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# How to Beat Powerball: And drastically reduce the odds (theory)...

Topic closed. 77 replies. Last post 10 years ago by Stack47.

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United States
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June 16, 2006
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 Posted: June 1, 2007, 9:31 am - IP Logged

It's pretty easy to get yourself into dellusions of grandeur....

'Gee, I spend \$10, ad I got 2 numbers, if I spend \$20 I might get 3, if I spend \$50 I might get 4, and gee: if I spend \$500 I may hit the jackpot........ yeah, that's what I will do.

Story: Back in about 1990, the first time I ever played Powerball, I played 5 games, and I got money back from all 5 games, so I figured this was EASY, so the following week I spent about \$150, and I got TWO numbers in ONE game - that was it.  That was before I started really becoming interested in the sport, which was in early 2006. Now I get a 3x5 at least once a week, if not twice, and I play 10 games per drawing. I'm still losing slightly overall, but I've hit a bunch of 4x5's in the last year.

As I have said before, my entire theory is based on things not to repeat (for awhile), which pushes me towards things that are more likely to happen, sometimes I get pretty lucky.

United States
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 Posted: June 1, 2007, 9:34 am - IP Logged

I am not explaining the split (numbers from 1-27 & 28-55), i know what those are...YOu can add that pattern (the split) to it if you like and i think it will be a great idea...I did not add that pattern (the split 1-27 & 28-55) because i believe in TnTea's 2-2-1 types, that's why i didn't post it...What i am explaining is the ending digit a particular number ends with...Here is an explanation i wrote (you may not have read it)....

" First you look at what ending digits are...For example the number 15, the ending digit is 5, the number 28, the ending digit is 8 (basically the digit at the right side)...The number 19 has ending digit of 9, the number 11 has ending digit of 1...NOTE: The numbers that have ending digit of 0, example 20, 30, 40 i call them the 10 ending digit and not the 0 ending digit...So what is a high ending digit and what is a low ending digit? Low ending digits are numbers that end from 1 to 5...Example: 1,11,21,31,41,51; 2,12,22,32,42,52; 3,13,23,33,43,53; 4,14,24,34,44,54 & 5,15,25,35,45,55 are all LOW ENDING DIGITS or LED..."

"High ending digits are (assuming is a pick5/55 or lotto5/55): 6,16,26,36,46; 7,17,27,37,47; 8,18,28,38,48; 9,19,29,39,49; 10,20,30,40,50 are all HIGH ENDING DIGIT or HED: (Again numbers have ending digit in "0" are considered "10" and not "0"....So basically low ending digits are numbers that have ending digits from 1 to 5 and high ending digits are numbers that have ending digits from 6 to 10..."

Please post about 10 games you think will hit this weekend so we can see if your system has any merit.

Kentucky
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 Posted: June 2, 2007, 5:38 pm - IP Logged

I assume he doesn't plan to spend \$20,000 for real but just want to know the answer to his question.  If he's not capable of making up those lists then he  probably hasn't thought about his theory enough to put it to paper.

You can only get 5 combinations on Rolling Cash 5 playslips and I usually make a couple mistakes filling out 6 or 7 playslips. And there is always the concern that the clerk will run the same playslip twice or forget one of them.

I can't comprehend filling out 5000 playslips, handing them to a clerk and finding out they didn't run one or two of them.

mid-Ohio
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 Posted: June 2, 2007, 5:47 pm - IP Logged

You can only get 5 combinations on Rolling Cash 5 playslips and I usually make a couple mistakes filling out 6 or 7 playslips. And there is always the concern that the clerk will run the same playslip twice or forget one of them.

I can't comprehend filling out 5000 playslips, handing them to a clerk and finding out they didn't run one or two of them.

I can't comprehend handing a clerk \$20,000 for lottery tickets, even QPs.

True some clerk will play the same slips twice but that's because after they run them they put them back in pile of slips that have not been played yet.  When I find one that dumb I stop them before they've run the third slip.

* you don't need to buy more tickets, just buy a winning ticket *

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 Posted: June 3, 2007, 12:43 am - IP Logged

I can't comprehend playing 50 games, let alone 20,000.

