Quick Links You last visited December 10, 2016, 5:13 pm All times shown are Eastern Time (GMT5:00)  Gap Strategy  Texas Lotto 0828San Angelo, Texas United States Member #1097 January 31, 2003 1394 Posts Offline  Posted: August 28, 2010, 8:23 pm  IP Logged  
http://www.lotterypost.com/thread/219231
Pumpi76 initiated a thread where he suggested that jackpots could be won by playing numbers suggested by the entire LP membership. Since no one came forward with a plausible idea as to how the 96,000+ numbers could be brought together in a usable way, due mainly to an apparent lack of interest, the discussion shifted to systems, strategies, workouts, etc. One member, RJOH, demonstrated his playing methods by generating 200 combinations for the 0825 PB drawing. These were posted in an open forum. His evaluation is available. Another member, Luminus, stressed his method, which is a variation of a popular commercial system. This post is a followup to my promise to demonstrate Gap Strategy for the 0828 Texas Lotto drawing. I was going to generate 100 combinations, but I decided 50 would be adequate. Besides, my pockets are shallow. Texas Lotto is a Pick 6 of 54 numbers game. Using various data streams, the first step in using Gap Strategy is choosing one or more 'structures' to guide number selections. Since the presence of all 6 numbers in a winning combination is rare, the combinations played must have 2, 3, 4 or 5 of the 6 number groups, A, B, C, D, E and F. For example: Winning combination 1.10.23.31.43.50 becomes ABCDEF. There is only one combination having this structure, which is called a 6point structure. There are 6 1point structures, 15 2point structures, 20 3point structures, 15 4point structures and 6 5point structures. A current structure inventory shows that 4point structures come up more often than any other structure, followed by 5point and 3point. Positional analysis inventory for Postions 1 and 2 shows that 'AB' has come up 131 times, 'BC' 56 times, 'AC' 37 times, 'BD' 11 times. Simular inventories for Positions 3 and 4 shows 'CD' 42 times, 'CD' 36 times, 'CE' 20 times, 'E.' 20 times, 'EF' 19 times, 'DF' 16 times, and 'D.' 12 times. (D. is correct) The inventory for Positions 4 and 5, yes, 4 and 5, shows 'EF' 61 times, 'DE' 59 times, 'DF' 31 times, 'E.' 21 times. These are mainly from 5point structures. (E. is correct) Using other data, I've decided (guessed) that the winning combination for 0828 will be either a 3point or a 4point structure. Specifically ABCE, ABDE, BCEF, BCD or BDE. Further, I decided to play 10 combinations for each of the possibilities. Wihout going into the nitty gritty, here are worksheet headers and the combinations for each structure. BCD  3 numbers each letter, 9 total numbers, 10 sets, 60 spots to fill, All numbers used 6 times, 6 numbers used 7 times. Numbers to be wheeled: 11.12.16.23.25.29.31.33.39 Using LS2004 wheeler, the 10 combinations are: 11.23.25.29.33.39; 11.12.23.29.31.39; 11.16.25.29.31.39; 11.16.23.29.31.33; 12.16.23.25.31.33; 11.16.25.31.33.39; 12.23.25.29.31.33; 12.16.23.25.33.39; 11.12.16.23.29.39; 12.16.25.29.31.33 BDE  3 numbers each letter, 9 total numbers, 10 sets, 60 spots to fill, All numbers used 6 times, 6 numbers used 7 times. Numbers in wheel: 12.15.17.30.32.33.40.42.46 Combinations to play are: 12.15.17.30.40.42; 12.15.17.32.40.42; 12.15.30.32.33.46; 12.15.30.33.40.46; 12.17.30.33.42.46; 12.17.32.33.40.46; 12.17.32.33.42.46; 15.17.30.32.33.40; 15.30.32.40.42.46; 17.30.33.40.42.46 ACDE  3 numbers each letter, 12 total numbers, 10 sets, 60 spots, All numbers 5 times. Numbers in wheel: 6.8.9.23.25.29.31.33.39.43.44.46 Combinations to play are: 6.8.9.25.39.43; 9.25.29.31.44.46; 