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# Can The Guru's explain to us please

Topic closed. 14 replies. Last post 13 years ago by Maryland.

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United States
Member #986
January 5, 2003
280 Posts
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 Posted: May 16, 2004, 5:26 pm - IP Logged

I've had this for a long time but could never figure it out.  Supposedly a good system.  If anyone could explain, maybe we all could benefit.

This system is based on the number for five years back on the same day as your going to play. As. If your going to play
on 12/20/04 then you'll need the numbers on that same day for the past five years. Ect. 12/20/02,12/20/01, 12/20/00,
12/20/99, 12/20/98.

Taking the highest and the lowest of these totals,6906 and 6017, and allowing a good margin,we may expect to find the
required number between 6000 and 7000. We now proceed to find the key number.

1.  By the Minor Differential.

1894-  6351=15
}-6

1895- 6906=21}=13

Y~l

1896-6017= 14}=12

}-5

1897-6715= 19}=11
}+6

1898-6430=13}=10

}-4

1899- ????=17

The series is found by adding together the integers of each given number, thus: 6351= 6+3+5+1=15. It will be seen that
the results gives 13,12,11,10 a numerical series whose intervals are equal. We therefore reguire a number whose

1894- 6351=15
}=36

1895-6906=21 }=71
}=35

1896-6017=14 }=68
}=33

1897-6715=19}=65
}=32

1898-6430=13}=62
}=30

1899- ????=17

Here also the intervals are equal in the final series. We therefore are confirmed in the knowledge that the required
number belongs to the series of 17.

3.  By the Major Differential.

1894- 6351

-555=15=6

1895 6906 }=13

+889=25=7

18966017}=12

CA
United States
Member #2987
December 10, 2003
832 Posts
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 Posted: May 16, 2004, 9:37 pm - IP Logged

Maryland -

Any research on how the system has worked in other states? Other games?

gl

john

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

United States
Member #986
January 5, 2003
280 Posts
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 Posted: May 17, 2004, 5:04 pm - IP Logged

No John, I picked it up somewhere but do remember how they were raving about it.  Can you figure it out?  Don't even know if it's for pick 3,4,5,6 etc.  It definitely has to do with picking lottery numbers.  I see alot of members posting these mathematical equations and thought they would know how it works.

Greensboro, North Carolina
United States
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June 5, 2003
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 Posted: May 17, 2004, 5:54 pm - IP Logged

Maryland, I have a copy of that program to. It is for Pick4. The person who sent it to me told me that it has to be dates for five years back that fall on a day that had a drawing. If it fell on Sunday then it was no good.  In Va. that only gave me a two day a week window to work with. It wasn't worth the stress.

Greensboro, North Carolina
United States
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June 5, 2003
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 Posted: May 17, 2004, 6:03 pm - IP Logged

Came off another lottery we

United States
Member #986
January 5, 2003
280 Posts
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 Posted: May 17, 2004, 6:29 pm - IP Logged

ok reddog, you have a copy, it came from another website.  Now can you explain it please?

Wyncote,Pa
United States
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January 3, 2004
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 Posted: May 17, 2004, 8:17 pm - IP Logged

I think it has to do with the Secret Progression.I had that book about

twenty years ago.There is a website for

it.

Wyncote,Pa
United States
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January 3, 2004
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 Posted: May 17, 2004, 8:22 pm - IP Logged

Here is the site

www.therota.co.uk/occult/amo/amotac6.htm

Wyncote,Pa
United States
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January 3, 2004
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 Posted: May 17, 2004, 8:27 pm - IP Logged

Here is the site again

www.therota.co.uk/occult/amo/amotac6.htm

Wyncote,Pa
United States
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January 3, 2004
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 Posted: May 17, 2004, 8:33 pm - IP Logged

It's under numerology in the

book called Manual of Occultism.

Greensboro, North Carolina
United States
Member #1616
June 5, 2003
1283 Posts
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 Posted: May 17, 2004, 9:16 pm - IP Logged

Maryland, here is a copy of what I got. Maybe you will have better luck with the instructions down at the bottom of the e-mail.

This system is based on the number for five years back on the same day as your going to play. As. If your going to play on 12/20/04 then youll need the numbers on that same day for the past five years.  Ect.12/20/02,12/20/01, 12/20/00, 12/20/99, 12/20/98.

