I made big errors in (On) my post, maybe I was (And still am) too tired and also I am getting to be too old.
But never mind that.
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This was one of the things that were wrong:
"The last 10 draws say that the 2 digits raw technique without any improvements might produce $16 over 2 played draws at 50 cents a number or $32 over the same 2 played draws at $1 per combo."
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This all is just and 'If" situation, as no draws were played for real.
56 combos played 2 times = 112 combos.
Won once and Lost once at $1 per combo = $112 spent and $80 Won = $32 Lost on those 2 (PLayable) draws if they had been played.
As you see, no money was won, just money lost.
This is for a 2 digit technique.
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MichDew
For a 2 digit technique you would not play any of the digits from the last draw.
On a double such as 006 there are of course only 2 digits, the 0 and the 6.
As there are 10 possible digits on a pick 3 game, then what we have left is the other 8 digits, but you would play only the singles and not the doubles.
8 digits Box wheeled = 56 boxed combos.
123, 124, 125, 127, 128, 129, 134, 135, 137, 138, 139, 145, 147, 148, 149, 157, 158, 159, 178, 179, 189, 234, 235, 237, 238, 239, 245, 247, 248, 249, 257, 258, 259, 278, 279, 289, 345, 347, 348, 349, 357, 358, 359, 378, 379, 389, 457, 458, 459, 478, 479, 489, 578, 579, 589, 789
56 Combos
I guess that I made many mistakes, I wonder if I am still making them right now.
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As the 590 combo came next then the 0 was a repeat from the 006, so boxed = 059 so if we had played:
123, 124, 125, 127, 128, 129, 134, 135, 137, 138, 139, 145, 147, 148,149, 157, 158, 159, 178, 179, 189, 234, 235, 237, 238, 239, 245, 247,248, 249, 257, 258, 259, 278, 279, 289, 345, 347, 348, 349, 357, 358,359, 378, 379, 389, 457, 458, 459, 478, 479, 489, 578, 579, 589, 789
We would had lost, as we are playing combos that only have digits that are not on the last draw.
So No = Lost if played according to the 2 digit technique.
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On:
2 8 4 N
6 2 9
The N = Lost if played according to the 3 digit technique as the 2 repeated from the last draw to the next draw.
7 Digits wheeled: = 35 boxed combos.
013, 014, 015, 017, 018, 034, 035, 037, 038, 045, 047, 048, 057, 058, 078, 134, 135, 137, 138, 145, 147, 148, 157, 158, 178, 345, 347, 348, 357, 358, 378, 457, 458, 478, 578
And as the 2 repeated then 284 (248) was not one of the 35 boxed numbers played.
That is, if they had been played, they were not, this is not for real, just testing on past draws.
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When a double is the last past draw, you then can either use the 2 digits technique on it or by-pass the double and use the last single combo that came out and then use the 3 digits technique.
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You, of course, should only play, if you think that there will not be any digits from the last draw repeating on the very next draw and even then you should use some other kind of extra filtration, to reduce the played combos even more.
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I hope that I didn't make any mistakes this time, but I don't know.