8.25.31.33.44.46; 8.23.29.31.39.44; 8.9.23.29.33.44; 6.9.23.31.33.46; 6.9.23.39.43.46; 6.23.25.33.39.43; 8.29.31.43.44.46; 6.25.29.33.39.43 ABCE  3 numbers for each letter, 12 total numbers, 10 sets, 60 spots to fill, All numbers 5 times. Numbers in wheel: 3.5.6.11.12.16.21.22.25.40.42.46 Combinations to play are: 3.5.6.12.25.40; 5.11.21.22.25.42; 6.16.25.40.42.46; 3.12.16.21.40.46; 3.5.11.16.22.46; 6.16.21.22.42.46; 5.6.12.21.22.42; 3.11.12.22.25.40; 5.11.12.16.40.42; 3.6.11.21.25.46 BCEF  3 numbers for each letter, 12 total numbers, 10 sets, 60 spots, All numbers 5 times. Numbers in wheel: 11.12.17.21.23.25.40.44.46.51.53.54 Combinations to play: 11.23.44.46.51.53; 17.21.23.25.46.53; 12.25.40.44.51.54; 11.12.23.46.51.54; 11.12.17.21.40.53; 12.17.25.40.44.53; 17.21.25.44.51.53; 11.21.40.46.51.54; 11.23.25.40.44.54; 11.17.21.23.46.54 These are my 'best guesses' based on the Gap Strategy data streams. Other players using the workouts could very well reach other conclusions. Gap Strategy is versatile. That is, if I only wanted to play 5 sets for a pick 6 game, I'd select a scheme that would provide a minimum of 3 numbers for each letter, 9 numbers overall, 30 spots to fill and a wheel setting to generate 5 sets. I'd then have to adjust the recommended combinations to ensure that all combinations have at least one of the nine numbers in the wheel. I could, of course, adopt a scheme where I would generate 5 or more numbers for each letter in the structure to be played. However, there are limits. Playing 5 numbers for 4 letters would require more than 10 combinations. I can't say exactly how many because I've never contemplated working with such a scheme. Thanks for your interest.
Bobby623 
  
San Angelo, Texas United States Member #1097 January 31, 2003 1394 Posts Offline  Posted: August 28, 2010, 11:42 pm  IP Logged  
Winning numbers: 1.12.25.36.39.45 = ABCDDE = ABCDE = 5point structure. One $3 winner. Several 'missed by one.' The $8 million jackpot was won in a city to be announced. Thanks for your interest.   
Texas United States Member #55889 October 23, 2007 5615 Posts Offline  Posted: August 29, 2010, 2:47 pm  IP Logged  
Winning numbers: 1.12.25.36.39.45 = ABCDDE = ABCDE = 5point structure. One $3 winner. Several 'missed by one.' The $8 million jackpot was won in a city to be announced. Thanks for your interest. Winning tic purchased in Hooks, Tx, wherever that is . Tx IS a big state. A couple weeks ago there was a story about the Tx Lottery Comm being short of money due to 2 jackpot wins within 2 weeks, now we have another win about 2 weeks from the last win. bobby623, that six decade combo that was drawn is pretty rare. I did that kind of analysis recently, and you are correct that 4 decades play the most. However, the person that won last night apparently didn't know or didn't care, he picked his own numbers. CAN'T WIN IF YOU'RE NOT IN A DOLLAR AND A DREAM (OR $2)
  
Texas United States Member #55889 October 23, 2007 5615 Posts Offline  Posted: August 29, 2010, 3:15 pm  IP Logged  
Correction.... 5 decades drawn last night. CAN'T WIN IF YOU'RE NOT IN A DOLLAR AND A DREAM (OR $2)
  
San Angelo, Texas United States Member #1097 January 31, 2003 1394 Posts Offline  Posted: August 29, 2010, 4:55 pm  IP Logged  
rcbbuckeye The winning numbers could fit birthdays or other personal dates. Or, maybe the winner is using a similar strategy and decided to play the 5point structure. I thought about dropping one 4point and going with a 5point, but none of the other data streams supported a change. That's the basic lottery story  you never know. By the way  Hooks is in Bowie County in far, far northeast Texas. It's within driving range of Arkansas.   
