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Is it better to by likely or unlikely numbers?

Pick the likely numbers

[ 3 ]

[ 37.5% ]

Get rid of the unlikely numbers

[ 5 ]

[ 62.5% ]

Total valid votes

[ 8 ]

Discarded votes

[ 1 ]

JKING

United States
Member #5,599
July 13, 2004
1,207 Posts
Offline

Jun 6, 2005, 8:57 pm

When you come up with a filter, you are faced with two choices:

1) Go with the most likely numbers, which means you eliminate alot of combinations. But, it also means you may have just filtered out the winning combination.

2) Get rid of the least likely numbers, which means your probably not going to eliminate the winning combination. But, you are left with so many combinations it's near imposible to pick the right one.

Any thoughts?

You are a slave to the choices you have made. jk

Even a blind squirrel will occasionally find an acorn.

There is no elevator to success, you will have to take the stairs.
RJOh

100

mid-Ohio
United States
Member #9
March 24, 2001
20,272 Posts
Offline

Jun 7, 2005, 6:35 am

Why would you include numbers in your combinations that you intended to eliminate later with a filter? Wouldn't it be easier to eliminate those numbers from the pool of numbers before creating your combinations?

RJOh

* you don't need to buy every combination, just the winning ones *
takeitez

Carters Lake, Ga.
United States
Member #5,313
June 29, 2004
1,065 Posts
Offline

Jun 7, 2005, 6:54 am

If a single digit shows 4 times in the last 4 draws, throw it out.

It is very rare to see it show 5, even so, I have seen them come 7 in a row about every two years.

But that is only one digit. Now you need to get rid of 3 or 4 more!

Easier said than done!

ez

........ in the long run........
JKING

United States
Member #5,599
July 13, 2004
1,207 Posts
Offline

Jun 7, 2005, 8:49 am

Rjoh,

It's not a Question of eleiminating now or later, it's a Question of which way is the best way to eliminate numbers and/or combinations.

For example,

Example A

Column Counts 1-0/10

1 2640 0.069113

2 282040 7.383602

3 1756920 45.99489

4 1602524 41.95291

5 175692 4.599489

3819816 100%

Should you just keep 3 and 4 with percentages of 45.99% and 41.95% respectively or keep Items 2 thru 5? Just one pass at Eliminating munbers/combinations?

When you come up with a filter, you are faced with two choices:

1) Go with the most likely numbers, which means you eliminate alot of combinations. But, it also means you may have just filtered out the winning combination.

2) Get rid of the least likely numbers, which means your probably not going to eliminate the winning combination. But, you are left with so many combinations it's near imposible to pick the right one.

Any thoughts?

You are a slave to the choices you have made. jk

Even a blind squirrel will occasionally find an acorn.

There is no elevator to success, you will have to take the stairs.
lottoarchitect

Greece
Member #2,815
November 18, 2003
502 Posts
Offline

Jun 7, 2005, 11:57 am

JKING, I would do none of the above. The reason is simple which you can see even in your example: all cases have achance to occur, some more often some less often. I use a delay approach, where I compare both the frequency of an event and its current delay status. I keep those values that owe to appear (according to delay) and those that have appeared less than statistically expected.

If you have something to do, at least do it well...