posts
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 Posted: December 8, 2003, 6:03 am - IP Logged

dynodyno,I am very happy to see you have counted right!Thats how my system works.if you know 1 3 5 ,my system will arrive at 1 2 3 11 15 ,then from 1 2 3 11 15 my system will arrrive at the winning number.So now you see where the chances are?

focus on this and you will win belive me.btw,you make to make sure that the reminder ONLY contain 5 number instead of 6 number for a better guarantee to win all numbers.Please tell me what you think and I think you might be the first winner at this forum,I will focus my attention on you from now on.

lottoking

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