Tx United States Member #4570 May 4, 2004 5180 Posts Offline  Posted: September 5, 2010, 1:16 pm  IP Logged  
http://www.lotterypost.com/thread/219231
Pumpi76 initiated a thread where he suggested that jackpots could be won by playing numbers suggested by the entire LP membership. Since no one came forward with a plausible idea as to how the 96,000+ numbers could be brought together in a usable way, due mainly to an apparent lack of interest, the discussion shifted to systems, strategies, workouts, etc. One member, RJOH, demonstrated his playing methods by generating 200 combinations for the 0825 PB drawing. These were posted in an open forum. His evaluation is available. Another member, Luminus, stressed his method, which is a variation of a popular commercial system. This post is a followup to my promise to demonstrate Gap Strategy for the 0828 Texas Lotto drawing. I was going to generate 100 combinations, but I decided 50 would be adequate. Besides, my pockets are shallow. Texas Lotto is a Pick 6 of 54 numbers game. Using various data streams, the first step in using Gap Strategy is choosing one or more 'structures' to guide number selections. Since the presence of all 6 numbers in a winning combination is rare, the combinations played must have 2, 3, 4 or 5 of the 6 number groups, A, B, C, D, E and F. For example: Winning combination 1.10.23.31.43.50 becomes ABCDEF. There is only one combination having this structure, which is called a 6point structure. There are 6 1point structures, 15 2point structures, 20 3point structures, 15 4point structures and 6 5point structures. A current structure inventory shows that 4point structures come up more often than any other structure, followed by 5point and 3point. Positional analysis inventory for Postions 1 and 2 shows that 'AB' has come up 131 times, 'BC' 56 times, 'AC' 37 times, 'BD' 11 times. Simular inventories for Positions 3 and 4 shows 'CD' 42 times, 'CD' 36 times, 'CE' 20 times, 'E.' 20 times, 'EF' 19 times, 'DF' 16 times, and 'D.' 12 times. (D. is correct) The inventory for Positions 4 and 5, yes, 4 and 5, shows 'EF' 61 times, 'DE' 59 times, 'DF' 31 times, 'E.' 21 times. These are mainly from 5point structures. (E. is correct) Using other data, I've decided (guessed) that the winning combination for 0828 will be either a 3point or a 4point structure. Specifically ABCE, ABDE, BCEF, BCD or BDE. Further, I decided to play 10 combinations for each of the possibilities. Wihout going into the nitty gritty, here are worksheet headers and the combinations for each structure. BCD  3 numbers each letter, 9 total numbers, 10 sets, 60 spots to fill, All numbers used 6 times, 6 numbers used 7 times. Numbers to be wheeled: 11.12.16.23.25.29.31.33.39 Using LS2004 wheeler, the 10 combinations are: 11.23.25.29.33.39; 11.12.23.29.31.39; 11.16.25.29.31.39; 11.16.23.29.31.33; 12.16.23.25.31.33; 11.16.25.31.33.39; 12.23.25.29.31.33; 12.16.23.25.33.39; 11.12.16.23.29.39; 12.16.25.29.31.33 BDE  3 numbers each letter, 9 total numbers, 10 sets, 60 spots to