Honduras
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 Posted: June 3, 2007, 3:18 am - IP Logged
Here is the 3rd pattern...I call this pattern the HEDABCD:...It stands for High Ending digits ABCD...Here you are tracking how many times the High Ending digits repeat..We are only tracking the High Ending Digits combinations alone, we are not tracking the Low Ending Digits (LED)...For example if the combination is: 10-23-42-48-54 then the High Ending digit's ABCD would be: AB...Why because the combination 10-23-42-48-54 only has 2 high ending digits that are 10 & 48..And they are different, so they will be: AB...If the combination had 3 DIFFERENT high ending digits then the letters would be: ABC....If the combination had 2 high ending digits that ARE THE SAME, then the designated letters will be: AA...If the combination had 3 high ending digits that ARE THE SAME, then the designated letters will be: AAA....If the combination had 3 high ending digits, and TWO ARE THE SAME, then the designated letters will be: AAB...If the combination had 4 ending digits and 2 were the same and the 2 left were different than the first two, but were THE SAME, then the designated letters will be: AABB..(in other words 1 pairs were the same & 1 more pairs were the same but the 2 pairs were different)....

Remember we are tracking the "High Ending Digits" ONLY, and not the low ending digits... If you track the High Ending Digits ABCD's from the first Powerball drawing of 2006 'til April 21st, 2007 this is what you will have:

1. AB        36. A          71. A            106. AAB
2. A          37. A          72. ABC          107. A
3. ABC       38. ABCD      73. ABC          108. A
4. AABC    39. AB        74. AABC        109. ABC
5. AB        40. A          75. AABC        110. AB
6. AB        41. A          76. AB            111. AAA
7. AAB      42. AAB        77. AB            112. ABCD
8. AAB      43. AAB        78. ABC          113. A
9. A        44. AABC      79. AABC        114. A
10. AB      45. AAAB      80. A              115. AB
11. A       46. AAA        81. AB            116. A
12. ABC    47. AB          82. ABC          117. AB
13. AB      48. AABC        83. A            118. A
14. A      49. A            84. AA          119. ABC
15. AB      50. ABCD        85. ABC          120. AB
16. ABC    51. AB           86. AB          121. A
17. AB      52. A            87. ABC         122. AB
18. A        53. AB          88. A            123. AABC
19. A        54. ABC        89. AB          124. A
20. AB      55. ABC        90. ABC          125. ABC
21. ABC   56. AABC       91. AB          126. AAA
22. A      57. AB          92. ABC        127. AB
23. AA      58. AB          93. AB          128. AABB
24. ABC    59. AB          94. AAB        129. AABC
25. A       60. AAB        95. AAB        130. AAB
26. AA      61. ABC        96. AB          131. AABB
27. AAA    62. ABC        97. ABC        132. A
28. ------    63. AB          98. AB          133. AB
29. AA      64. AB          99. A            134. ABC
30. AAB  65. AB          100. ABC        135. AB
31. A      66. AB         101. AA          136. AB
32. ABC    67. AAB       102. AB
33. AB      68. AAB        103. ABC
34. AAB    69. A          104. ABC
35. ABC    70. AAB        105. A

This is the third pattern...If you look at the AB & ABC they've played 68 times (or 50%), while AAB, AABB, AA, & AAA have played 34 times out of 136 (or 25%)....If we can eliminate the AAB, AA, AABB, & the AAA from our combinations and leave the rest or make up our future combinations with the rest, we will be O.K...Looking at the HED & LED this way (as ABCD), looks like the Double & Single DNA strands...But in this case they will be the Double & Single DNA strands of numbers...
Is my belief, that out of those 6,376 we will be able to eliminate 1,500 combinations (to be on the safe side) that make up the AAB, AA, AABB, & AAA....And from the 19,766 we would be able to eliminate 3,000 combinations (to be on the safe side) that also make up for the AAB, AA, AABB, & AAA....So this will leave you with 4,876 (6,376 - 1,500 = 4,876) AND it will leave us with 16,766 ( 19,766 - 3,000 = 16,766)....So your odds would be 1 in 19,766 or 1 in 4,876 & not 1 in 150 million....And this is only looking at the HED, is not looking at the LED (Low Ending Digits) reduction we have to make....The bad news is that currently there is no software in the world that will reduce all of Powerball combinations the way we like it...

