Search

Neural Net Lottery PickerReply
Guys Just for your information. I've run some tests and here are the results. That is for 6/49 game. The aim was simple: finding out what's the break-point where at least 50% of the sample has a 6 of 6 among the x-top ranking numbers. To have a pretty reasonable sample size I skipped 10 games and went on a testing spree to get the answer. Many settings give the same results: to have a 50/50 chance you need to play the pool of 43 top ranking numbers out of the total of 49. I'm afraid
Sep 29, 2015, 9:33 am - adamcustom - Mathematics Forum

6/49 number % question.Reply
For any N / R lottery and Q / R wheel the percent probability S drawn numbers are in Q wheel numbers. P(N, R, Q, S) = 100% Comb(Q, S) Comb(N - Q, R - S) / Comb(N, R) N - Lottery Pool Size R - Lottery Pick Size Q - Wheel Pool Size S - Quantity of Drawn Numbers Matching the Wheel Numbers Where Q N and S R; Comb(n, r) = n! / (r! (n - r)!); n! = n (n - 1) (n - 2) ... 3 2 1 and 0! = 1.
Jul 5, 2015, 3:20 pm - JADELottery - Mathematics Forum

Not sure where to put this question (D3)...Reply
Addendum: as always, each succeeding digit is dependent upon the digit played before it - this is why First, Second, Third placement is vital. It's the magical illusion of numbers, that in theory - again, from scratch - every available box is open to play. But (just like it would be if I'm incorrect about all this), as each digit falls, the pool of boxes shrinks dramatically. Yes, though all boxes would initially be open to play (weird to think, but yes, that would be so), the pool shrinks
Aug 31, 2014, 12:36 pm - PeerGynt - Mathematics Forum

Fibonacci retracement process applied to Pick 5 - Process 1Reply
The idea is to look for the winning numbers in the pool of numbers from the previous drawing, after multiplying the wiining numbers by these percentages. There are still way too many numbers, even when rounded or truncated to choose from, and it isn't a given that the numbers will even be there. However, used in conjunction with another system, or finding a group of percentages that seem to come close can be helpful. I've expanded these percentages to see if I could come closer to narro
Mar 15, 2013, 4:52 pm - karinda - Mathematics Forum

Calculating odds for a subset of numbersReply
Yes, 879 to 1 makes sense but I'm not playing all 200K numbers(that would be nice though!). I'm trying to calculate my odds of picking the winner out of the 200K ticket pool if I play X number of tickets and I know the pool contains the winner 75% of the time. The odds are 200K to 1 at least if I play a single ticket but the part I'm not getting my head around is how the 75% changes things. Does it increrase the odds 25%? So instead of 200K to 1 on a single ticket it's now 250K
Apr 26, 2012, 4:48 pm - mega-mega - Mathematics Forum

Badger 5: My number selection process to youReply
Rtxx: Thanks for your interest in the System. Best to PM Winsumloosesum for info on SpeedSheets. No 'One Single Tab' will give you the numbers. To use, first update the Draws tab for the newest draw, then suggest drawing out the XYAxisChart. Go to XYAxisResults tab, ACROSS Chart, and figure out what Rows, R1 to R9-R10 will get hits. Then go to the DOWN Chart, same tab and figure out what Columns, 0s to 7s-8s, will get hits. Numbers will intersect on your hand drawn chart. Good lu
Dec 3, 2011, 2:49 pm - BlueDuck - Mathematics Forum

Are the following odds correct?Reply
You simply figure the number of combinations in the pool size you're using for your wheel and divide that number by the number of combinations in a pool of 49 numbers. 6/18 = 18564 6/20 = 38760 6/24 = 134596 6/30 = 593775 6/40 = 3838380 and etc. 6/49 = 13983816
Sep 30, 2011, 10:04 am - RJOh - Mathematics Forum

A Simple Wheel Generator Source.Reply
There are three things we need to complete the algorithm process. 1 - Track the pool numbers selected. 2 - Track the wheel combinations generated. 3 - Create the total combinations that are possible for the matching condition. From those three things we can start selection of matching combinations and make a playable combo for our wheel. The process works well, but it has a interesting problem that may occur and is handled by checking for any missing pool numbers not selected.
Apr 9, 2011, 10:48 am - JADELottery - Mathematics Forum

any Maths probability, odds whizz kids ?Reply
Luke, I am assuming that the UK lotto is a 6 of 49 game and that your Pick 3 Hot Picks entails picking three specific numbers between 1 through 49 and matching them out of the six drawn by the lottery. There is ((49!)/((49-6)!))/(6!)=13,983,816 ways to pick (or draw) six numbers from the pool of 49. In case you didnt know, the exclamation mark in the formula above means Factorial in mathematics. There is also ((49!)/((49-3)!))/(3!)=18,424 ways to choose or draw 3 numbers from 49. Si
Apr 25, 2006, 2:56 am - Thoth - Mathematics Forum

Revealed: How to WinReply
Let's take a closer look at what they did. This is my understanding based on the UK article. In case any one wants to try it! The Lottery is a 6/49 number lottery. The syndicate has 17 persons. They need 17 tickets. Here is how they generated the 17 tickets PHASE I 1. They put the 49 numbers on slips of paper. 2. Each person dipped and selected 6 pieces of paper-six numbers. Note: 6*8=48...so only eight persons can select from this pool...and each subsequent pewrson who dips
Oct 26, 2006, 1:47 pm - Fibonacci - Mathematics Forum