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# My China Method explained

Topic closed. 7 replies. Last post 13 years ago by CalifDude.

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Poway CA (San Diego County)
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Member #3489
January 25, 2004
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 Posted: May 13, 2004, 3:25 am - IP Logged

Let me start by explaining where I got the name "China Method".  Some time back there was a member on this forum called "goose".  He said that you could have a guaranteed straight every draw by playing his system.  Of course, that caught the eye of many of us!  He had a "wheel" of 64 tickets that guaranteed the straight IF you had the correct numbers.  Goose said he was from China.  So I call this the China Method!

He said that if you could come up with three sets of 4 digits with each set containing one of the winning numbers and you had them in the proper sequence, you would play 64 tickets and win a straight every time.

Those of us that were following that thread were trying to figure out how to get the correct numbers in the correct sequence.  I don't think anyone did (if they did, they didn't share it!!).

Here is the way it works.  You have one set of 4 digits that will be your first digit, the next set of 4 will be your second digit, and the third is the third digit.  An example:

1234 (Row A)

4567 (Row B)

7890 (Row C)

Now it is simply 1 from Row A, 1 from Row B, and 1 from Row C.  Of course, that makes 64 tickets and to get the straight the first number has to be from Row A, second from Row B, and third from Row C.  You can play all 64 or try to "see" a 3-digit number like in many of the other "workouts" or "stacks", etc.  So, with the example, you might like 269 or 448.

Here is how I have been getting the 3 rows.  I get my 10-digit number for my Columns A and B.  I then break it up as follows:

I number the positions 12345-67890.  The dash makes it easy to glance at the number and see which position is which.  If you don't know how I get the 10-digit number, look at my Blog and click on the link.  That will take you to a detailed explanation of how I do my method.  The 3 rows are:

1234

4567

7890

So as an example for Texas Midday draw on 5/13 I have the following 10-digit number:

37950-28614

Now I break that up into the 3 rows:

3795

5028

8614

As long as I have one of the winning digits in each row, I will have a BOX win.

Here is the recent draws for Texas:

 35028-76914 168 35028-76914 (112) 52837-69014 418 83769-01524 (889) 68901-35724 268 90163-58724 471 63058-71294 937 05368-71294 (434) 68731-02594 684 73102-58946 071 70125-83946 172 10275-83946 (422) 75083-91426 739

The bold numbers are the winning digits, the next column is the position numbers of the winning digits and the yellow indicates that the China Method had a win on that draw.

continued...

Poway CA (San Diego County)
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January 25, 2004
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 Posted: May 13, 2004, 3:30 am - IP Logged

It seems to work about 1/3 of the time or a little more.  Maybe we can improve it so that we get more wins.  I'm thinking of seeing if there are positions that hit more for the first digit, and the second, etc.

I think we can come up with improvements that will allow us to get more wins and maybe with less than 64 tickets.  Of course, you can try to visualize the numbers you want to play and not do all 64.  I have an Excel spreadsheet that does all 64 for me.  I was using that when I posted the numbers for the China Method, but from now on I will be just posting the 3 rows for each state.

Try this in your state and see how well it works.  It doesn't pick doubles very well, of course.

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February 26, 2004
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 Posted: May 13, 2004, 4:31 am - IP Logged

Can you show me an example for Louisiana.

Thanks a lot

Poway CA (San Diego County)
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 Posted: May 13, 2004, 6:51 am - IP Logged

The LA Lottery only shows the last 7 draws and that was not enough to get the 10-digit number for LA.  You will have to do it yourself from a database you maintain.  You can start with those 7 and then just add on.

Poway CA (San Diego County)
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 Posted: May 13, 2004, 6:57 am - IP Logged

I found the other draws.  For Louisiana 5/13:

 Wed 5/12/2004 2 9 3 face=arial color=#0000ff Winners Tue 5/11/2004 1 2 4 face=arial color=#0000ff Winners Mon 5/10/2004 9 9 5 face=arial color=#0000ff Winners Sun 5/9/2004 3 0 3 face=arial color=#0000ff Winners Sat 5/8/2004 2 9 4 face=arial color=#0000ff Winners Fri 5/7/2004 9 1 0 face=arial color=#0000ff Winners Thu 5/6/2004 3 1 0 face=arial color=#0000ff Winners Wed 5/5/2004 3 3 5 face=arial color=#0000ff Winners Tue 5/4/2004 8 9 4 face=arial color=#0000ff Winners Mon 5/3/2004 2 0 3 face=arial color=#0000ff Winners Sun 5/2/2004 2 4 3 face=arial color=#0000ff Winners Sat 5/1/2004 9 6 7 face=arial color=#0000ff Winners

2931 (Row A)

1450 (Row B)

0867 (Row C)

Poway CA (San Diego County)
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January 25, 2004
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 Posted: May 13, 2004, 8:37 am - IP Logged

I just spent a lot of time going through my Texas database trying to determine if there really is a way to pick the digits in the correct order for a straight using the China Method.  Here is what I discovered:

I only have 82 draws that I have the 10-digit numbers in the database, so this is only for the last 82 draws.  The counts for the digits are:

#1      #2        #3

1=8    1=8    1=11

2=9    2=6    2=9

3=6    3=9    3=3

4=10    4=8    4=5

5=7    5=3    5=14

6=12    6=8    6=7

7=6    7=12    7=8

8=9    8=13    8=11

9=5    9=9    9=6

0=10    0=6    0=8

So I went through using the way I showed you and counted the number of straights and boxes that I would have had.  Then I went through using the above (positions 2,4,6, and 0 for the first digit, positions 3,7,8, and 9 for the second digit, positions 1,2,5, and 8 for the third digit) and I counted again.  Here are my results:

The "regular" way that I showed first:  28 box, 5 straight

The "new" way:  13 box, 14 straight

Now...the danger is using past results to develop a method and then using the past results to prove it!!  Of course, it will prove itself.  So this will have to be tested from this point on to see if it really works.

Poway CA (San Diego County)
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 Posted: May 13, 2004, 10:39 am - IP Logged

I tried the same modification as above for California using the last 100 draws with the following results:

The original way: 15 box 2 straight (last 50 draws)

The modified way: 8 box 9 straight (last 50 draws)

If you played straight only and used the modified way and it held up, you would invest \$3200 (\$64x50), and get back (figuring \$500 for a straight) \$4500.  So it would make money, but that depends again on past results continuing in the future!

For 100 draws, I show for California:

Digit #1 = Positions 1, 4, 7, and 0

Digit #2 = Positions 1, 2, 5, and 9

Digit #3 = Positions 1, 2, 3, and 9

I will keep close tabs on California to see how this does.  Can't promise for other states!

Poway CA (San Diego County)
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 Posted: May 27, 2004, 8:52 pm - IP Logged

I have a lot of people asking me to explain my method and/or do it for their state.  I don't have the time to do other states.  I'm responding here to bump this thread up to the top again so people can find this post.

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