NOTE: And i haven't even added the Split yet (1-27, 27-55)....You wouldn't be able to win or have the best chances to hit Powerball everyday, but every other day/draw (because of the bonus ball factor)...
mid-Ohio
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 Posted: June 3, 2007, 8:18 am - IP Logged

I can't comprehend playing 50 games, let alone 20,000.

Jack Whittaker brought a 100 combinations when he won the PowerBall and so did the guy in Michigan who split the BigGame jackpot(largest ever) with a guy in Illinois.

* you don't need to buy more tickets, just buy a winning ticket *

United States
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 Posted: June 3, 2007, 6:00 pm - IP Logged

Jack Whittaker brought a 100 combinations when he won the PowerBall and so did the guy in Michigan who split the BigGame jackpot(largest ever) with a guy in Illinois.

That's fine, but I betcha there are far more losers that have bought 100 tickets or more than there are winners that have bought 10 - or less...

If someone is willing to give me a fair chunk of money every single drawing like clockwork, I can fit that into my game playing..

Kentucky
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 Posted: June 3, 2007, 6:12 pm - IP Logged

Pumpi,

If I wanted to play "HOHOO" in the next PB drawing, how many combinations would that be?

mid-Ohio
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 Posted: June 3, 2007, 6:38 pm - IP Logged

That's fine, but I betcha there are far more losers that have bought 100 tickets or more than there are winners that have bought 10 - or less...

If someone is willing to give me a fair chunk of money every single drawing like clockwork, I can fit that into my game playing..

There are far more losers than winners in any lottery no matter how you classify them, I was simply making the point that it's not that hard to comprehend someone playing 50 lottery combinations.  States are finding players will spend \$50 or a scratch-off ticket too.

* you don't need to buy more tickets, just buy a winning ticket *

Honduras
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August 29, 2005
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 Posted: June 4, 2007, 3:25 pm - IP Logged
Here is the 3rd pattern...I call this pattern the HEDABCD:...It stands for High Ending digits ABCD...Here you are tracking how many times the High Ending digits repeat..We are only tracking the High Ending Digits combinations alone, we are not tracking the Low Ending Digits (LED)...For example if the combination is: 10-23-42-48-54 then the High Ending digit's ABCD would be: AB...Why because the combination 10-23-42-48-54 only has 2 high ending digits that are 10 & 48..And they are different, so they will be: AB...If the combination had 3 DIFFERENT high ending digits then the letters would be: ABC....If the combination had 2 high ending digits that ARE THE SAME, then the designated letters will be: AA...If the combination had 3 high ending digits that ARE THE SAME, then the designated letters will be: AAA....If the combination had 3 high ending digits, and TWO ARE THE SAME, then the designated letters will be: AAB...If the combination had 4 ending digits and 2 were the same and the 2 left were different than the first two, but were THE SAME, then the designated letters will be: AABB..(in other words 1 pairs were the same & 1 more pairs were the same but the 2 pairs were different)....

Remember we are tracking the "High Ending Digits" ONLY, and not the low ending digits... If you track the High Ending Digits ABCD's from the first Powerball drawing of 2006 'til April 21st, 2007 this is what you will have:

1. AB        36. A          71. A            106. AAB
2. A          37. A          72. ABC          107. A
3. ABC       38. ABCD      73. ABC          108. A
4. AABC    39. AB        74. AABC        109. ABC
5. AB        40. A          75. AABC        110. AB
6. AB        41. A          76. AB            111. AAA
7. AAB      42. AAB        77. AB            112. ABCD
8. AAB      43. AAB        78. ABC          113. A
9. A        44. AABC      79. AABC        114. A
10. AB      45. AAAB      80. A              115. AB
11. A       46. AAA        81. AB            116. A
12. ABC    47. AB          82. ABC          117. AB
13. AB      48. AABC        83. A            118. A
14. A      49. A            84. AA          119. ABC
15. AB      50. ABCD        85. ABC          120. AB
16. ABC    51. AB           86. AB          121. A
17. AB      52. A            87. ABC         122. AB
18. A        53. AB          88. A            123. AABC
19. A        54. ABC        89. AB          124. A
20. AB      55. ABC        90. ABC          125. ABC
21. ABC   56. AABC       91. AB          126. AAA
22. A      57. AB          92. ABC        127. AB
23. AA      58. AB          93. AB          128. AABB
24. ABC    59. AB          94. AAB        129. AABC
25. A       60. AAB        95. AAB        130. AAB
26. AA      61. ABC        96. AB          131. AABB
27. AAA    62. ABC        97. ABC        132. A
28. ------    63. AB          98. AB          133. AB
29. AA      64. AB          99. A            134. ABC
30. AAB  65. AB          100. ABC        135. AB
31. A      66. AB         101. AA          136. AB
32. ABC    67. AAB       102. AB
33. AB      68. AAB        103. ABC
34. AAB    69. A          104. ABC
35. ABC    70. AAB        105. A