Taking the highest and the lowest of these totals,6906 and 6017, and allowing a good margin,we may expect to find the required number between 6000 and 7000. We now proceed to find the key number.

1.    By the Minor Differential.
1894-    6351 = 15
}-6
1895-    6906 = 21          }=13
}+7
1896-    6017 = 14          }=12
}-5
1897-    6715 = 19          }=11
}+6
1898-    6430 = 13          }=10
}-4
1899-    ????  = 17

The series is found by adding together the integers of each given number, thus: 6351= 6+3+5+1=15. It will be seen that the results gives 13,12,11,10 a numerical series whose intervals are equal. We therefore reguire a number whose integers added = 17.

1894-    6351=15
}=36
1895-    6906=21            }=71
}=35
1896-    6017=14            }=68
}=33
1897-    6715=19            }=65
}=32
1898-    6430=13            }=62
}=30
1899-    ???? =17

Here also the intervals are equal in the final series. We therefore are confirmed in the knowledge that the required number belongs to the series of 17.

3.    By the Major Differential.
1894-    6351
-555=15=6
1895    6906                    }=13
+889=25=7
1896    6017                    }=12
-698=23=5
1897    6715                    }=11
+285=15=6
1898    6430                    }=10
-??? = ?? =4
1899      ????

Again the intervals are made equal by the supposition of the figure 4. The number required, therefore is one which, when 6430 is taken from it, leaves a number whose integers = 4, 13,22, or 31=4

1894-    6351
}=13,257=18=9
1895      6906                          }=17
}=12,923=17=8
1896      6017                          }=14
}=12,732=15=6
1897      6715                          }=11
}=13,145=14=5
1898      6430                          }=8
}=??,???  =12=3
1899      ????.

The series 17,14,11,8 shows equal intervals. The required number, therefore, is one which, added to 6430, gives a sum whose figures add to 12.

Consequently, we now know that the number is one whose integers add to 17, and that it is a number which, being added to 6430, yields a sum whose figures add to 12.
Having ascertained these facts concerning the hidden or unknown number, the task is not now a difficult one to anybody accustomed to handling figures.
Between 6000 and 7000 there are only 70 numbers whose integers add to 17.
Between 6000 and 7000 there are only 31 numbers whose figures amount to 12.
Of these 31 numbers there are only 14 numbers whose difference of 6430 is a number whose figures add to 13.
Finally there are only 7 numbers within these limits which exactly satisfy all the conditions of the Secret Progression. These are 6470,6632,6641,6650,6731,6740,and6830. By the third process the Major Differential we found the number to be grater than 6430 so that the field of inquiry was limited to numbers between 6430 and 7000. We have found seven numbers which are capable of satisfying all the conditions imposed by the different processes, and since the master key is not to be divulged we must be content with a statement which reduces the possible number of chances from 1000 to 7. The Registrar-General returned the number 6731. A moments study will show how exactly it fits all the requirements of the several processes.
1.    Minor Differential.  6731=17, which compared with 13 shows the latter yields 4, which added to 6=10.
3.    Major Differential. If from 6731 we take 6430, we have 301, which =4.
4.    Major Additive. 6731 added to 6430= 13,161, which yields a unit valve of 12, which equals 3, which added to 5 gives 8.

United States
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April 24, 2004
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 Posted: May 17, 2004, 11:41 pm - IP Logged

Hmmm... anything having to do with numerology is  pretty skeptical.

United States
Member #14
November 9, 2001
31333 Posts
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 Posted: May 18, 2004, 12:03 am - IP Logged

cool site.

love to nibble those micey feet.

Australia
Member #3084
December 22, 2003
328 Posts
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 Posted: May 18, 2004, 2:41 am - IP Logged
Quote: Originally posted by reddog on May 17, 2004

Finally there are only 7 numbers within these limits which exactly satisfy all the conditions of the Secret Progression. These are 6470,6632,6641,6650,6731,6740,and6830

Reddog

I closed my eyes when pasting the secret number. If you or someone else wants to code it in VB I'll give it a few runs to see how it performs.

Regards
Colin

United States
Member #986
January 5, 2003
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 Posted: May 18, 2004, 5:53 pm - IP Logged

Thanks for the page blackapple but I still don't understand

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