Due to time constraints, I'm going to just publish the numbers to use for you to choose your own picks. There are 3 groups of 4 digits. Play ONE digit from each group to make up your 3-digit number. If you played all of them, you would play 64 tickets, so you may want to use filters like no doubles or no pure numbers, etc.
Things to consider: We just had a double (998) and that puts us in what I call the "Double Zone" for California. Doubles often follow doubles or skip 1. Here is the chart showing how many skips between doubles (0 means doubles followed doubles with no skip):
DBL
|
|
0=
|
26
|
1=
|
21
|
2=
|
21
|
3=
|
12
|
4=
|
8
|
5=
|
6
|
6=
|
5
|
7=
|
3
|
8=
|
6
|
9=
|
2
|
10=
|
1
|
>10=
|
3
|
The number 4 has skipped 10 times. The last time it skipped more than 10 it skipped 13 before hitting on the 14th draw. The number 6 has skipped 15 times. The last 2 long skips for 6 were 10 and 13 before hitting on the next draw. If you want to reduce the number of tickets, you might want to play a double with a 6 in it, or even double 6, although that would not be in my 64 from the above chart. This last draw was an even sum and it would be a good bet to consider playing an odd sum. Looking at recent history, when an even hits (after an odd) it switched back to odd 9 times, but only continued with another even twice.