This is the third pattern...If you look at the AB & ABC they've played 68 times (or 50%), while AAB, AABB, AA, & AAA have played 34 times out of 136 (or 25%)....If we can eliminate the AAB, AA, AABB, & the AAA from our combinations and leave the rest or make up our future combinations with the rest, we will be O.K...Looking at the HED & LED this way (as ABCD), looks like the Double & Single DNA strands...But in this case they will be the Double & Single DNA strands of numbers...
Is my belief, that out of those 6,376 we will be able to eliminate 1,500 combinations (to be on the safe side) that make up the AAB, AA, AABB, & AAA....And from the 19,766 we would be able to eliminate 3,000 combinations (to be on the safe side) that also make up for the AAB, AA, AABB, & AAA....So this will leave you with 4,876 (6,376 - 1,500 = 4,876) AND it will leave us with 16,766 ( 19,766 - 3,000 = 16,766)....So your odds would be 1 in 19,766 or 1 in 4,876 & not 1 in 150 million....And this is only looking at the HED, is not looking at the LED (Low Ending Digits) reduction we have to make....The bad news is that currently there is no software in the world that will reduce all of Powerball combinations the way we like it...

NOTE: And i haven't even added the Split yet (1-27, 27-55)....You wouldn't be able to win or have the best chances to hit Powerball everyday, but every other day/draw (because of the bonus ball factor)...

I made a mistake...Number 14 is AB....Number 39 is: A....

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 Posted: June 4, 2007, 10:22 pm - IP Logged

I am sure there are, but I could never do it.

10 leads to 20, 20 leads to 25, 25 leads to 40, then to 50, then 100, then you file bankruptcy...

United States
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 Posted: June 4, 2007, 10:25 pm - IP Logged

Pumpi,

If I wanted to play "HOHOO" in the next PB drawing, how many combinations would that be?

Are you calling someone a 'Ho' ?

That got Don Imus fired, buddy.  (LOL)

Honduras
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 Posted: June 5, 2007, 3:16 am - IP Logged

Please post about 10 games you think will hit this weekend so we can see if your system has any merit.

I am trying to refine this system to see if it will be perfect..I can't post it right now...Also i am busy trying to lose some weight and that takes time away from me, it only gives me time at night to log on to LP....Predictions take a lot of time from someone...Also i will not be predicting numbers but this is how my prediction is going to go....I"ll tell you for the nex draw or two whether is going to be 3 evens and 2 odds or 2 odds and 3 evens or 4 odds and 1 even, i'll tell you what position each even and each odd is going to be (thus HOOHO types, etc), i'll tell you what sum the winning combination is going to have, i'll tell you whether is AAB OR ABC OR AABB, etc of the high ending digits and low ending digits, i'll tell you what's the ratio of the split whether is going to be 3 high numbers and 2 low numbers (low numbers been 1-27 and high numbers been 27-55) & i'll tell you whether is 3 high ending digits and 2 low ending digits or 4 high ending digits and 1 low ending digits, etc...But give you numbers i can't do that because i don't know which numbers are going to play...Wish i did...Plus i am bad at predicting numbers...And i am paranoid that the lottery corporation will see my predictions and do more pre-tests so that what i predict will not come out...It wouldn't surprise me if they did...

