|Posted: June 6, 2004, 5:30 am - IP Logged|
Take one digit from each row to make up your 3-digit number. Pick a Key # and play only those numbers that have the Key #. In most cases that will produce only 16 tickets.
Here is the above chart in columns instead of rows:
My analysis for this draw may be way too much. But I'm going to offer it, anyway!! By too much I mean that sometimes some of us eliminate the winning number by being too selective.
I would not play doubles this time. Looking back 300 draws at the times that doubles have come in twice in a row (we had 337 followed by 090), the number of times that a double came in again was 5 and the number of times a double did not hit again was 12.
I would not play the number that is in position 5 (the number 6) because position 5 has hit 3 times in a row. Looking back about 50 draws, a position has never hit more than 3 times in a row.
A very good candidate for a Key # is the number 7. It is in position 4 which has skipped 18 times. But, if you use 7 as your Key #, you have a possible problem with my chart because it is listed twice and would therefore be a double!
If you were to follow all of my suggestions this time, you would end up playing 19 tickets. I will list them for you:
That will be my play for the Midday today in California. Using 7 as Key #, not playing any numbers with a 6 and not playing any doubles.