Here's the Reality and Hard Fact of the Matter.
You won't be told it's a Crash till after it has happened.
Look beyond the articles of confusion.
![]()
The time is now 12:10 am
You last visited
June 7, 2026, 2:27 am
All times shown are
Eastern Time (GMT-5:00)
You won't be told it's a Crash till after it has happened.
Look beyond the articles of confusion.
![]()
Adjusted for an All Time Daily Close High
The Red sheet is the classical gain / loss.
The Green sheet is the relative gain / loss.
The Blue sheet is the relative acceleration gain / loss.
We've come up with some additional boundaries for the Market Blackhole effect.
Each of the percent changes are relative to some maximum, i.e. 52 Week High or an All Time High value.
Just a few computations for a theory we've been working on.
Entry in to the System of Investment Decay - The pull of the Economic Singularity is first noticed.
-1 + √20 / 21 ≈ -2.41%
Zeroth Investment Dark Moment - Economic Singularity locks on to the investment.
-1 + 4√1 / 2 ≈ -15.91%
First Investment Dark Moment - Direct escape from the Economic Singularity is near impossible.
-1 + √2 / 3 ≈ -18.35%
Second Investment Dark Moment - Diverted escape from the Economic Singularity is near impossible.
-1 + ((-1 + √17) / 4) ≈ -21.92%
Based on a Market Mass of 15,542.40 ...
... the first Investment Dark Moment is 12,690.31 ...
... the second Investment Dark Moment is 12,135.14 .
![]()
It closed last night at 13,014.87.
Based on a Market Mass of 15,942.60 ...
... the first Investment Dark Moment is at 13,017.08 ...
... the second Investment Dark Moment is 12,447.61.
Below that, we're inside the Blackhole, next stop is the Economic Singularity.
The equations we posted about an actual Blackhole are not being used for this calculation; for these boundaries.
These are based on a different calculation, but important none the less.
![]()
There are two dark moments around a blackhole and their boundaries are at two different radii.
The first is the obvious escape velocity radius of no return.
If given the equation ve = √2·G·m / re, where ve is the velocity and re is the distance from the center of blackhole mass, m, then we can set ve equal to the speed of light, c.
The equation becomes c = √2·G·m / re; solve for re it becomes, re = 2·G·m / c2.
The second might not be so obvious; it's the centripetal velocity radius of no return.
This is a balance between two forces; one centripetal: mo·vc2 / rc and two gravitation: -G·m·mo / rc2, where mo is the mass of smaller object, m is the mass of the blackhole, vc is the centripetal velocity around the blackhole at radius rc.
The second equation becomes (mo·vc2 / rc) - (G·m·mo / rc2) = 0, solve for rc it becomes, rc = G·m / vc2.
Now set vc equal to the speed of light, c, it becomes rc = G·m / c2.
As we can see, the two boundaries are different by only a factor of 2, re = 2·G·m / c2 and rc = G·m / c2, but the velocities are at 90 degrees of each other.
The escape velocity is pointing out from the center of the blackhole, normal or perpendicular to the circle swept out by the radius re.
The centripetal velocity is pointing on a tangent to the circle swept out by the radius rc.
the revisit of another 1972 meteor is closing in on us.
![]()
We added a Market Vitality column to the http://www.jadexcode.com/Market/DowJonesMarketData.aspx data.
You need to become absolutely and completely virtual.
Decentralize beyond the server.
Put it out of reach of the fucers.
http://www.jadexcode.com/FactoredExpansion-2.html
It is Highly recommended you view this in Mozilla Firefox.
The MathJax script can take a long time to render the mathematical expressions.
Also, again, all the polynomials you see are related to each other.
![]()