Honduras
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August 29, 2005
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 Posted: June 5, 2007, 4:04 am - IP Logged
Here is the 4th pattern...I call this pattern the LEDABCD:...It stands for Low Ending digits ABCD...Here you are tracking how many times the Low Ending digits repeat..We are only tracking the Low Ending Digits combinations alone, we are not tracking the High Ending Digits (HED, we did that already)...For example if the combination is: 10-23-42-48-54 then the Low Ending digit's ABCD would be: ABC...Why because the combination 10-23-42-48-54 has 3 Low ending digits that are 23, 42 & 54..And they are different, so they will be: ABC...If the combination had 2 low ending digits that ARE THE SAME, then the designated letters will be: AA....If the combination had 2 DIFFERENT low ending digits then the letters would be: AB....If the combination had 4 low ending digits that ARE DIFFERENT, then the designated letters will be: ABCD...If the combination had 3 low ending digits that ARE THE SAME, then the designated letters will be: AAA....If the combination had 3 low ending digits, and TWO ARE THE SAME, then the designated letters will be: AAB...If the combination had 4 low ending digits and 2 were the same and the 2 left were different than the first two, but were THE SAME, then the designated letters will be: AABB..(in other words 1 pairs were the same & 1 more pairs were the same but the 2 pairs were different)....

Remember we are tracking the "Low Ending Digits" ONLY, and not the high ending digits (we tracked those already)... If you track the Low Ending Digits' ABCD's from the first Powerball drawing of 2006 'til April 21st, 2007 this is what you will have:

1. ABC         36. AABC        71. AABC        106. AB

2. AABC        37. AABC        72. AB          107. ABCD

3. AB          38. A            73. AA          108. AABC

4. A            39. AABC        74. A            109. AB

5. ABC        40. ABCD        75. A             110. ABC

6. AAB        41. AABC        76. ABC          111. AB

7. AB          42. AB            77. AAB          112. A

8. AB          43. AB            78. AB          113. AABB

9. AABC       44. A              79. A            114. AABB

10. ABC        45. A            80. ABCD        115. AAB

11. AABC      46. AA            81. AAB          116. AABB

12. AB          47. AAB          82. AB           117. ABC

13. AAB        48. A            83. AABC        118. AAAB

14. ABC        49. ABCD        84. AAB        119. AA

15. AAB        50. A            85. AB          120. ABC

16. AB          51. ABC          86. ABC          121. AABC

17. AAB        52. AABC        87. AB          122. ABC

18. AABC      53. ABC          88. AABC        123. A

19. AABC       54. AB          89. ABC          124. AABC

20. ABC        55. AB          90. AA            125. AA

21. AB          56. A            91. ABC           126. AA

22. ABCD      57. AAB          92. AB            127. AAB

23. ABC        58. AAB          93. AAB          128. A

24. AB         59. ABC         94. AA           129. A

25. AAAB      60. AB          95. AA            130. AB

26. ABC        61. AB          96. ABC          131. A

27. AB          62. AB          97. AB            132. ABCD

28. AABBC     63. ABC         98. AAB          133. ABC

29. ABC        64. AAB        99. AABC        134. AB

30. AA          65. AAB        100. AB            135. ABC

31. ABCD        66. AAB         101. AAB         136. ABC

32. AB          67. AB          102. AAB

33. ABC         68. AB          103. AB

34. AB           69. AAAB       104. AB

35. AB          70. AB          105. AABC

This is the Fourth Pattern...If you look at the 136 draws from the first Powerball draw of 2006, 'till April 21st, 2007 and you look at the AB, ABC & ABCD they've played 83 times out of 136 (or 61%), while AAB, AABB, AA, AABC & AAA have played 53 times out of 136 (or 39%)....Which is a good number...If you can make your combinations have LED of AB, ABC, ABCD you will be good...

Is my belief, that out of those 4,876 we will be able to eliminate 1,500 combinations (to be on the safe side) that make up the Low Ending digits' AAB, AA, AABB, AABC & AAA....And from the 16,766 we would be able to eliminate 3,000 combinations (to be on the safe side) that also make up for the AAB, AA, AABB, AABC & AAA....So this will leave you with 3,376 (4,876 - 1,500 = 3,376) AND it will leave us with 13,766 ( 16,766 - 3,000 = 13,766)....So your odds would be theoretically 1 in 13,376 or 1 in 3,376 & not 1 in 150 million....And this is looking at the LED, is not looking at Low numbers and High numbers (the split) (1-27 and 28-55 ratio) reduction we have to make....The bad news is that currently there is no software in the world that will reduce all of Powerball combinations the way we would like it...

NOTE: You wouldn't be able to win or have the best chances to hit Powerball everyday, but every other day/draw (because of the bonus ball factor)...Actually you will have the best odd or could win Powerball second prize 5/5 match everyday, but the 5/5 + 1 you will win it or have the best odds every other day/draw...

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