Hello, Tomterrific....
you have asked for some help in understanding what I do, yes? First off---Reread my explanations! Not being funny with you but it can take several passes to know what I am doing. When I stated that "this game is so simple that it is difficult" the method employed has to run on the same premise. The number of sets given were to acquaint you with the ---How It's Done! I use a stack of 12 last sets (including the very last win.) There is no limitation on how many sets to use once the idea has sunk in. The main thought to remember is that you are breaking each set of three digits into pairs of which you will have three distinct pairs per that set. Eg., example---349 =34,39 and 49. When you have whatever amount of full sets, that's twelve or more last wins, there will usually be identical single digits that duplicate the last winning entry---REMOVE them so that there is only one of a kind with the last three digits from the last winning set, no repeated numbers! The leftovers plus the last winning set holds the key! If there were no repeating digits then use only the last set of three digits.
Teufellj...