fill, All numbers used 6 times, 6 numbers used 7 times. Numbers in wheel: 12.15.17.30.32.33.40.42.46 Combinations to play are: 12.15.17.30.40.42; 12.15.17.32.40.42; 12.15.30.32.33.46; 12.15.30.33.40.46; 12.17.30.33.42.46; 12.17.32.33.40.46; 12.17.32.33.42.46; 15.17.30.32.33.40; 15.30.32.40.42.46; 17.30.33.40.42.46 ACDE  3 numbers each letter, 12 total numbers, 10 sets, 60 spots, All numbers 5 times. Numbers in wheel: 6.8.9.23.25.29.31.33.39.43.44.46 Combinations to play are: 6.8.9.25.39.43; 9.25.29.31.44.46; 8.25.31.33.44.46; 8.23.29.31.39.44; 8.9.23.29.33.44; 6.9.23.31.33.46; 6.9.23.39.43.46; 6.23.25.33.39.43; 8.29.31.43.44.46; 6.25.29.33.39.43 ABCE  3 numbers for each letter, 12 total numbers, 10 sets, 60 spots to fill, All numbers 5 times. Numbers in wheel: 3.5.6.11.12.16.21.22.25.40.42.46 Combinations to play are: 3.5.6.12.25.40; 5.11.21.22.25.42; 6.16.25.40.42.46; 3.12.16.21.40.46; 3.5.11.16.22.46; 6.16.21.22.42.46; 5.6.12.21.22.42; 3.11.12.22.25.40; 5.11.12.16.40.42; 3.6.11.21.25.46 BCEF  3 numbers for each letter, 12 total numbers, 10 sets, 60 spots, All numbers 5 times. Numbers in wheel: 11.12.17.21.23.25.40.44.46.51.53.54 Combinations to play: 11.23.44.46.51.53; 17.21.23.25.46.53; 12.25.40.44.51.54; 11.12.23.46.51.54; 11.12.17.21.40.53; 12.17.25.40.44.53; 17.21.25.44.51.53; 11.21.40.46.51.54; 11.23.25.40.44.54; 11.17.21.23.46.54 These are my 'best guesses' based on the Gap Strategy data streams. Other players using the workouts could very well reach other conclusions. Gap Strategy is versatile. That is, if I only wanted to play 5 sets for a pick 6 game, I'd select a scheme that would provide a minimum of 3 numbers for each letter, 9 numbers overall, 30 spots to fill and a wheel setting to generate 5 sets. I'd then have to adjust the recommended combinations to ensure that all combinations have at least one of the nine numbers in the wheel. I could, of course, adopt a scheme where I would generate 5 or more numbers for each letter in the structure to be played. However, there are limits. Playing 5 numbers for 4 letters would require more than 10 combinations. I can't say exactly how many because I've never contemplated working with such a scheme. Thanks for your interest.
Bobby623 
bobby You said that: There are 6 1point structures, 15 2point structures, 20 3point structures, 15 4point structures and 6 5point structures. A current structure inventory shows that 4point structures come up more often than any other structure, followed by 5point and 3point. Positional analysis inventory for Postions 1 and 2 shows that 'AB' has come up 131 times, 'BC' 56 times, 'AC' 37 times, 'BD' 11 times. Simular inventories for Positions 3 and 4 shows 'CD' 42 times, 'CD' 36 times, 'CE' 20 times, 'E.' 20 times, 'EF' 19 times, 'DF' 16 times, and 'D.' 12 times. (D. is correct) The inventory for Positions 4 and 5, yes, 4 and 5, shows 'EF' 61 times, 'DE' 59 times, 'DF' 31 times, 'E.' 21 times. These are mainly from 5point structures. (E. is correct) Can you please do the same for the TxCash5? Thanks! Fernando.
