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Quantum Quasiality.
Published:
Updated:
Now, that you have seen the Common Math applied to Boolean States.
Let's look at a Quasi Boolean State, where the boolean state is not just an absolute 0 or 1, but a value greater than 0 and less than 1; some Probable state between 0 and 1.
Let's say we can only be 50% certain of A and B are either 0 or 1, then A = 0.5 and B = 0.5.
Then (A And B) = A × B = 0.5 × 0.5 = 0.25
From the truth table in the absolute states we have
(A And B) = A × B
A | B | A And B |
0 | 0 | 0 |
0 | 1 | 0 |
1 | 0 | 0 |
1 | 1 | 1 |
If we average the total outcomes it becomes, (0 + 0 + 0 + 1) / 4 = 1 / 4 = 0.25; just what we got when we took a 50/50 guess on their states.
Let's try the Or condition: (A Or B) = A - (A × B) + B = 0.5 - (0.5 × 0.5) + 0.5 = 0.5 - 0.25 + 0.5 = 0.75
Looking at the truth table for Or,
(A Or B) = A - (A × B) + B
A | B | A Or B |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
Now, average the outcomes, (0 + 1 + 1 + 1) / 4 = 3 / 4 = 0.75
And one more for Xor.
(A Xor B) = A - (A × B) - (A × B) + B = 0.5 - (0.5 × 0.5) - (0.5 × 0.5) + 0.5 = 0.5 - 0.25 - 0.25 + 0.5 = 0.5
Truth table for Xor
(A Xor B) = A - (A × B) - (A × B) + B
A | B | A Xor B |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 0 |
Average the outcomes, (0 + 1 + 1 + 0) / 4 = 2 / 4 = 1 / 2 = 0.5
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