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Can The Guru's explain to us please

Topic closed. 14 replies. Last post 13 years ago by Maryland.

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January 5, 2003
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Posted: May 16, 2004, 5:26 pm - IP Logged

I've had this for a long time but could never figure it out.  Supposedly a good system.  If anyone could explain, maybe we all could benefit.

This system is based on the number for five years back on the same day as your going to play. As. If your going to play
on 12/20/04 then you'll need the numbers on that same day for the past five years. Ect. 12/20/02,12/20/01, 12/20/00,
12/20/99, 12/20/98.

Taking the highest and the lowest of these totals,6906 and 6017, and allowing a good margin,we may expect to find the
required number between 6000 and 7000. We now proceed to find the key number.

1.  By the Minor Differential.

1894-  6351=15
}-6

1895- 6906=21}=13

Y~l

1896-6017= 14}=12

}-5

1897-6715= 19}=11
}+6

1898-6430=13}=10

}-4

1899- ????=17

The series is found by adding together the integers of each given number, thus: 6351= 6+3+5+1=15. It will be seen that
the results gives 13,12,11,10 a numerical series whose intervals are equal. We therefore reguire a number whose
integers added =17.

2.  By the Minor Additive.

1894- 6351=15
}=36

1895-6906=21 }=71
}=35

1896-6017=14 }=68
}=33

1897-6715=19}=65
}=32

1898-6430=13}=62
}=30

1899- ????=17

Here also the intervals are equal in the final series. We therefore are confirmed in the knowledge that the required
number belongs to the series of 17.

3.  By the Major Differential.

1894- 6351

-555=15=6

1895 6906 }=13

+889=25=7

18966017}=12

    johnph77's avatar - avatar
    CA
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    Posted: May 16, 2004, 9:37 pm - IP Logged

    Maryland -

    Any research on how the system has worked in other states? Other games?

    gl

    john

    Blessed Saint Leibowitz, keep 'em dreamin' down there..... 

    Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

     =^.^=

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      Posted: May 17, 2004, 5:04 pm - IP Logged

      No John, I picked it up somewhere but do remember how they were raving about it.  Can you figure it out?  Don't even know if it's for pick 3,4,5,6 etc.  It definitely has to do with picking lottery numbers.  I see alot of members posting these mathematical equations and thought they would know how it works.

        reddog's avatar - patch
        Greensboro, North Carolina
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        Posted: May 17, 2004, 5:54 pm - IP Logged

        Maryland, I have a copy of that program to. It is for Pick4. The person who sent it to me told me that it has to be dates for five years back that fall on a day that had a drawing. If it fell on Sunday then it was no good.  In Va. that only gave me a two day a week window to work with. It wasn't worth the stress.

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          reddog's avatar - patch
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          Posted: May 17, 2004, 6:03 pm - IP Logged

          Came off another lottery we

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            Posted: May 17, 2004, 6:29 pm - IP Logged

            ok reddog, you have a copy, it came from another website.  Now can you explain it please?

              Blackapple's avatar - nw rogue2.jpg
              Wyncote,Pa
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              Posted: May 17, 2004, 8:17 pm - IP Logged

              I think it has to do with the Secret Progression.I had that book about

              twenty years ago.There is a website for

              it.

                Blackapple's avatar - nw rogue2.jpg
                Wyncote,Pa
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                Posted: May 17, 2004, 8:22 pm - IP Logged

                Here is the site

                www.therota.co.uk/occult/amo/amotac6.htm

                  Blackapple's avatar - nw rogue2.jpg
                  Wyncote,Pa
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                  Posted: May 17, 2004, 8:27 pm - IP Logged

                  Here is the site again

                  www.therota.co.uk/occult/amo/amotac6.htm

                    Blackapple's avatar - nw rogue2.jpg
                    Wyncote,Pa
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                    Posted: May 17, 2004, 8:33 pm - IP Logged

                    It's under numerology in the

                    book called Manual of Occultism.

                      reddog's avatar - patch
                      Greensboro, North Carolina
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                      Posted: May 17, 2004, 9:16 pm - IP Logged

                      Maryland, here is a copy of what I got. Maybe you will have better luck with the instructions down at the bottom of the e-mail.


                      This system is based on the number for five years back on the same day as your going to play. As. If your going to play on 12/20/04 then youll need the numbers on that same day for the past five years.  Ect.12/20/02,12/20/01, 12/20/00, 12/20/99, 12/20/98.

                      Taking the highest and the lowest of these totals,6906 and 6017, and allowing a good margin,we may expect to find the required number between 6000 and 7000. We now proceed to find the key number.

