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Calif 5/24 Midday China Method

Topic closed. 1 reply. Last post 13 years ago by CalifDude.

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Poway CA (San Diego County)
United States
Member #3489
January 25, 2004
14120 Posts
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Posted: May 24, 2004, 10:11 am - IP Logged







Key #: 2



5281


(Row A)


1690


(Row B)


0347


(Row C)




Modified



1690


(Row A)


0347


(Row B)


5281


(Row C)




Take one digit from each row to make up your 3-digit number.  If you do all of them, you will come up with 64 tickets (4X4X4 = 64). The "modified" rows are modified sequence for this state only and are designed to maximize your chance of a straight.

I'm not always posting a Key #, but this time I felt like I had to.  When I look for a Key #, I look first to see if a number is in the same numerical position in my 10-digit number.  Well, that does happen this time...2 is in position 2, but when I don't see a situation like that, then I look to see which position hasn't hit for the longest time.  Have you guessed it?  Yes, position 2.  So my strong suggestion is that you play only numbers with the 2 in them.  If you play all of them using one of the above charts, that is only 16 tickets.

I have also changed the order for the "modified" chart.  Therefore, I'm starting a new count for BOX and STRAIGHT hits produced by both charts.

If you would rather use the most overdue number, then play the 7. 

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    Poway CA (San Diego County)
    United States
    Member #3489
    January 25, 2004
    14120 Posts
    Offline
    Posted: May 24, 2004, 5:36 pm - IP Logged

    Calif Midday = 702 ... a BOX hit in both charts and you got it if you played the 2 or the 7!!!! 




    5281


    (Row A)


    1690


    (Row B)


    0347


    (Row C)




    Modified



    1690


    (Row A)


    0347


    (Row B)


    5281


    (Row C)