keystonechas You've misunderstood my statement. I said there's a 50% chance that the SUM of all 6 numbers is odd.
For example: 01 05 17 20 21 44
01+05+17+20+21+44=98 (even)
The sum of ALL 6 numbers can ONLY be an even number or an odd number. Therefore, it is a 50% chance. I hope that clear things up.
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I have tested my filters against 100 previously drawed winning numbers and that chance of winning is 94% with the 301,662 reduced combinations. However, in order to qualify for the 94% chance, you must get the sum of all 6 numbers right (50% chance). If you want to bypass the 50% chance, you can buy all even and odds set, a total of 603,324 possible combinations (A guaranteed 94% chance of winning the jackpot). It's just too bad I don't have $603,324.00
Some of the filters I've used is listed below:
Odds/Evens Distribution 4/2 3/3 2/4
Range of Sum
Range of Sum Average
Range of Positions
Range of Highest Number minus Lowest Number
Elimination of all Odd/Even Combinations
Pattern Elimination (eg. 05, 15, 20, 25, 30)
Consecutive Number Elimination (eg. 1 2 3 4 5 6 or 8 9 10 11 26 45)
Product of 2 Number Equal Another Number Elimination
Quote of 2 Number Equal Another Number Elimination
Elimination Of All 6 Numbers in Lower Half/Upper Half
Elimination of All Combinations Previously Drawn
Elimination of Number Multiples (eg. 4 10 16 22 28 34)
Elimination of All Same Last Digits
Elimination of All Number In Same Group of 10
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So far, I've got 60 filters with 94% winning the jackpot in 603,324 possible combinations. However, it can be reduced down to 301,662 combination by chosing only those combination with the sum as an even or odd number (50% chance).