  
San Angelo, Texas United States Member #1097 January 31, 2003 1394 Posts Offline  Posted: September 5, 2010, 3:53 pm  IP Logged  
Lantern I quit playing Tx Cash 5 when the jackpot dropped below $25,000. A lot of work with a good possibility that there would be more than one winner. You can obtain the data you want yourself by doing the following. 1. Using graph paper, log the winning combinations in numerical order. Go back 30 more drawings. 2. Convert numerical combinations to what I call an 'alpha sequence' by substituting a letter for the numerals in a separate column. Divide into P1p2 P3 P4P5. Key: 19 = A, 1019 =B, 2029 = C, 3037 = D. 3. Convert the alpha sequences to 'structures' by eliminating duplicates. For example, ABBCD becomes ABCD, which is a 4point structure. To this point, you should have" Date 01 10 20 30 37 AB C DD ABCD 4 date 14 23 33 34 35 BC D DD BCD. 3 date 07 08 09 11 16 AA A BB AB.. 2 etc You can number the structures individually on same sheet, or use a separate sheet maintain an inventory. I use a separate sheet. There are 4 1point, 6 2point, 4 3 point and 1 4point structures in every 5/3X game. Update the totals after each drawing. On a 3rd sheet, log the P1P2 pairs. Number them 1up. I use Gap Strategy, therefore, I enter the gap number in a 4th column E. Heading # P1P2 # 1 AB  2 AB 1 Strike through each pair as they are tabulated. Don't obliterate, just a mark to show it shouldnt be counted a second time. Do the same for P2P3, and P3P4. Keep in mind that some pairs will be '..' When you are done, you will have an exact total for each pair, and make play choices accordingly. Construct a structure follower chart. Prepare a 4x4 square with rows and columns marked 1 thru 4. Count the number of times one structure follows another and put the total in appropriate box. When you are done you will know exactly how many times the structures follow one another. If the last structure was a 3, you can refer to chart and decide if the next will be a 3, a 4, a 2 or a 1, depending on the totals and current trends. You can keep the same type of stats for the alpha sequences. Some sequences come up way more often than others. As far as the numbers are concerned, you will have to adopt appropriate inventory streams and followers. Good luck!   
Tx United States Member #4570 May 4, 2004 5180 Posts Offline  Posted: September 5, 2010, 4:27 pm  IP Logged  
Lantern I quit playing Tx Cash 5 when the jackpot dropped below $25,000. A lot of work with a good possibility that there would be more than one winner. You can obtain the data you want yourself by doing the following. 1. Using graph paper, log the winning combinations in numerical order. Go back 30 more drawings. 2. Convert numerical combinations to what I call an 'alpha sequence' by substituting a letter for the numerals in a separate column. Divide into P1p2 P3 P4P5. Key: 19 = A, 1019 =B, 2029 = C, 3037 = D. 3. Convert the alpha sequences to 'structures' by eliminating duplicates. For example, ABBCD becomes ABCD, which is a 4point structure. To this point, you should have" Date 01 10 20 30 37 AB C DD ABCD 4 date 14 23 33 34 35 BC D DD BCD. 3 date 07 08 09 11 16 AA A BB AB.. 2 etc You can number the structures individually on same sheet, or use a separate sheet maintain an inventory. I use a separate sheet. There are 4 1point, 6 2point, 4 3 point and 1 4point structures in every 5/3X game. Update the totals after each drawing. On a 3rd sheet, log the P1P2 pairs. Number them 1up. I use Gap Strategy, therefore, I enter the gap number in a 4th column E. Heading # P1P2 # 1 AB  2 AB 1 Strike through each pair as they are tabulated. Don't obliterate, just a mark to show it shouldnt be counted a second time. Do the same for P2P3, and P3P4. Keep in mind that some pairs will be '..' When you are done, you will have an exact total for each pair, and make play choices accordingly. Construct a structure follower chart. Prepare a 4x4 square with rows and columns marked 1 thru 4. Count the number of times one structure follows another and put the total in appropriate box. When you are done you will know exactly how many times the structures follow one another. If the last structure was a 3, you can refer to chart and decide if the next will be a 3, a 4, a 2 or a 1, depending on the totals and current trends. You can keep the same type of stats for the alpha sequences. Some sequences come up way more often than others. As far as the numbers are concerned, you will have to adopt appropriate inventory streams and followers. Good luck! bobby O.K. Thanks you much! Fernando.   
