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Filter/Reduction Choices

Topic closed. 4 replies. Last post 11 years ago by lottoarchitect.

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Is it better to by likely or unlikely numbers?

Pick the likely numbers [ 3 ]  [37.50%]
Get rid of the unlikely numbers [ 5 ]  [62.50%]
Total Valid Votes [ 8 ]  
Discarded Votes [ 1 ]  
JKING's avatar - Kaleidoscope 3.gif

United States
Member #5599
July 13, 2004
1184 Posts
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Posted: June 6, 2005, 8:57 pm - IP Logged

When you come up with a filter, you are faced with two choices:

1) Go with the most likely numbers, which means you eliminate alot of combinations. But, it also means you may have just filtered out the winning combination.

2) Get rid of the least likely numbers, which means your probably not going to eliminate the winning combination. But, you are left with so many combinations it's near imposible to pick the right one.

Any thoughts?

You are a slave to the choices you have made.  jk

Even a blind squirrel will occasioanlly find an acorn.

    RJOh's avatar - chipmunk
    mid-Ohio
    United States
    Member #9
    March 24, 2001
    19825 Posts
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    Posted: June 7, 2005, 6:35 am - IP Logged

    Why would you include numbers in your combinations that you intended to eliminate later with a filter?  Wouldn't it be easier to eliminate those numbers from the pool of numbers before creating your combinations? 

    RJOh

     * you don't need to buy more tickets, just buy a winning ticket * 
       
                 Evil Looking       

      takeitez's avatar - japheth
      Carters Lake, Ga.
      United States
      Member #5313
      June 29, 2004
      1065 Posts
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      Posted: June 7, 2005, 6:54 am - IP Logged

      If a single digit shows 4 times in the last 4 draws, throw it out.

      It is very rare to see it show 5, even so, I have seen them come 7 in a row about every two years.

      But that is only one digit. Now you need to get rid of 3 or 4 more!

      Easier said than done!

      ez

                No Pity!Guitar  Drum ........ in the long run........

        JKING's avatar - Kaleidoscope 3.gif

        United States
        Member #5599
        July 13, 2004
        1184 Posts
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        Posted: June 7, 2005, 8:49 am - IP Logged

        Rjoh,

          It's not a Question of eleiminating now or later, it's a Question of which way is the best way to eliminate numbers and/or combinations.

          For example,

        Example A

          Column Counts 1-0/10
        126400.069113
        22820407.383602
        3175692045.99489
        4160252441.95291
        51756924.599489
        3819816100%


        Should you just keep 3 and 4 with percentages of 45.99% and 41.95% respectively or keep Items 2 thru 5? Just one pass at Eliminating munbers/combinations?

        When you come up with a filter, you are faced with two choices:

        1) Go with the most likely numbers, which means you eliminate alot of combinations. But, it also means you may have just filtered out the winning combination.

        2) Get rid of the least likely numbers, which means your probably not going to eliminate the winning combination. But, you are left with so many combinations it's near imposible to pick the right one.

        Any thoughts?

         

         

        You are a slave to the choices you have made.  jk

        Even a blind squirrel will occasioanlly find an acorn.

          lottoarchitect's avatar - waveform

          Greece
          Member #2815
          November 18, 2003
          502 Posts
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          Posted: June 7, 2005, 11:57 am - IP Logged

          JKING, I would do none of the above. The reason is simple which you can see even in your example: all cases have achance to occur, some more often some less often. I use a delay approach, where I compare both the frequency of an event and its current delay status. I keep those values that owe to appear (according to delay) and those that have appeared less than statistically expected.

          If you have something to do, at least do it well...