                      1.    By the Minor Differential.
                      1894-    6351 = 15
                                                    }-6
                      1895-    6906 = 21          }=13
                                                    }+7
                      1896-    6017 = 14          }=12
                                                    }-5
                      1897-    6715 = 19          }=11
                                                    }+6
                      1898-    6430 = 13          }=10
                                                    }-4
                      1899-    ????  = 17

                      The series is found by adding together the integers of each given number, thus: 6351= 6+3+5+1=15. It will be seen that the results gives 13,12,11,10 a numerical series whose intervals are equal. We therefore reguire a number whose integers added = 17.

                      2.    By the Minor Additive.
                      1894-    6351=15
                                                    }=36
                      1895-    6906=21            }=71
                                                    }=35
                      1896-    6017=14            }=68
                                                    }=33
                      1897-    6715=19            }=65
                                                    }=32
                      1898-    6430=13            }=62
                                                    }=30
                      1899-    ???? =17

                      Here also the intervals are equal in the final series. We therefore are confirmed in the knowledge that the required number belongs to the series of 17.


                      3.    By the Major Differential.
                      1894-    6351
                                            -555=15=6
                      1895    6906                    }=13
                                            +889=25=7
                      1896    6017                    }=12
                                            -698=23=5
                      1897    6715                    }=11
                                            +285=15=6
                      1898    6430                    }=10
                                            -??? = ?? =4
                            1899      ????

                            Again the intervals are made equal by the supposition of the figure 4. The number required, therefore is one which, when 6430 is taken from it, leaves a number whose integers = 4, 13,22, or 31=4

                      4.    By the major additive.
                      1894-    6351
                                            }=13,257=18=9
                      1895      6906                          }=17
                                            }=12,923=17=8
                      1896      6017                          }=14
                                            }=12,732=15=6
                      1897      6715                          }=11
                                            }=13,145=14=5
                      1898      6430                          }=8
                                            }=??,???  =12=3
                      1899      ????.

                      The series 17,14,11,8 shows equal intervals. The required number, therefore, is one which, added to 6430, gives a sum whose figures add to 12.

                      Consequently, we now know that the number is one whose integers add to 17, and that it is a number which, being added to 6430, yields a sum whose figures add to 12.
                      Having ascertained these facts concerning the hidden or unknown number, the task is not now a difficult one to anybody accustomed to handling figures.
                      Between 6000 and 7000 there are only 70 numbers whose integers add to 17.
                      Between 6000 and 7000 there are only 31 numbers whose figures amount to 12.
                      Of these 31 numbers there are only 14 numbers whose difference of 6430 is a number whose figures add to 13.
                      Finally there are only 7 numbers within these limits which exactly satisfy all the conditions of the Secret Progression. These are 6470,6632,6641,6650,6731,6740,and6830. By the third process the Major Differential we found the number to be grater than 6430 so that the field of inquiry was limited to numbers between 6430 and 7000. We have found seven numbers which are capable of satisfying all the conditions imposed by the different processes, and since the master key is not to be divulged we must be content with a statement which reduces the possible number of chances from 1000 to 7. The Registrar-General returned the number 6731. A moments study will show how exactly it fits all the requirements of the several processes.
                      1.    Minor Differential.  6731=17, which compared with 13 shows the latter yields 4, which added to 6=10.
                      2.    Minor Additive. 6731=17, which added to 13=30,which added to 32=62.
                      3.    Major Differential. If from 6731 we take 6430, we have 301, which =4.
                      4.    Major Additive. 6731 added to 6430= 13,161, which yields a unit valve of 12, which equals 3, which added to 5 gives 8. 


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                        Posted: May 17, 2004, 11:41 pm - IP Logged

                        Hmmm... anything having to do with numerology is  pretty skeptical.

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                          Posted: May 18, 2004, 12:03 am - IP Logged

                          cool site.

                          love to nibble those micey feet.

                           

                                                       


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                            Posted: May 18, 2004, 2:41 am - IP Logged
                            Quote: Originally posted by reddog on May 17, 2004



                            Finally there are only 7 numbers within these limits which exactly satisfy all the conditions of the Secret Progression. These are 6470,6632,6641,6650,6731,6740,and6830





                            Reddog

                            I closed my eyes when pasting the secret number. If you or someone else wants to code it in VB I'll give it a few runs to see how it performs.

                            Regards
                            Colin

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                              Posted: May 18, 2004, 5:53 pm - IP Logged

                              Thanks for the page blackapple but I still don't understand