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Imagine the Infintely Zeroth Possibilities
Published:
a > b
taking the reciprocal of both side causes the > to change to <.
reciprocal of a > b is a-1 < b-1
a > b | a-1 < b-1 | ||
a | b | a-1 | b-1 |
1 | 0.25 | 1.00000 | 4.00000 |
1 | 0.5 | 1.00000 | 2.00000 |
2 | 1 | 0.50000 | 1.00000 |
2 | 1.5 | 0.50000 | 0.66667 |
10 | 5 | 0.10000 | 0.20000 |
10 | 9 | 0.10000 | 0.11111 |
1000 | 500 | 0.00100 | 0.00200 |
1000 | 900 | 0.00100 | 0.00111 |
2 - Apply Reciprocal Operation of Inequality to the Inequality of ¥ -1 > 0
¥ -1 > 0
the reciprocal of ¥ -1 > 0 is ¥ < 0 -1
if the inequality ¥ < 0 -1 is true, then 0 -1 is a new number, I, and exists outside the set of Real numbers or Hyper-infinite.
the number I is analogous to the number i = Ö-1
3 - Some other additional inequalities and equalities
0 ¹ ¥ -1
0 -1 ¹ ¥
I = 0 -1 Hyper-infinite number
0 ´ I = 1
1 ´ I = I
n ´ I = nI
0 ´ nI = n
a is Real and bI is Hyper-infinite, then the sum of a and bI is complex and is a + bI
4 - If ¥ -1 = 0 , then 0 + ¥ -1 = 0
0 + ¥ -1 = 0
0 + ( 1 / ¥ ) = 0
0 ( ¥ / ¥ ) + ( 1 / ¥ ) = 0
( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) = 0
( 0 * ¥ + 1 ) / ¥ = 0
0 * ¥ + 1 = 0 * ¥
( 0 * ¥ ) - ( 0 * ¥ ) + 1 = ( 0 * ¥ ) - ( 0 * ¥ )
0 + 1 = 0
1 = 0
1 = 0 , is false \ ¥ -1 ¹ 0
5 - If ¥ -1 > 0 , then 0 + ¥ -1 > 0
0 + ¥ -1 > 0
0 + ( 1 / ¥ ) > 0
0 ( ¥ / ¥ ) + ( 1 / ¥ ) > 0
( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) > 0
( 0 * ¥ + 1 ) / ¥ > 0
0 * ¥ + 1 > 0 * ¥
( 0 * ¥ ) - ( 0 * ¥ ) + 1 > ( 0 * ¥ ) - ( 0 * ¥ )
0 + 1 > 0
1 > 0
1 > 0 , is true \ ¥ -1 > 0
6 - n ¥ = ¥
( n ¥ ) / ¥ = ¥ / ¥
n ( ¥ / ¥ ) = ¥ / ¥
n ( 1 ) = 1
n = 1, \ n ¥ = ¥ true when n = 1
7 - n ¥ ¹ ¥
( n ¥ ) / ¥ ¹ ¥ / ¥
n ( ¥ / ¥ ) ¹ ¥ / ¥
n ( 1 ) ¹ 1
n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1
8 - n ¥ = -¥
( n ¥ ) / ¥ = -¥ / ¥
n ( ¥ / ¥ ) = -¥ / ¥
n ( 1 ) = -1
n = -1, \ n ¥ = -¥ true when n = -1
9 - n ¥ ¹ -¥
( n ¥ ) / ¥ ¹ -¥ / ¥
n ( ¥ / ¥ ) ¹ -¥ / ¥
n ( 1 ) ¹ -1
n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1
10 - 0 * ¥ = n
( 0 * ¥ ) / ¥ = n / ¥
0 ( ¥ / ¥ ) = n / ¥
0 ( 1 ) = n / ¥
0 = n / ¥ , if and only if n = 0 * ¥
11 - 0 * ¥ = n
( 0 * ¥ ) / 0 = n / 0
¥ ( 0 / 0 ) = n / 0
¥ ( 1 ) = n / 0
¥ = n / 0
¥ = n / 0 , if and only if n = 0 * ¥
12 - If X / X = 1, then -¥ / -¥ = 1
-¥ / -¥ = 1
-¥ = 1 * -¥
-¥ = -¥, true \ -¥ / -¥ = 1
13 - If X / X ¹ 1, then -¥ / -¥ ¹ 1
-¥ / -¥ ¹ 1
-¥ ¹ 1 * -¥
-¥ ¹ -¥, false \ -¥ / -¥ = 1
14 - If X / X = 1, then 0 / 0 = 1
0 / 0 = 1
0 = 1 * 0
0 = 0, true \ 0 / 0 = 1
15 - If X / X ¹ 1, then 0 / 0 ¹ 1
0 / 0 ¹ 1
0 ¹ 1 * 0
0 ¹ 0, false \ 0 / 0 = 1
16 - If X / X = 1, then ¥ / ¥ = 1
¥ / ¥ = 1
¥ = 1 * ¥
¥ = ¥, true \ ¥ / ¥ = 1
17 - If X / X ¹ 1, then ¥ / ¥ ¹ 1
¥ / ¥ ¹ 1
¥ ¹ 1 * ¥
¥ ¹ ¥, false \ ¥ / ¥ = 1
18 - If Y = 1 and is continuous for all Real values in the function Y = f(X) and f(X) = X / X, then Y = 1 = X / X and is continuous for all Real values
Y = 1 = X / X
Y * X = 1 * X = X
1 * X = 1 * X = X
X = X = X, true if and only if Y = 1
-¥ = -¥ = -¥, true if and only if Y = 1
0 = 0 = 0, true if and only if Y = 1
¥ = ¥ = ¥, true if and only if Y = 1
The mathematical operation of X / X = 1 must be continuous for all Real values of X; including {-¥, 0, ¥}.
When dealing with 0 and ¥ it is better to treat them as if they were variables first and do normal math operations first, then work the final equation or inequality. There are times when 02 ¹ 0 and ¥2 ¹ ¥ , much like X2 does not exactly equal X.
Also, 0 * ¥ is a non-reducible number much like 2i is a non-reducible number, it is what it is, a number all by itself.
In addition, ¥ -1 is the infinitesimal unit and is exactly and only exactly the first number after 0.
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