Why 10 Quadrillion? Quantum outcomes between the possible 10K on P4 or 1K on P3?

the matrix is as follow
(the matrix is to be written in brackets [ ], but we can not place the brackets [ ] around the matrix due to font limitations):

a b c d
e f g h
i j k m
n p q r

a, b, c, d, e, f, g, h, i, j, k, m, n, p, q, r can be any number 0 through 9 ...
... which becomes abcdefghijkmnpqr or a,bcd,efg,hij,kmn,pqr.

this translates to 0,000,000,000,000,000 through 9,999,999,999,999,999 ...
... , hence, is equivalent to 10,000,000,000,000,000 possible outcomes.

the determinant of that matrix needs to be calculated for each and every possible outcome.

the calculation of just one of those outcomes is as follows:

D4 = a × (f × (k × r - m × q) - g × (j × r - m × p) + h × (j × q - k × p)) - b × (e × (k × r - m × q) - g × (i × r - m × n) + h × (i × q - k × n)) + c × (e × (j × r - m × p) - f × (i × r - m × n) + h × (i × p - j × n)) - d × (e × (j × q - k × p) - f × (i × q - k × n) + g × (i × p - j × n))

Oops, that font thing again.... disregard that last reply.

the matrix is as follow
(the matrix is to be written in brackets [ ], but we can not place the brackets [ ] around the matrix due to font limitations):

a b c d
e f g h
i j k m
n p q r

a, b, c, d, e, f, g, h, i, j, k, m, n, p, q, r can be any number 0 through 9 ...
... which becomes abcdefghijkmnpqr or a,bcd,efg,hij,kmn,pqr.

this translates to 0,000,000,000,000,000 through 9,999,999,999,999,999 ...
... , hence, is equivalent to 10,000,000,000,000,000 possible outcomes.

the determinant of that matrix needs to be calculated for each and every possible outcome.

the calculation of just one of those outcomes is as follows:

D4 = a X (f X (k X r - m X q) - g X (j X r - m X p) + h X (j X q - k X p)) - b X (e X (k X r - m X q) - g X (i X r - m X n) + h X (i X q - k X n)) + c X (e X (j X r - m X p) - f X (i X r - m X n) + h X (i X p - j X n)) - d X (e X (j X q - k X p) - f X (i X q - k X n) + g X (i X p - j X n))

Too much number crunching... here, just for clairity (punched X when i should have done *).

D4 = a * (f * (k * r - m * q) - g * (j * r - m * p) + h * (j * q - k * p)) - b * (e * (k * r - m * q) - g * (i * r - m * n) + h * (i * q - k * n)) + c * (e * (j * r - m * p) - f * (i * r - m * n) + h * (i * p - j * n)) - d * (e * (j * q - k * p) - f * (i * q - k * n) + g * (i * p - j * n))

I'm in the Twilight Zone.... the original reply looks fine in my Premium Blog.

4 x 4 = 16 squares with 10 possible digits on each of them.
10 at 16 exponent
10 at 1 = 10
10 at 2 (Square) = 100
!0 at 16 exponent might be: 10 000 000 000 000 000.
I don't know any Math at all myself.
Good Luck!